Mid-Term 2013 Review
Name___________________________________
Find the slope of the line tangent tangent to the graph a the given point. 1) y= x2 + 10x, x = 8 A) m = 144
B) m = 18
C) m = 16
D) m = 26
Answer: D 2) y =
6 ,x=7 3+x
A) m =
3 5
B) m =
3 50
3 5
C) m = -
D) m = -
3 50
Answer: D Find an equation for the tangent to the curve at the given point. 3) h(x) = t3 - 36t - 5, (6, -5) A) y = 72t - 437
B) y = 72t - 5
C) y = -5
D) y = 67t - 437
Answer: A 4) f(x) = 10 x - x + 3, (100, 3) A) y = 3
B) y =
1 x - 53 2
C) y = -
1 x + 53 2
Answer: C Calculate the derivative of the function. Then find the value of the derivative as specified. 5) g(x) = x3 + 5x; g (1) A) g (x) = 3x2 + 5x; g (1) = 8
B) g (x) = 3x2 + 5; g (1) = 8
C) g (x) = 3x2; g (1) = 3
D) g (x) = x2 + 5; g (1) = 6
Answer: B
1
D) y = -
1 x+3 2
6)
dr if r = dt t =3
4 28 - t
A)
dr 4 dr 4 ; = = dt (28 - t)3/2 dt t =3 125
B)
dr 2 dr 2 ; = = dt (28 - t)3/2 dt t =3 125
C)
dr 2 dr 2 ; ===3 dt 3/2 dt t 125 (28 - t)
D)
dr 4 dr 4 ; ===3 dt 3/2 dt t 125 (28 - t)
Answer: B Find y . 7) y = (5x - 2)(6x + 1) A) 60x - 3.5
B) 30x - 7
C) 60x - 7
Answer: C 8) y = (3x - 5)(4x3 - x2 + 1) A) 12x3 + 23x2 - 69x + 3
B) 36x3 + 69x2 - 23x + 3
C) 48x3 - 23x2 + 69x + 3
D) 48x3 - 69x2 + 10x + 3
Answer: D
2
D) 60x - 17
Solve the problem. 9) The graph of y = f(x) in the accompanying figure is made of line segments joined end to end. Graph the derivative of f.
Answer:
3
10) Use the following information to graph the function f over the closed interval [-5, 6]. i) The graph of f is made of closed line segments joined end to end. ii) The graph starts at the point (-5, 1). iii) The derivative of f is the step function in the figure shown here.
Answer:
Provide an appropriate response. 11) Find all points (x, y) on the graph of y =
A) (0, 0), (14, 2)
x with tangent lines perpendicular to the line y = 7x - 2. (x - 7)
B) (0, 0), (7, 2)
C) (0, 0)
Answer: A
4
D) (14, 2)
Find the second derivative. 23x3 -8 12) y = 6
A) 23x - 8
B) 23x
C)
23 2 x 2
Answer: B The graph of a function is given. Choose the answer that represents the graph of its derivative. 13)
A)
B)
C)
D)
Answer: D
5
D)
23 x 6
Suppose u and v are differentiable functions of x. Use the given values of the functions and their derivatives to find the value of the indicated derivative.
14) u(1) = 4, u (1) = -6, v(1) = 7, v (1) = -3. d (2u - 4v) at x = 1 dx
A) -20
B) 36
C) 0
D) -24
Answer: C Solve the problem. 15) Assume that a watermelon dropped from a tall building falls y = 16t2 ft in t sec. Find the watermelon's average speed during the first 4 sec of fall and the speed at the instant t = 4 sec. A) 32 ft/sec; 64 ft/sec
B) 65 ft/sec; 130 ft/sec
C) 64 ft/sec; 128 ft/sec
D) 128 ft/sec; 65 ft/sec
Answer: C Find y . 16) y =
2 2 +x -x x x
A)
8 + 2x x3
B) -
4 - 2x x3
C) -
8 - 2x x3
D) -
8 + 2x x
Answer: C Find the derivative of the function. x2 + 8x + 3 17) y = x
A) y =
2x + 8 2x 3/2
B) y =
3x2 + 8x - 3 x
C) y =
Answer: C
6
3x2 + 8x - 3 2x3/2
D) y =
2x + 8 x
Solve the problem. 18) Under standard conditions, molecules of a gas collide billions of times per second. If each molecule has diameter t, the average distance between collisions is given by 1 L= , 2 t2 n where n, the volume density of the gas, is a constant. Find
A)
dL =dt
2
2 t3 n
B)
dL 1 = dt 2 2 t3 n
dL . dt
C)
dL =dt
1 2 tn
D)
dL = dt
Answer: A Find the derivative. 19) s = t7 tan t -
t
A)
ds 1 = 7t6 sec2 t dt 2 t
B)
ds 1 = - t7 sec2 t + 7t6 tan t + dt 2 t
C)
ds 1 = t7 sec t tan t + 7t6 tan t dt 2 t
D)
ds 1 = t7 sec2 t + 7t6 tan t dt 2 t
Answer: D 20) y = (csc x + cot x)(csc x - cot x) A) y = - csc x cot x
B) y = - csc2 x
C) y = 1
Answer: D 21) y =
2 1 + sin x cot x
A) y = - 2 csc x cot x + sec2 x
B) y = 2 csc x cot x - sec2 x
C) y = 2 cos x - csc2 x
D) y = 2 csc x cot x - csc2 x
Answer: A Find the indicated derivative. 22) Find y
if y = 6x sin x.
