Resonance and Formal Charge 1

Chem 1011 – Intersession 2011 Class #6 13-May-11 1 Class 6: Resonance and Formal Charge • Sec 9.7 – Lewis Structures of Molecular Compounds and Po...
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Chem 1011 – Intersession 2011 Class #6

13-May-11

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Class 6: Resonance and Formal Charge •

Sec 9.7 – Lewis Structures of Molecular Compounds and Polyatomic Ions (con’t) ▫ ▫



Writing Lewis Structures for Molecular Compounds Writing Lewis Structures for Polyatomic Ions

Sec 9.8 – Resonance, Formal Charge ▫ ▫

Resonance Formal Charge

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Formal Charge • Formal Charge ▫ The number of valence electrons in an isolated atom minus the number of electrons assigned to that atom in a Lewis structure.

• For any particular atom within the Lewis Structure: FC = # of valence e– – # of lone pair e– – ½ (# of bonding e–)

• A helpful way to remember how to find FC just by looking at the atom’s surroundings: FC = # of valence e– – dots around atom – lines around atom

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Formal Charge • In cases where more than one Lewis structure seems possible, formal charges can be used to determine which structure is most accurate. • Note that formal charges are hypothetical only, and are not real charges ▫ They are a form of ―electron book-keeping‖ that helps in the selection of a probable Lewis structure. ▫ It relates the number of electrons each atom ―owns‖ in the structure, compared to how many valence electrons it typically has

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Chem 1011 – Intersession 2011 Class #6

13-May-11

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Formal Charge • Formal Charge must be considered when determining whether or not a Lewis Structure is plausible • Things to look out for:

▫ The sum of the formal charges must equal:  zero for a neutral molecule  the charge for a polyatomic ion

▫ Where formal charges are required (ie, in polyatomic ions), they should be as small as possible. ▫ Negative formal charges usually appear on the most electronegative atoms; positive formal charges on the least electronegative atoms. ▫ Structures having formal charges of the same sign on neighbouring atoms are unlikely.

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Problems • Given the two potential structures of the nitronium ion (NO2+) below, identify which is the most plausible. O=N=O

+

O≡N—O

0 +1 0

+

+1 +1 –1



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Manipulating Formal Charges • What if the Lewis Structure we’ve built isn’t a suitable one? How can we manipulate the formal charges? • Example – Perchlorate (ClO4–) ▫ The Lewis Structure, after building the skeletal structure and adding in all lone pairs, looks like:





O



O — Cl — O O

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Chem 1011 – Intersession 2011 Class #6

13-May-11

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Manipulating Formal Charges • Assign all Formal Charges —

–1



O

+3



O — Cl — O –1

O

Chlorine

e–

–1

–1

Oxygen (Each)

e–

FC = v – lp FC = 7 – 4 – 0 FC = +3

– ½ bp

e–

FC = v e– – lp e– – ½ bp e– FC = 6 – 6 – 1 FC = –1

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Manipulating Formal Charges • Even though all FC add to –1, this is not a desirable structure • Keeping in mind two important points from before: ▫ Where formal charges are required (ie, in polyatomic ions), they should be as small as possible. ▫ Negative formal charges usually appear on the most electronegative atoms; positive formal charges on the least electronegative atoms.

• This means our end goal here is to have a single O atom carrying a –1 formal charge, and all others at zero

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Reducing Formal Charges • We can interpret from Formal Charge that: ▫ Atoms with a positive FC aren’t surrounded by enough electrons ▫ Atoms with a negative FC are surrounded by too many electrons

• If a negative FC resides next to a positive FC, a lone pair from the negative atom can be converted into a bonding pair to be shared with the positive atom, thus neutralizing each others formal charges

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Chem 1011 – Intersession 2011 Class #6

13-May-11

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Reducing Formal Charges —

–1

— —

+3

+2

O

–1



–1



+1

O— — Cl — O

O — Cl — O

–1

— —

— —

–1

O

— —

O



–1

— —

O

O — Cl — O

–1





O — Cl — O –1



O



O

–1

O

–1

O

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Expanded Octet



— —

O

— —

O— — Cl — O –1

O

• This is the correct Lewis Structure for ClO4–

▫ How is this possible?! Cl is surrounded by 14 e–!

• Chlorine has an expanded octet ▫ It can disobey the octet rule to satisfy FC because it has access to d-block orbitals to ―store‖ extra electrons beyond the regular 8 e– ▫ This ability is only seen in atoms from Phosphorous (P) onwards. Be mindful of this before forming double bonds!

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Resonance • In this example, we picked 3 oxygen atoms randomly to form double bonds with the central Cl atom; there was no real reasoning behind selecting the atoms we did • Any combination of 3 O atoms double bonded to the Cl, and one O atom singly bonded and carrying a –1 formal charge would be correct • In cases where alternative ways to draw the same correct structure exist, the molecule or ion is said to possess resonance

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Chem 1011 – Intersession 2011 Class #6

13-May-11

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Resonance Structures • We can ―rotate‖ the placement of single / double bonds to create resonance structures for the ClO4– ion • Equivalent Resonance Structures are indicated by a double-headed arrow ▫ Here, 4 resonance structures are possible

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Resonance Structures —

O— — Cl — O

O— — Cl — —O —

–1

O

O –1



— — O



— —

O— — Cl — —O

O

O — Cl — —O –1

— —

–1



O



— —

O

— —

— —

O

O

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Problem • Draw the proper Lewis Structure for the Carbonate Ion, CO32– . Assign Formal Charges to all atoms and include all relevant resonance structures. • Complete the same for the Phosphate Ion, PO 43–

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Chem 1011 – Intersession 2011 Class #6

13-May-11

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Resonance Hybrids • The true structure of a molecule or ions is a combination of the different contributing resonance structures. • That resulting structure is known as a resonance hybrid • Example: Ozone (O3) ▫ Has two possible resonance structures ▫ Experiments have shown that both bonds lengths are equal, measuring between typical single and double bond lengths –

: :

:

: :

: :

:

: :

–½

+

–½

: :

+

:

+

:O — O — O ↔ O — O — O:

: :



O—O—O

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Resonance Hybrids • Benzene (C6H6) ▫ Is a cyclic structure – the carbons bond together form a ring ▫ Experimental evidence has shown that each C—C bond length is 140pm  A C—C double bond is 135pm  A C—C single bond is 147pm

▫ The actual benzene structure exists as a resonance hybrid Simplified Representation of Benzene

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Problems •

Draw a plausible Lewis structure for the following. Then, draw all resonance structures as well as the resonance hybrid: (a) SO2 molecule (b) Nitrate (NO3-) ion

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Chem 1011 – Intersession 2011 Class #6

13-May-11

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Next Week! •

Sec 9.9 – Exceptions to the Octet Rule ▫ ▫ ▫

Odd-Electron Species (Suggested Reading Only) Incomplete Octets Expanded Octets



Sec 9.11 – Bonding in Metals



Enjoy the weekend! 

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