Mendelian Patterns of Inheritance Chapter 11
QOD:
c 1. Heredity i 2. Genotype e 3. Phenotype d 4. Dominant b 5. Recessive h 6. Alleles f 7. Homozygous
(Pure) a 8. Heterozygous (Hybrid) g 9. Genetics
Genetics Vocabulary Practice
a. The alleles of a particular gene are different b. Not expressed when the dominant form of the trait is present c. Passing of trait from parents to offspring d. The expressed form of a trait (cover up other forms) e. Physical appearance of a trait f. When the two alleles of a particular gene are the same g. Branch of a biology that studies heredity h. Different versions of a gene i. Set of alleles that an individual has
Ch 11
Sexual Reproduction and Genetics
Genetics: the study of heredity Heredity the passing of traits to the next generation. :
(from parent to child)
§ Trait: a physical feature (blue eyes)
Dominant trait: a trait that always shows, can cover the other allele. - represented by a Capital letter EX: Brown eye: B Recessive trait: a trait that only shows of both alleles are present. - represented by lower case letter EX: blue eye: b
Codominant: both alleles are expressed (shown) . EX: Bb: Brown (B) and Blue (b) eyes are both expressed
Sexual Reproduction and Genetics
§ Homozygous: Homozygous: two of the same alleles for a particular trait § ex: BB or bb also called pure § Heterozygous Heterozygous: two different alleles for a particular trait § Ex: Bb also called hybrid Gregor Mendel: the father of genetics, studies the traits of pea plants
11.1 Gregor Mendel “Father of Genetics”
• Developed the fundamental laws of heredity • He studied science and mathematics -chose to study genetics in garden peas (Pisum sativum)as as they are easily grown and their pollination is easily controlled. He controlled pollination by manually moving pollen between plants Developed True-breeding plants by selfpollination
Funfact: Mendel originally wanted to breed mice, but wasn't allowed to because it was considered scandalous
http://science.howstuffworks.com/life/29784-100-greatestdiscoveries-genetics-and-gregor-mendal-video.htm
Mendel examined varieties of peas for heritable characters and traits for his study. (stem length, pod shape, seed shape, seed color..etc) Developed hybrid plants by crossbreeding two plants of differing characteristics Tall v Short
Sexual Reproduction and Genetics
Mendel
P generation parents
F1 offspring 1 kids
F2 offspring 2 grandkids
11.2 Mendel's Law of Segregation (MONOHYBRID CROSS)
• A monohybrid cross
involves one (mono) character and different (hybrid) traits. The F1 seeds were all purple; the white flower trait failed to appear at all.
•
Because the purple flower trait completely masks the white flower trait when true-breeding plants are crossed, the purple flower trait is called dominant, and the white flower trait is called recessive.
Creating the F2 generation *Cross the F1 generation together to create F2 *Ratio is always 3:1 Mendel proposed that the units responsible for inheritance were discrete particles - particulate theory of inheritance
In 1865, Mendel published his findings in a paper called Experiments on Plant Hybridization, which was mostly ignored at the time due to a number of reasons. First, Mendel was not well known in scientific community. Second, his theory ran against the popular model of blended inheritance.
As Viewed by Modern Genetics
• During production of gametes, only one of the pair
members for a given parent passes to the gamete. (LAW OF SEGREGATION) Mendel's units of inheritance are now called genes. Different forms of a gene are called alleles. Each allele is given a symbol:
• • •
Parental Cross
PP x pp purple x white
Mendel’s Three Laws 1. Dominance & Recessiveness 2. Segregation: the two alleles for a trait separate (or
segregate) during the formation of gametes 3. Independent Assortment: during gamete formation,
alleles pair independently, meaning a particular allele for one character can be paired with either allele of another character
• Two copies of same allele = homozygous. Homo means "the same"
• Therefore both PP and pp are considered homozygous, just one is purple and the other is white.
• Some purple-flowered plants could be Pp.
