Standardized Test Practice - Cumulative, Chapters 1-5 Read each question. Then fill in the correct answer on the answer document provided by your teacher or on a sheet of paper. 1. The table below shows the membership cost for two CD clubs. How many CDs would you need to buy in a year in order for the total cost of both memberships to be the same?
A 30 B 25 C 20 D 15
SOLUTION: The annual fee for Club #1 + the cost per CD × the number of CDs = the annual fee for Club #2 + the cost per CD × the number of CDs. Let c = the number of CDs.
You would need to buy 30 CDs in a year for the total cost of both memberships to be the same. So, Choice A is the correct answer.
2. Georgina needs to practice the piano for at least 45 minutes tonight. Which of the following inequalities represents this situation? F t ≤ 45 G t < 45 H t ≥ 45 J t > 45
SOLUTION: Let t = the number of minutes Georgina needs to practice the piano. So, t ≥ 45. Choice H is the correct answer.
3. On Monday, the price of a share of stock was $79. It fell $3 each day for 11 consecutive days. Which of the following expressions could you use to find the price of the stock on any one of those days? A 3d + 79 B 3d – 79 C –3d + 79 D –3d – 79
SOLUTION: The price of stock = the amount it fell each day times the number of days plus the starting price. Let the amount the stock fell each day be represented by the integer –3. Let d = number of days. So, the expression –3d + 79 could be eSolutions - Powered by Cognero Page 1 usedManual to find the price of the stock on any day. Choice C is the correct answer.
4. Jonathan has a gift card worth $75. If each DVD costs $12.50, how many DVDs can he buy if he spends no more
H t ≥ 45 J t > 45
SOLUTION:
Standardized Test Practice - Cumulative, Chapters 1-5
Let t = the number of minutes Georgina needs to practice the piano. So, t ≥ 45. Choice H is the correct answer.
3. On Monday, the price of a share of stock was $79. It fell $3 each day for 11 consecutive days. Which of the following expressions could you use to find the price of the stock on any one of those days? A 3d + 79 B 3d – 79 C –3d + 79 D –3d – 79
SOLUTION: The price of stock = the amount it fell each day times the number of days plus the starting price. Let the amount the stock fell each day be represented by the integer –3. Let d = number of days. So, the expression –3d + 79 could be used to find the price of the stock on any day. Choice C is the correct answer.
4. Jonathan has a gift card worth $75. If each DVD costs $12.50, how many DVDs can he buy if he spends no more than $75? F up to 6 DVDs G more than 6 DVDs H up to 7 DVDs J more than 7 DVDs
SOLUTION: Cost of each DVD × the number of DVDs ≤ $75. Let d = the number of DVDs.
So, Jonathan can buy up to 6 DVDs. Choice F is the correct answer.
5. Solve the following equation. x – 7 = x – 10 Ax=9 B x = 18 C x = 21 D x = 24
SOLUTION:
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Standardized Test Practice - Cumulative, Chapters 1-5 So, Jonathan can buy up to 6 DVDs. Choice F is the correct answer.
5. Solve the following equation. x – 7 = x – 10 Ax=9 B x = 18 C x = 21 D x = 24
SOLUTION:
So, Choice B is the correct answer.
6. What is the perimeter of the triangle below?
F 32 millimeters G 35 millimeters H 37 millimeters J 41 millimeters
SOLUTION: To find the perimeter of the triangle, find the sum of the lengths of its sides. 9 + 12 + 16 = 37 So, the perimeter is 37 millimeters. Choice H is the correct answer.
7. The top running speed of a lion is lion run? A 45 mph B 50 mph C 55 mph eSolutions D 60Manual mph - Powered by Cognero
SOLUTION:
that of a cheetah. If a cheetah can run up to 70 miles per hour, how fast can a
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SOLUTION: To find the perimeter of the triangle, find the sum of the lengths of its sides. 9 + 12 + 16 = 37 Standardized Test Practice - Cumulative, Chapters 1-5 So, the perimeter is 37 millimeters. Choice H is the correct answer.
