10/9/2016
NPV in Project Management FREE PROFESSIONAL DEVELOPMENT SEMINAR
The Basics • Most people know that money you have in hand now is more valuable than money you collect later on. • That’s because you can use it to make more money by running a business, or buying something now and selling it later for more, or simply putting it in the bank and earning interest. • Future money is also less valuable because inflation erodes its buying power. This is called the time value of money.
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The Basics • But how exactly do you compare the value of money now with the value of money in the future? • That is where net present value comes in.
What is Net Present Value? • Net present value (NPV) or net present worth (NPW) is a measurement of the profitability of an undertaking that is calculated by subtracting the present values (PV) of cash outflows (including initial cost) from the present values of cash inflows over a period of time. • Incoming and outgoing cash flows can also be described as benefit and cost cash flows, respectively.
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Example of Time Value of Money Example 1 - Increase in value What will be the future value of $100, 5 years from now if the interest rate is 10% F = P (1+i)n
F = $100 (1.10)5 |
|
F = $100 x 1.610 |
F = $161
______________________________________________________________________ Example 2- Decrease in value What is the present value of $161 to be received after 5 years if the interest rate is 10% P
F
(1i)
n
P=
161
(1+.10)
5
P = $100
Cash Flow • Cash flow is the difference between total cash inflow and outflows for a given period of time. • It is an important concept in evaluating investment opportunities, projects, etc., • Cash flow diagram is an excellent technique to visualize and solve several cash flow problems.
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Cash Flow Representation Income/Benefits/Receipts/Salvage
$40,000
Cash Flow Table
$33,000 Year
Income
0
$35,000
Expense $60,000
1
$33,000
$1000
2
$35,000
$1500
3
$40,000
$2000
0
1
$1000
2
3
$1500 $2000
Cost/Expenditure/Disbursements
$60,000
NPV in Decision Making • NPV is an indicator of how much value an investment or project adds to the firm. In financial theory, if there is a choice between two mutually exclusive alternatives, the one yielding the higher NPV should be selected.
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NPV in Decision Making If…
Means…
Then…
NPV > 0
the investment would add value to the firm
the project may be accepted
NPV < 0
the investment would subtract value from the firm
the project should be rejected
NPV = 0
the investment would neither gain nor lose value for the firm
We should be indifferent in the decision whether to accept or reject the project.
Single Payment – Compound Amount Factor
The future worth of a sum invested (or loaned) at compound interest.[1]
F = P ( 1 + i )n
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Single Payment – Compound Amount Factor
Example 3 If you invest $10000 in a fixed deposit that pays an interest of 8%, compounded annually, what will be the maturity value at the end of year 10? F= ?
Find Future Value, Given Present Value F = P (1+i)n F = $10000 (1+.08)10 F = $10000 (2.1589) F = $21589
i = 8%, n = 10
P = $10000 11
Single Payment – Present Worth Factor
The discount factor used to convert future values (benefits and costs) to present values.[1]
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Single Payment – Present Worth Factor
Example 4 A bank pays 6% interest rate per year for fixed deposit. If you want a maturity value of $10000 in 5 years, how much you should initially deposit in the bank? F=$10000
Find Present Value, Given Future Value. i = 6%, n = 5
P=
F (1+ i)n
P=
10000 (1+.06)5
P = 7474
P=? 13
Uniform Series, Compound Amount Factor
Takes a uniform series and moves it to a single value at the time of the last payment in the series.
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Uniform Series, Compound Amount Factor
Example 5 If you plan to deposit $900 each year in a savings account for 5 years and if the bank pays 6% per year, compounded annually, how much money will have accumulated at EOY 5? F=?
Find Future Value, Given Annuity. i = 6%, n = 5 0
F = 900 * 5.637
F = $5073
1
2
3
A = $900
4
5
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Uniform Series, Sinking Fund Factor
Takes a single payment and spreads into a uniform series over N earlier periods. The last payment in the series occurs at the same time as F.
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Uniform Series, Sinking Fund Factor
Example 6 How much you should deposit per year for 5 years to accumulate $80000 at the EOY 5 if the bank pays 6% interest per year compounded annually? F = $80000
Find Annuity, Given Future Value
i = 6%, n = 5 0
A = 80000*0.1774
A = $14192
1
2
3
4
5
A=? 17
Uniform Series, Capital Recovery Factor
Takes a single payment and spreads it into a uniform series over N later periods. The first payment in the series occurs one period later than P.
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Uniform Series, Capital Recovery Factor
Example 7 You have accumulated $100000 in a savings account that pays 7% per year, compounded annually. Suppose you wish to withdraw a fixed sum of money at the end of each year for 5 years, what is the maximum amount that can be withdrawn?
A=?
Find Annuity, Given Present Value.
0
1
2
3
4
5
i = 7%, n = 5
A =100000*0.2439 A = $24389
P = $100000 19
Uniform Series, Present Worth Factor
Takes a single payment and spreads it into a uniform series over N later periods. The first payment in the series occurs one period later than P.
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Uniform Series, Present Worth Factor
Example 8 If you decide to withdraw $5000 from your savings account at the end of each year for 5 years, how much money you should have in the bank now, if the bank pays 8% interest rate compounded annually.