Individuals that are purple, but had a white parent, are heterozygous: Pp. Hetero means "different". The F1 cross Pp x Pp purple x purple
Review Terms F1 vs F2 True Breeding vs Hybrid Self Pollination vs Cross Pollination Homozygous vs Heterozygous Particulate Theory vs Blending Theory Segregation
The physical appearance of an organism is its phenotype. Purple-flowered would be a phenotype. The actual composition of the organism's alleles for a gene is its genotype: Pp is a genotype.
GENOTYPE Pp
PHENOTYPE purple flowers
rr
wrinkled seeds
TT
tall
tt
short
Organisms have many different genes some have thousands, and complex organisms have 10 times that number.
BY CONVENTION: The dominant trait is given a capitol letter, the lowercase of that same letter is the recessive trait. DO NOT MIX LETTERS. Pick one and stick to it. Also, some letters are better than others. Capital S looks a lot like a lowercase (s). Pick a different letter... Okay Short hair = SS Short hair = Ss Long hair = ss Steps to solving genetics problems 1. Key 2. Parents cross 3. Punnett Square 4. Genotype and ratio 5. Phenotype and ratio
Better (use H for hair) HH Hh hh
Punnett Square: to predict outcome of offspring Steps to solving genetics problems Cross heterozygous green pea 1. Key (Gg) with heterozygous green pea 2. Parents cross 3. Punnett Square plant (Gg). Yellow is recessive. 4. Genotype and ratio 5. Phenotype and ratio
P = Gg x Gg G
g
G
GG Gg
g
Gg gg F1
Key: GG: Gg: green
gg yellow
Genotype: ¼ GG; 2/4 Gg; ¼ gg Genotype ratio: 1:2:1 Phenotype: ¾ green; ¼ yellow Phenotype ratio: 3:1
In dragons... Wings are a dominant trait, but some dragons are born wingless.
1. If a wingless dragon is crossed with one that is heterozygous, how many of its offspring will also be wingless? 2. What are the chances that two heterozygous dragons have a whelp that is wingless?
If a wingless dragon is crossed with one that is heterozygous, how many of its offspring will also be wingless? P = ff x Ff f
f
F
Ff
Ff
f
ff
ff F1
Key: FF: Ff: wings
ff wingless
Genotype: 2/4= ½ Ff; ½ ff Genotype ratio: 1:1 Phenotype: ½ wing; ½ wingless Phenotype ratio: 1:1
What is a test cross? Help, help! I don't know what my genotype is!! Am I Ff or FF?
Key: F= winged f=wingless
I can help you! Let's have offspring!
Practice with Punnett Squares 1. A round seeded plant (RR) is crossed with a wrinkle seeded plant (rr). What are the phenotypes of the offspring?
2. Two heterozygous purple flowered pea plants are crossed. What are the phenotypes of their offspring and in what proportion?
3. A plant with green seeds (yy) is crossed with a heterozygous plant. What percentage of their offspring have yellow seeds?
Why does the punnett square work? It all goes back to meiosis.. each side represents a sperm or egg. The boxes filled out simply give you the statistical chance that a certain sperm will fertilize a certain egg.
Probability: The chance that an event will occur - It is a prediction, and it could be wrong.
Mendel’s Laws of Probability - Can use probability and math to solve genetic problems.
Ex: If two parents are heterozygous for nostril flaring. P= Ee X Ee Chance of E =½ Chance of e = ½ 1. 2. 3. 4.
Chance of EE = ½ x ½ Chance of Ee = ½ x ½ Chance of eE = ½ x ½ Chance of ee = ½ x ½
=¼ =¼ =¼ =¼
Ee= ¼ + ¼ = ½
If a wingless dragon is crossed with one that is heterozygous, how many of its offspring will also be wingless?
P = ff x Ff ½½
Key: FF: Ff: wings
½½
1
fF= 1 X ½ = ½ ff=1 x ½ = 1/2
ff wingless
Incomplete Dominance
In Make believe flowers……. Incomplete Dominance Key: RR = red Rr = purple (BLENDING) rr = blue
CoDominance Key: RR = red Rr = red and blue (both are expressed) rr = blue
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Resources
Copyright © by Holt, Rinehart and Winston. All rights reserved.
