Recap Last Lecture. Recap Last Lecture. Recap Last Lecture. Sub-shell energy. Four quantum numbers

Recap – Last Lecture Recap – Last Lecture •  Four quantum numbers. l=2 Energy n=3 n=2 n =1 Shell ml = -2,-1,0,+1,+2 l =1 ml = -1,0,+1 6e- l...
Author: Lorraine Dean
24 downloads 0 Views 667KB Size
Recap – Last Lecture

Recap – Last Lecture

•  Four quantum numbers. l=2

Energy

n=3

n=2

n =1 Shell

ml = -2,-1,0,+1,+2

l =1

ml = -1,0,+1

6e-

l=0

ml = 0

2e-

l =1

ml = -1,0,+1

6e-

l=0

ml = 0

2e-

l=0 Sub-shell

ml = 0 Orbital

•  Each shell is divided into subshells called s, p, d, f…. •  There is one extra subshell for each new shell

10e 18e -

8e-

2eElectrons

1

Recap – Last Lecture

1s 2s

2p

3rd shell

3s

3p

3d

4th shell

4s

4p

4d

4f

5th shell

5s

5p

5d

5f

etc

2

•  In hydrogen the energy of the sub-shells of a given n are degenerate (of the same energy). •  In all other atoms the sub-shells are of different energies.

•  Consequently electrons occupy a 3-D area. •  Uncertainty means we have electron ‘clouds’ though often represented by a surface incorporating 90% of the electron density.

p orbital

1st shell 2nd shell

Sub-shell energy

•  Electrons as waves.

s orbital

–  First shell: 1s –  Second shell: 2s and 2p –  Third shell: 3s, 3p and 3d –  Fourth shell: 4s, 4p, 4d and 4f

d orbital 3

4

1

Sub-shell energy

Electron configuration •  There are three rules in determining electron configuration:

•  The order in which the sub-shells are filled becomes important with the orbital energy increasing in the order:

•  Pauli exclusion principle - no two electrons can have the same four quantum numbers. i.e. maximum of 2 electrons in any one orbital.

1s < 2s < 2p < 3s < 3p < 4s < 3d < 4p < 5s < 4d < 5p …

•  Aufbau principle - fill up low energy orbitals first before high energy ones.

•  Follow the arrows, starting at the top, to get the order of energies of the subshells.

•  Hund’s rule - orbitals with the same energy (i.e. the same sub-shell) have the maximum number of unpaired electrons. 5

Electron Configuration

Electron Configurations

2 electrons can fit into a s subshell 6 electrons can fit into a p subshell 10 electrons can fit into a d subshell 14 electrons can fit into a f subshell

s: 2 electrons p: 6 electrons d: 10 electrons

•  Ground state (no ‘excited’ electrons) –  H has 1 electron: 1s1 –  He has 2 electrons: 1s2 1s2

(1s  now  full)  

2s1

–  Li has 3 electrons: –  Be has 4 electrons: 1s2 2s2 –  B has 5 electrons: 1s2 2s2 2p1

energy increases

energy increases

•  •  •  • 

6

(2s  now  full)  

1s

1s 2s

2p

3s

3p

3d

4s

4p

4d

4f

5s

5p

5d

5f

etc

7

2s

2p

3s

3p

3d

4s

4p

4d

4f

5s

5p

5d

5f

etc

8

2

s: 2 electrons p: 6 electrons d: 10 electrons

Electron Configurations •  Period 2, 3 & 4

s: 2 electrons p: 6 electrons d: 10 electrons

Electron Configurations •  Period 4

–  Ne has 10 electrons: 1s2 2s2 2p6 –  Na has 11 electrons: 1s2 2s2 2p6 3s1 –  Mg has 12 electrons: 1s2 2s2 2p6 3s2 –  Ar has 18 electrons: 1s2 2s2 2p6 3s2 3p6

or: [Ne] 3s1 or: [Ne] 3s2

–  Ca has 20 electrons: 1s2 2s2 2p6 3s2 3p6 4s2 or: [Ar] 4s2 –  Fe has 26 electrons: [Ar] 4s2 3d6 –  Zn has 30 electrons: [Ar] 4s2 3d10 –  Se has 34 electrons: [Ar] 4s2 3d10 4p4

–  K has 19 electrons: 1s2 2s2 2p6 3s2 3p6 4s1 or: [Ar] 4s1 –  Ca has 20 electrons: 1s2 2s2 2p6 3s2 3p6 4s2 or: [Ar] 4s2 No-ce!  We  have  filled  4s  before  3d   9

Periodic Table •  Group 1:

Box representation of orbitals •  A box represents an orbital and an arrow represents an electron. •  Indicates occupancy of orbitals.