A) y
= 6 cos x - 12x sin x
B) y
= - 6x sin x
C) y
= - 12 cos x + 6x sin x
D) y
= 12 cos x - 6x sin x
Answer: D
7
D) y = 0
2
2 t3n
Solve the problem. 23) Find the tangent to y = 2 - sin x at x = . A) y = - x +
-2
B) y = x - 2
C) y = x -
+2
D) y = - x + 2
Answer: C 24) Does the graph of the function y = tan x - x have any horizontal tangents in the interval 0 A) No
B) Yes, at x =
C) Yes, at x = 0, x = , x = 2
D) Yes, at x =
2
,x=
x
2 ? If so, where?
3 2
Answer: C The function s = f(t) gives the position of a body moving on a coordinate line, with s in meters and t in seconds. 25) s = 5t2 + 3t + 7, 0 t 2 Find the body's speed and acceleration at the end of the time interval. A) 23 m/sec, 20 m/sec2
B) 23 m/sec, 10 m/sec2
C) 30 m/sec, 10 m/sec2
D) 13 m/sec, 2 m/sec2
Answer: B Solve the problem. 26) Suppose that the dollar cost of producing x radios is c(x) = 400 + 20x - 0.2x2 . Find the marginal cost when 40 radios are produced. A) $4
B) -$880
C) $36
D) $880
Answer: A Suppose that the functions f and g and their derivatives with respect to x have the following values at the given values of x. Find the derivative with respect to x of the given combination at the given value of x. x f(x) g(x) f (x) g (x) 27) 3 1 9 6 7 4 3 3 2 -6 f2(x) ยท g(x), x = 3
A) 84
B) 25
C) 61
Answer: D
8
D) 115
Find the derivative of the function. 28) q =
20r - r7
A)
1 2 20r - r7
B)
20 - 7r6
-7r6
C)
2 20r - r7
20r - r7
D)
Answer: B 29) s = sin
A) C)
7 t 7 t - cos 2 2 7 7 t 7 7 t cos sin 2 2 2 2
B)
7 7 t 7 7 t cos + sin 2 2 2 2
7 7 t 7 7 t cos sin 2 2 2 2
D) cos
7 t 7 t + sin 2 2
Answer: C cos x 5 1 + sin x
30) h(x) =
A) 5 C)
cos x 4 1 + sin x
-5 cos4 x (1 + sin x)5
B) -5
sin x 4 cos x
D) -
4 sin x cos x 4 cos x 1 + sin x
Answer: C Find dy/dt. 31) y = cos7 ( t - 16) A) -7 cos6( t - 16) sin( t - 16)
B) -7 cos6 ( t - 16) sin( t - 16)
C) 7 cos6( t - 16)
D) -7 sin6 ( t - 16)
Answer: A Solve the problem. 32) Find dy/dx given y = (a) x2 sin x3 (b) sin7 x cos x (c) cos4 x 4 (d) sin (x 3 + x 2 + x + 1) Answer: (a) 3x 4 cos x3 + 2x sin x3 (b) 7 cos2 x sin6 x - sin8 x (c) -16x 3 cos3 x 4 sin x 4 (d) (3x 2 + 2x + 1) cos (x 3 + x 2 + x + 1)
9
1 2 20 - 7r6
33) Find the exact coordinates of the inflection points and critical points marked on the graph of 2 f(x) = x3 - 2x2 -6x. 3
Answer: maximum at (-1,
10 22 ); minimum at (3, -18); inflection point at (1, ) 3 3
34) Find the exact coordinates of the inflection points and critical points marked on the graph of f(x) = 4x5 - 100x3 -5.
Answer: maximum at (- 15, 2318.79); minimum at ( 15, 30 30 ( , -1442.77), (, 1432.77) 2 2
10
-2328.79); inflection points at (0, -5),
35) Match the graph of the function (1 - 5) with the graph of its second derivative (A-E). (1) (A)
(2)
(B)
(3)
(C)
(4)
(D)
(5)
(E)
Answer: 1 C, 2 A, 3 B, 4 E, 5 D
11