Incomplete Dominance Traits appear to "blend" in offspring RR x WW RW (pink) Show: Pink x Red Pink x Pink White x White
Figure 11.14
This illustrates another style of "letters" to denote genotypes R1 and R2
Coloration in Rodents Black x White = Gray BB x WW = BW
Sickle Cell Trait in Humans Genotypes & Phenotypes
Pleiotropic Effect: a single mutant gene affects two or more seemingly unrelated traits - Sickle cell shape, and resistant to malaria parasite
Prevalence of Malaria In tropical Africa, where malaria is common:
homozygous dominant individuals die of malaria homozygous recessive individuals die of sickle cell anemia heterozygote carriers are relatively free of both reproductive advantage
Pleiotropic Effect: a single mutant gene affects two or more seemingly unrelated traits
Prevalence of Sickle Cell Anemia
Wavy hair is an example of incomplete dominance
Codominance
ROAN COW What happens when you cross a white and a red cow?
Roan is codominant - both alleles R and W are expressed
What happens when two Roan Cows are Crossed? R R
RR
r
Rr
r Rr rr
In Make believe flowers……. Incomplete Dominance Key: RR = red Rr = purple (BLENDING) rr = blue
CoDominance Key: RR = red Rr = red and blue (both are expressed) rr = blue
Ex: A brown bird crosses with a white one and all the offspring produced are Key: BB= Brown tan. If these offspring were crossed Bb = Tan and produced 16 birds, how many would be tan? bb = White
P = Bb x Bb B
b
Genotype: ¼ BB; ½ Bb; ¼ bb
B
BB Bb
Genotype ratio: 1:2:1
b
Bb
Phenotype: ¼ Brown ; ½ Tan ; ¼ White
bb F2
Phenotype ratio: 1:2:1
If these offspring produced 16 birds how many would be expected to be tan? 8
Keep in mind: in most real organisms, it is not that simple. More than one gene will code for a trait.
QOD: Mendel’s Properties 1. What does INDEPENDENT ASSORTMENT mean?
In your own words, describe what it means with regard to Mendelian genetics.
2. Mendel would have never developed this law if he'd chosen traits located on the same chromosome. Why do you think that would have altered his results? 3. What is the difference in complete dominance, codominance, and incomplete dominance and which did Mendel study? Why?
Dihybrid Cross
Mendel's Law of Independent Assortment – Illustrated by the DIHYBRID cross law describes the outcome of dihybrid (two character) crosses, or hybrid crosses involving additional characters. A dihybrid is an individual that is a double heterozygote (e.g., with the genotype RrYy - round seed, yellow seed). What are the gametes that can be produced by this individual?
Dihybrid Cross: RrYy x RrYy cross two traits at same time: remember independent assortment
Key: In pigs, T = curly tail t = straight tail Complete dominance
1a.
P = TtBb
B =brown coat b = white coat Complete dominance
x
G TB, Tb , tB, tb
X
TtBb TB, Tb, tB, tb
Phenotype
Genotype: TB,
Tb ,
tB,
1/16 TTBB
tb
9/16 curly tail & brown coat
2/16 TTBb
TB TTBB
TTBb
TtBB
TtBb
Tb TTBb
TTbb
TtBb
Ttbb
tB
TtBB
TtBb
ttBB
ttBb
tb
TtBb
2/16 TtBB 4/16 TtBb 1/16 TTbb
3/16 straight tail & brown coat
2/16 Ttbb
1/16 straight tail & white coat
1/16 ttBB
Ttbb
ttBb
ttbb
2/16 ttBb 1/16 ttbb
Pheno ratio: 9 : 3 : 3 : 1
3/16 curly tail & white coat
1a.
Continued….