•  Group 2: 2s1

–  Li: [He] –  Na: [Ne] 3s1 –  K: [Ar] 4s1

10

2 s2

–  Be: [He] –  Mg: [Ne] 3s2 –  Ca: [Ar] 4s2

3s 2s

core valence electrons electrons

2p 2s

2p

1s

•  Elements in the same group have the same valence electron configurations and, as a result, very similar chemical properties 11

1s

C

C: 1s2 2s2 2p2

Na Na: 1s2 2s2 2p6 3s1 12

3

Ions

Ions

•  Add or subtract electrons as appropriate.

•  In forming a cation, electrons are always removed from the sub-shell with the highest principle quantum number first. •  So for period 4 elements this means the 4s electrons are removed first.

Eg Na: 1s2 2s2 2p6 3s1 or [Ne] 3s1 Na+:1s2 2s2 2p6 or [Ne]

Eg K: 1s2 2s2 2p6 3s2 3p6 4s1 or [Ar] 4s1 K+:1s2 2s2 2p6 3s2 3p6 or [Ar]

Eg S: 1s2 2s2 2p6 3s2 3p4 or [Ne] 3s2 3p4 S2-: 1s2 2s2 2p6 3s2 3p6 or [Ne] 3s2 3p6

Eg Fe: 1s2 2s2 2p6 3s2 3p6 4s2 3d6 or [Ar] 4s2 3d6 Fe2+: 1s2 2s2 2p6 3s2 3p6 4s0 3d6 or [Ar] 3d6 Fe3+: 1s2 2s2 2p6 3s2 3p6 4s0 3d5 or [Ar] 3d5 13

Excited Configurations

Applications Mendeleev constructed his periodic table guided by the

•  Electrons can be excited to higher energy levels 1 s2

2s2

2p6

–  Ground state Na has –  One excited state of Na has 1s2 2s2 2p6 3s0 3p1 –  Excited state relaxes to ground state emitting yellow light

3s1

sodium  line  

1s2 2s2 2p6 3s0 3p1 The  Sun  

1s2

2s2

2p6

14

3s1

Na  

chemical properties of the elements. The reason this works is that elements in the same Group have similar valence p shell electron configurations. s Periodic Table has blocks of elements: “s block” (two elements wide) “p block” (6 elements wide) “d block” (10 elements wide) “f block” (14 elements wide)

d

16

emission  spectra   sodium  street  light  

15

f

4

Learning Outcomes:

Questions to complete for next lecture:

•  By the end of this lecture, you should:

1.  List the sub-shells present in the third shell and indicate the maximum number of electrons each may contain.

−  be able to write out the electron configuration for atoms and ions. −  recognise ground state and excited state electron configurations. −  Be able to use the box notation to represent orbital occupancy. −  Understand the three rules associated with determining electron configurations.

2.  Write the electron configuration of the following atoms or ions: a)  N b)  P3c)  Ca d)  Mn

3.  What feature do all elements in the ‘p’ – block of the Periodic Table share?

−  be able to complete the worksheet (if you haven’t already done so…) 17

18

Questions to complete for next lecture: 4.  The electron configuration of He is 1s2. Why do you think it is included in Group 18 in the Periodic Table rather than Group 2? 5.  Which of the following are impossible electron configurations? Give your reason(s). (a) 1s2 2p1 (b) 1s2 2s3 (c)  1s2 2s2 2p6 3d1 (d) 1s2 2s2 2p7 (e) 1s2 2s0.5 19

5

Suggest Documents