A = $5000
Find Present Value, Given Annuity.
0
1
2
3
4
5
i = 8%, n = 5
P = 5000 *3.9927
P $19964
P=? 21
Arithmetic Gradient – Present Worth Factor
Takes a arithmetic gradient series and moves it to a single payment two periods earlier than the first nonzero payment of the series.
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Arithmetic Gradient – Present Worth Factor
Example 9 How much money must initially be deposited in a savings account paying 6% per year, compounded annually, to provide for 5 withdrawals that starts at $5000 and increase by $500 each year? Find Present Value, Given Annuity and Gradient.
+
+
0
1
2
3
4
5
i = 6%, n = 5
P = 21062 +3967
P = $25029
P=? 23
Arithmetic Gradient – Uniform Series Factor
Takes a arithmetic gradient series and converts it to a uniform series. The two series cover the same interval, but the first payment of the gradient series is 0.
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Arithmetic Gradient – Present Worth Factor
Example 10 How much money must initially be deposited in a savings account paying 6% per year, compounded annually, to provide for 5 withdrawals that starts at $5000 and increase by $500 each year? Find Present Value, Given Annuity and Gradient.
0
A = 500*1.8836
2
1
A = $942 A = $942 + $5000 = $5942
3
4
5
i = 6%, n = 5 P=?
P = $25029
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Investment Alternatives
Example 11 The XYZ manufacturing company is currently earning an average before-tax return of 25% on its total investment. The board of directors of XYZ is considering three project as given in the below table.
End of Year
Select a desirable project based on Net Present Value.
Cash Flows Project A Project B Project C
0
-$50000
-$80000
-$53000
1
20000
30000
23000
2
20000
30000
23000
3
20000
30000
23000
4
20000
30000
23000
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Investment Alternatives
Example 12 NPVA = -$50000 + $20000(P/A, 25%, 4) = -$2760 NPVB = -$80000 + $25000(P/A, 25%, 4) = -$20950 NPVC = -$53000 + $23000(P/A, 25%, 4) = $1326
Based on NPV, Project C is favorable.
EOY
Cash Flows Project A Project B Project C
0
-$50000
-$80000
-$53000
1
20000
30000
23000
2
20000
30000
23000
3
20000
30000
23000
4
20000
30000
23000
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Depreciation and Taxes
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Depreciation
DEPRECIATION (1) Decline in value of a capitalized asset. (2) A form of capital recovery applicable to a property with a life span of more than one year, in which an appropriate portion of the asset's value is periodically charged to current operations.
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Computation Methods
STRAIGHT LINE METHOD For an asset with useful life n years, the annual depreciation in year j is
SD =
adjusted cost n
( j = 1,2,3,…..,n )
Adjusted cost = Asset Value – Salvage Value 30
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Straight Line Method
Example 13 A new machine costs $120,000, has a useful life of 10 years, and can be sold for $15,000 at the end of its useful life. Determine the annual straight-line depreciation amount for this machine.
120000 -15000 SD = = $10500 10
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Straight Line Method Year
Example 14
Determine the straight-line depreciation schedule for example 5.1
Depreciation Charge per year
Accumulated Depreciation,
Book Value at End of Year
1
$10500
$10500
$109500
2
$10500
$21000
$99000
3
$10500
$31500
$88500
4
$10500
$42000
$78000
5
$10500
$52500
$67500
6
$10500
$63000
$57000
7
$10500
$73500
$46500
8
$10500
$84000
$36000
9
$10500
$94500
$25500
10
$10500
$105000
$15000
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The effect of Tax and Depreciation
Example 15 An equipment can be purchased for $18000. The operating costs will be $10000 per year, and the useful life is expected to be 5 years, with $5000 salvage value that time. The present annual sales volume should increase by $16000 as a result of acquiring the equipment. The company’s tax rate is 50%. Using straight-line depreciation technique with 10% MARR, calculate Net Present Worth of this investment. Solution Straight Line Depreciation per year = Asset Value – Salvage Value / n Straight Line Depreciation per year = ($18,000 - $5000)/5 = $2600 33
The effect of Tax and Depreciation Calculation
Description
Year 1 Year 2 Year 3 Year 4 Year 5
Income - Expense
A. BTCF
$6000 $6000 $6000 $6000 $6000
(AV-SV)/n
B. Depreciation
-2600
-2600
-2600
-2600
-2600
C=A-B
C. Net Taxable Income
3400
3400
3400
3400
3400
D = C x .50
D. 50% Tax
-1700
-1700
-1700
-1700
-1700
E=C-D
E. Profit
1700
1700
1700
1700
1700
F=E+B
F. ATCF
4300
4300
4300
4300
4300
*BTCF – Before Tax Cash Flow, *ATCF – After Tax Cash Flow
NPV = -$18000 + $4300 (P/A, 10%,5) + $5000 (P/F, 10%,5) NPV = -$18000 + 16301 + 3104 NPV = $1405 34
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END OF SEMINAR Please Fill the FEEDBACK FORM and RETURN IT to the RECEPTION.
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