What percentage of the offspring will be purebred dominant for both traits? 1/16 or 6% What percentage of the offspring will be hybrid for both traits? 4/16 or 25% Genotype:
Phenotype
1/16 TTBB
Key:
In pigs, T = curly tail B =brown coat
2/16 TTBb
t = straight tail b = white coat
1/16 TTbb
9/16 curly & brown
2/16 TtBB 4/16 TtBb 3/16 curly & white
2/16 Ttbb 1/16 ttBB
3/16 straight & brown
2/16 ttBb 1/16 ttbb
1/16 straight & white
All of these type of crosses will follow the same ratio
AaBb x AaBb both heterozygous for both traits 9 - (two dominant traits) 3 - (one dominant, one recessive) 3 - (one recessive, one dominant) 1 - (two recessive traits)
1b.
Key:
In pigs, T = curly tail t = straight tail Complete dominance
P = TTbb G
Tb Tb
x X
B =brown coat b = white coat Complete dominance
ttbb tb
Genotype: 100% Ttbb
tb
Ttbb
Pheno ratio: 0 : 1 : 0 : 0
Phenotype 100% curly tail and white coat
3.
Key:
In Drosophila fruit flies W = long wings w = vestigial wings Complete dominance
P = Wwhh G
Wh, wh Wh
WH
wh
WWHh WwHh
Wh
WWhh
Wwhh
H = hairless body h = hairy body Complete dominance
x
WWHh
X
WH, Wh
Genotype:
Phenotype
1/4 WWHh
50% long wings and hairless body
1/4WwHh
50% long wings and hairy body
1/4 WWhh 1/4 Wwhh
Pheno ratio: 1 : 1 : 0 : 0
What percentage of the offspring will have long wings and hairless bodies?
50%
2.
Key:
In pea plants L = long stems l = short stems Complete dominance
P = LLgg G
Lg Lg
lG
LlGg
x X
G =green pods g = yellow pods Complete dominance
llGG lG
Genotype:
Phenotype:
100% LlGg
100% long stems and green pods
Pheno ratio: 1 : 0 : 0 : 0
It may be faster to solve problems mathematically. This one is NOT 9:3:3:1
HhBb x hhBb How many off the offspring will be short haired and red eyed?
Try another mathematical model.. Winged, Fire breathing dragon DdFf x Wingless, Fire breathing dragon ddFf
Consider the cross between a plant with round seeds, purple flowers to one with wrinkled seeds and white flowers ...
RrPp x rrpp
Multiple Alleles
Multiple Alleles: more than two alleles in the population ex: Blood Types
Blood Type
There are 3 alleles that code for what type of blood you have. A, B, and O. A and B are Co-Dominant and O is recessive. Phenotype Genotype
Type A
IAIA, IAiO
Blood Donor Donate to Type A/AB
% of population 42%
Type B
IBIB, IBiO
Donate to Type B/AB
Type AB
IA IB
Universal recipient/Donate to AB
4%
Type O
iOiO
Universal Donor/ only receive O
44%
10%
Practice #1 Cross: Type A (AA) father with a type 0 mother. What are the possible blood types of the offspring?
P = AA x OO A
A
O AO AO O AO
AO
Genotype: 4/4 AO Phenotype: 4/4 Type A
Practice #3 Suppose two newborn babies were accidentally mixed up in a hospital, something that rarely happens. In an effort to determine the parents of each baby, the blood types of the parents and the babies were determined. Baby 1-type B Mrs. Davisson-type B Mrs. Morgan - type O Baby 2-type O Mr. Davisson- type B Mr. Morgan - type AB
A Name
Genotype
Mrs. D
BO
Mr. D Mrs. M Mr. M Baby 1 Baby 2
BB, BO BO BB, BO OO OO AB AB BO BB, BO OO OO
B
O AO BO O AO
BO
1. Which baby belongs to Mr. & Mrs. Davisson? Baby 2 2. Which baby belongs to Mr. and Mrs. Morgan? Baby 1
Chapter 9
blood type is located on chromosome #9 • Type A, B, AB or O RH factor is a separate gene that codes for another protein. This is the positive or negative part of the blood type, on chromosome #1.