7. The top running speed of a lion is
that of a cheetah. If a cheetah can run up to 70 miles per hour, how fast can a
lion run? A 45 mph B 50 mph C 55 mph D 60 mph
SOLUTION: To find the running speed of the lion, multiply the cheetah’s running speed by
.
(70) = 50 So, a lion can run 50 miles per hour. Choice B is the correct answer. Record your answers on the answer sheet provided by your teacher or on a sheet of paper. 8. Write an inequality to represent the number line below.
SOLUTION: There is a closed dot at –9 which means it is included. The arrow points to the left. So, n ≤ –9 represents the number line.
9. GRIDDED RESPONSE What is the area, in square meters, of the right triangle shown below?
SOLUTION: To find the area of a triangle, multiply
times the length of the base times the height.
So, the area of the triangle is 35 square meters.
10. GRIDDED RESPONSE Solve the equation. 7n – 11 = 3(12 – 4n) + 10
SOLUTION:
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Standardized Test Practice - Cumulative, Chapters 1-5 So, the area of the triangle is 35 square meters.
10. GRIDDED RESPONSE Solve the equation. 7n – 11 = 3(12 – 4n) + 10
SOLUTION:
11. Describe when to flip the direction of an inequality symbol when solving inequalities. Give an example. SOLUTION: Sample answer: Flip the direction of the inequality symbol when multiplying or dividing each side of the inequality by a negative number.
12. Forty out of 48 freshmen and 42 out of 50 sophomores had perfect attendance last quarter. a. What fraction of each class had perfect attendance last quarter? Write your answers in lowest terms. b. Write the fractions as decimals. c. Which class had a greater portion have perfect attendance last quarter?
SOLUTION: a. To write the fraction of students that had perfect attendance last quarter, write the number that had perfect attendance over the total number of students. freshmen:
or
sophomores:
or
b. To write the fractions as decimals, divide the numerator by the denominator. freshmen: sophomores: c. Compare the hundredths place of the decimals to find which class had a greater portion have perfect attendance last quarter. Because 0.84 >
, the sophomores had a greater portion have perfect attendance last quarter.
13. The equation 2w + 36 = 88 represents the relationship between the width w of Daniel’s yard and the total amount of fencing he has.
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a. Solve the equation for w, the width of the yard. b.
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sophomores: c.
Compare the hundredths place of the decimals to find which class had a greater portion have perfect attendance Standardized Test Practice - Cumulative, Chapters 1-5 last quarter. Because 0.84 >
, the sophomores had a greater portion have perfect attendance last quarter.
13. The equation 2w + 36 = 88 represents the relationship between the width w of Daniel’s yard and the total amount of fencing he has.
a. Solve the equation for w, the width of the yard. b. If Daniel increased each side by 12 feet, how much total fencing would he need?
SOLUTION: a.
So, the width is 26 feet. b. If Daniel increased each side by 12 feet, then 26 + 12 + 36 + 12 + 26 + 12 or 124 feet of fencing would be needed. Record your answers on a sheet of paper. Show your work.
14. The formula C =
(F – 32) can be used to convert temperatures in degrees Fahrenheit, F, to degrees Celsius, C.
a. Water boils when it reaches a temperature of 212° Fahrenheit. Write this temperature in degrees Celsius. b. Water freezes at a temperature of 0° Celsius. Write this temperature in degrees Fahrenheit. c. Solve the formula for F to find a new formula that converts temperatures from Celsius to Fahrenheit.
SOLUTION: a. To write 212° Fahrenheit as degrees Celsius, replace F with 212 in the equation C =
(F – 32).
So, 212° Fahrenheit is 100º Celsius. b. To write 0° Celsius as degrees Fahrenheit, replace C with 0 in the equation C =
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(F – 32).
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So, 212° Fahrenheit is 100º Celsius.
Standardized Test Practice - Cumulative, Chapters 1-5 b. To write 0° Celsius as degrees Fahrenheit, replace C with 0 in the equation C =
(F – 32).
So, 0° Celsius is 32º Fahrenheit. c.
To convert a temperature from Celsius to Fahrenheit use the formula F = 1.8C + 32.
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