Important questions in chemistry. How far? How fast?

Important questions in chemistry How far? How fast? Learning objectives ► ► ► ► ► ► ► ► Describe fundamental principles behind reaction kinetics ...
Author: Walter McDowell
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Important questions in chemistry How far? How fast?

Learning objectives ►

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Describe fundamental principles behind reaction kinetics Describe factors that affect reaction rates Define rate of reaction Describe concept of equilibrium in terms of forward and reverse reactions Write equilibrium constant expressions Predict concentrations of reactants and products using equilibrium constant expressions Describe physical basis of Le Chatelier’s principle Predict responses of systems to changes in conditions using Le Chatelier’s principle

Equilibrium ► Not

all reactions go to completion – equilibrium ► State of equilibrium is when system has reached lowest energy state  Not a static event but a dynamic one  Rate of formation of products = rate of formation of reactants ► Le

Chatelier’s principle predicts how systems at

equilibrium respond to changes in conditions

Underlying principles behind reactions: echoes of kinetic theory ► Molecules

are in motion ► Molecules undergo collisions ► Only some collisions result in products ► Temperature increases motion of molecules

Reaction pathway in energy ► In

order for a reaction to proceed reacting molecules must leap over energy barrier; molecules with insufficient energy don’t make it

Bond breaking

Bond making Returns 100 kJ

Requires 100 kJ

Kinetics deals with things in the box Reactants at equilibrium

Products at equilibrium Province of kinetics

Exo-thermic and endo-thermic ► H2

+ O2 gives out energy – exothermic

► N2

+ O2 absorbs energy - endothermic

The pathway of a reaction

Chance meetings ► On

the molecular level reactions occur via collisions

Big But: Not all collisions result in reaction ►Two

considerations

► Energy

of the molecules

 Overcoming the barrier ► Orientation

of the molecules

 Getting them lined up  Very significant for larger molecules

Insufficient energy

Wrong orientation

Factors that affect reaction rate ► Concentration

► Temperature ► Presence ► Physical

of REACTANTS

(kinetic energy of molecules)

of a catalyst

state of reactants (surface area)

Higher concentration = more collisions

Ways over (or around) the barrier ► Temperature

increases reaction rate by increasing fraction of molecules with enough energy to jump barrier

►A

catalyst is a way to lower the barrier. A catalyst increases the reaction rate, but is not consumed itself during the reaction

Catalysts modify the pathway ► Addition

of chlorine catalyst increases rate of decomposition of O3 to O2 – reason for ozone hole (CFCs) ► Pathway is modified: two barriers smaller than one without catalyst

Clean air and catalysis ► The

metal surface catalyzes oxidation of unwanted exhaust to CO2, H2O and N2

Without catalysts, there would be no life at all, from microbes to humans ► ENZYMES

are biological catalysts ► Most enzymes are proteins – large molecules ► Have correct shape to bring reactant molecules together Enzyme in correct orientation

Equilibrium: a rate of reaction perspective ► Forward

reaction A+B→C+D

► Backward

reaction A+B←C+D

► Equilibrium

results: Rate of forward reaction = rate of backward reaction A+B↔C+D

Equilibrium constant expression aA + bB ↔ cC + dD Coefficient

c

K eq Reactants

d

[C ] [ D ] a b [ A] [ B ]

Always Products over Reactants

Products

Not all products and reactants are included ► Ignore

all pure solids and liquids – they do not change concentrations during reactions ► Consider MnO2(s) + 4HCl(aq) = MnCl2(aq) + Cl2(g) + 2H2O(l)

Not all products and reactants are included ► Ignore

all pure solids and liquids – they do not change concentrations during reactions MnO2(s) + 4HCl(aq) = MnCl2(aq) + Cl2(g) + 2H2O(l)

K eq

[ MnCl2 ][Cl2 ] 4 [ HCl ]

Significance of large Keq ► The

finishing point is the same coming from either direction

Significance of small Keq

Calculations – putting numbers in ► Consider

the reaction 2HI(g) ↔ H2(g) + I2(g)

What is the value of Keq if [HI] = 0.54 M, [H2] = [I2] = 1.72 M?

K eq K eq

[ H 2 ][ I 2 ] 2 [ HI ]

[1.72 ][1.72 ] 10 .2 2 [0.54 ]

Solving problems with K ► Equilibrium

constant for reaction: N2O4(g) = 2NO2(g) is 4.6 x 10-3 ► If [NO2] = 0.050 M, what is [N2O4]?

Solving problems with K ► Equilibrium

constant for reaction: 2NOBr(g) = 2NO(g) + Br2(g) is 2.0



If [NO] = 2.0 M and [Br2] = 1.0 M, what is [NOBr]?

Upsetting the applecart ► What

happens to the equilibrium when changes are made? ► Le Chatelier’s Principle If a stress is placed on a system at equilibrium, the system will respond by changing its position to minimize the stress

Changes in composition ► Consider

the reaction at equilibrium 2HI(g) ↔ H2(g) + I2(g)

► What

happens if additional H2(g) is added?

 The system responds by trying to reduce the amount of added material; H2 is converted into HI – the equilibrium shifts away from the point of change 2HI(g) ↔ H2(g) + I2(g)

In general:  Add products: products → reactants aA + bB ↔ cC + dD  Add reactants: reactants → products aA + bB ↔ cC + dD ► Other

effects;

 Temperature  Pressure

Specific example

Temperature and equilibrium N2(g) + 3H2(g) = 2NH3(g) + heat  Exothermic Reaction:  Supply heat: equilibrium adjusts to disperse heat: shifts towards reactants ►Less

NH3 is made

 Endothermic reactions show opposite response  Heat shifts towards products ►Why

we heat endothermic reactions

Pressure and equilibrium 2HI(g) ↔ H2(g) + I2(g)  2 moles reactants → 2 moles products  No overall pressure change N2(g) + 3H2(g) = 2NH3(g)

 4 moles reactants → 2 moles products  Increase pressure drives reactants → products

Summary of Le Chatelier