Many Genes Have Multiple Alleles A population might have more than two alleles for a given gene. In Labrador retriever, coat color is determined by one gene with four different alleles. Five different colors result from the combinations of these alleles. (More on labradors later)
• •
Eye color is also controlled by multiple alleles
The simulation is a bit simplified, but the idea is that MULTIPLE ALLELES control a single trait (eye color)
It is likely that more than 2 alleles control eye color, this is simplified just made it simple to understand.
Polygenic Traits
• Individual heritable characters found to be controlled by groups of several genes, called polygenes. • Each allele intensifies or diminishes the phenotype. • Variation is continuous or quantitative (adding up) - also called quantitative inheritance • Seed Color in wheat - aabbcc, Aabbcc, AaBbcc, AaBbCc, AABbCc, AABBCC (light, intermediate colors, dark) • In humans - hair color, height, skin color
Pg 197
Polygenic Inheritance AABBCC x aabbcc (P) AaBbCc x AaBbCc (F1) Seven Possible Phenotypes in the F2 The more “dominant” alleles for dark pigmentation (caused by melanin), the darker the skin
Figure 11.16
Example polygenetic trait question:
In a cross AaBbCc AaBbCc, what is the probability of producing the genotype AABBCC? a. ¼ b.1/8 c.1/16 d.1/32 e.1/64 ANSWER: E
Environment and Phenotype Temperature, water, food sources can have an affect on how a gene is expressed = “multifactoral” Rabbits have a gene that codes for darker pigments - this gene is more active at low temperatures. Parts of the body that are colder will develop the darker pigmentation ears and feet
• SIAMESE CATS
Multiple Alleles control the combs of chickens.
Assignment: Multiple Alleles in Chickens
LEGHORN CHICKEN – SINGLE COMB
BUTTERCUP CHICKEN - BUTTERCUP COMB
Buckeye Chicken – Pea Comb
Wyandotte Chicken - Rose Comb
Lethal Genes (Not in book, added)
• Some genes are lethal when both
alleles are present. Lethality can occur before or after birth Huntington's disease in humans is caused by a lethal allele, death occurs later in life Other examples: Mouse coat color (yellow), Creeper legs in chickens, Manx Cats (no tails)
• •
An example is the "creeper" allele in chickens, which causes the legs to be short and stunted.
Manx cat
X- linked traits
Inheritance and Human Heredity X-linkedComplex traits: traits on the X chromosome • Colorblindness • Hemophilia • Muscular Dystrophy More common in males
Colorblindness sex-linked recessive condition in which people can’t see certain colors don’t make some of the pigments in the eye that are necessary for color vision. The most common form is red-green colorblindness
Normal color vision : 29 Red green color blind : a bunch of spots!
Normal color vision : 56 Red green color blind : 56
Normal color vision : 8 Red green color blind : spots
Hemophilia: condition that impairs the blood’s ability to clot. Hemophilia is a recessive sex-linked trait. Also known as bleeders disease
Hemophilia: Royal Disease
Muscular Dystrophy (MD): disease that results in
progressive wasting away of skeletal muscle. Caused by a defective protein known as dystrophin
Ex:
Colorblindness
Key: XX = female normal vision XY = male normal XXe = female carrier (normal vision vision) XeY = male colorblind XeXe = female colorblind
Cross carrier female with normal male X X
XX
Xe XXe
Y XY XeY
P = XY x X Xe Genotype Phenotype 1/4XX: female normal vision 1/4 XXe : female carrier 1/4 XY: male normal vision ¼ XeY: male color blind
What % of their boys will be expected to be colorblind?
50%
Hemophilia
Key: XX = normal female XY = male normal XXh = female carrier XhY = male hemphiliac XhXh = female hemophiliac MD
Key: XX = normal female XXm = female carrier XmXm = female with MD
XY = male normal XmY = male with MD
Carrier
1. XY male normal 2, XXe female carrier 3. XY male normal 4. XXe female carrier 5. XXe female carrier 6, XY male normal
7. XeY male colorblind 8. XXe female carrier 9. XX or XXe 10. XeY male colorblind 11. XY male normal 12. XeXe female colorblind
Complex Inheritance and Human Heredity
Pedigrees:
A diagram that traces the inheritance of a particular trait through several generations
Human Disorders
Pg 192
Autosomal Recessive vs Autosomal Dominance
Aa
Aa
aa
Aa
Aa
aa
Figure 11.10
Figure 11.11
Hereditary Genetic Disorders Name of Disorder
Tay Sacks Cystic Fibrosis PKU Sickle Cell Disease Neurofibromatosis Huntington's Disease Achondroplasia
Type (autosomal, sex linked, dominant, recessive)
Description/ Symptoms
Type of people group/ treatment / other
Tay Sachs Autosomal recessive -progressive deterioration of nerve cells and of mental and physical abilities Young children begin showing signs of slowed development Severe impairment and death strikes 1 in 3600 births 100 times greater than incidence among non-Jews
non-functional enzyme fails to breakdown lipids in brain cells fats collect in cells destroying their function symptoms begin few months after birth seizures, blindness & degeneration of muscle & mental performance child usually dies before 5yo
Cystic Fibrosis autosomal recessive -More common in Caucasians -Mucus in respiratory tract, difficulty breathing extreme salty sweat -Mucus may cause secondary infections http://www.redorbit.com/news/video/health_2/1113011363/miracle-drug-for-cystic-fibrosis-11222013/
Effect on Lungs normal lungs
airway
Cl–
Chloride channel transports salt through protein channel out of cell Osmosis: H2O follows Cl– Cl– channel
H 2O cells lining lungs
cystic fibrosis
Cl–
bacteria & mucus build up
H 2O thickened mucus hard to secrete
mucus secreting glands
Phenylketonuria (PKU)
• Lack enzyme for normal metabolism • Phenylalanine builds up and causes brain damage • Newborns are routinely tested • Changes in diet lead to normal life
Phenylalanine Hydroxylase is the enzyme needed, absent in those with PKU
http://www.youtube.com/watch? v=XKSoMi4U-1k http://www.youtube.com/watch? v=w3L2SPj7alQ
autosomal recessive
Sickle Cell Disease • More common in Africans (African-Americans) • Causes blood to be sickle shaped • Affects oxygen flow to organs, causing weakness, pain, anemia, etc Heterozygotes are resistant to malaria
•
AA = normal Aa = sickle cell trait aa = sickle cell disease
Neurofibromatosis -Autosomal dominate -carry high risk of tumor formation -Tumors form under skin and can cause skeletal deformities, blindness "The Elephant Man" Several years ago, research teams located the exact position of the NF1 gene on chromosome 17. The product of the NF1 gene is a large and complex protein called neurofibromin, which is primarily active in nervous cells as a regulator of cell division. Intensive efforts have let to the identification of the NF2 gene on chromosome 22. The NF2 gene product is a tumor-suppressor protein called merlin.
http://www.bcnf.bc.ca/learn/about-the-charity/
Huntington's Disease HH = Huntington's Hh = Huntingtons hh = normal Symptoms appear later in life, often starting with poor muscle control Autosomal Dominant
neurodegenerative genetic disorder that affects muscle coordination and leads to cognitive decline
There are different types of dwarfism. Achondroplasia is caused by a dominant allele.
Meet Kenadie Two dwarfs can have a normal child. Dd x Dd
http://www.youtube.com/watch? feature=player_embedded&v=_QBy8DFaLR4
Primordial Dwarfism
Genes and crossing over: the higher the crossing over frequency, the farther apart the genes The following crossover frequencies were noted via experimentation for a set of five genes on a single chromosome:
A and B → 35% B and C → 15% A and C → 20% A and D → 10% D and B → 25% A and E → 5% B and E → 40% Pick the answer that most likely represents the relative positions of the five genes.
29. In a cross AaBbCc AaBbCc, what is the probability of producing the genotype AABBCC? a. ¼ b.1/8 c.1/16 d.1/32 e.1/64 ANSWER: E
Goals 1. Finish Pedigree worksheet staple into QOD 2. Grid in questions in Genetics FRQ packet can check answers with yellow answer key 3. Finish lab(s)