Lecture 17: The Role of Water in Slope Stability Key Questions 1. How does the weight of water influence the factor of safety? 2. What does too much w...
Lecture 17: The Role of Water in Slope Stability Key Questions 1. How does the weight of water influence the factor of safety? 2. What does too much water do to the cohesion strength of the sediment? 3. How does water interact with clay minerals in the sediment? 4. How does water decrease the “friction force” and hence the factor of safety?
La Conchita, CA
Slope Model
. W
θ
FS =
resisting forces driving forces
W x cosθ x μ + c
friction + cohesion
=
= Fp
The slope fails if FS is less than “1”
.
W
Friction = Ff
FN
θ
Fp
cohesion = c
θ
W x sinθ
Water makes slopes unstable
1. Water adds weight
. W
θ
One gallon of water weighs 8 lbs
If a 100 by 200 foot slope soaks up 2 inches of rain, the slope weight increases by 200,000 lbs
Burien, WA near Shorewood Drive SW and 131st Street
FS =
resisting forces driving forces
W x cosθ x μ + c
friction + cohesion
=
= W x sinθ
Fp
water increases the weight of the slope which increases the driving force Fp
.
W
Friction = Ff
FN
θ
Fp
cohesion = c
θ
The slope fails if FS is less than “1”
2. Too much water in the voids spaces reduces or eliminates the cohesion force holding the grains together. air water
grain Remember, the cohesion force requires air and water in the pores spaces.
FS =
resisting forces driving forces
W x cosθ x μ + c
friction + cohesion
=
= Fp
W x sinθ
too much water decreases cohesion
.
W
Friction = Ff
FN
θ
Fp
cohesion = c
θ
The slope fails if FS is less than “1”
3. Slopes with high clay contents are more unstable when wet.
. W
θ
Scanning electron microscope image of clay
Clay minerals have a “negative” surface charge
_________________________________
water is polar __
+
+
clay minerals attract water molecules to their surfaces
_________________________________
dry, more friction, hence more resistant to sliding
wet, less friction, hence lower strength
FS =
resisting forces driving forces
W x cosθ x μ + c
friction + cohesion
=
= Fp
wet clay reduces friction
.
W
Friction = Ff
FN
θ
Fp
cohesion = c
θ
The slope fails if FS is less than “1”
W x sinθ
4. Water buoys up the grains which reduces the friction force
. W
θ
Slope Model
. W
θ
shear plane
weight
friction force
FN = W x cosθ = normal force
.
W
θ
cosθ =
adjacent hypotenuse θ
weight
FN
friction force = normal force x coefficient of friction or friction force = FN x μ
friction force
What happens when the grains are immersed in water?
friction force
water surface
= P = water pressure ρw = water density g = acceleration of gravity
h
h = depth to the balloon
P = ρw·g·h = hydrostatic pressure
water surface
= P = water pressure ρw = water density g = acceleration of gravity
h1
h2
h = depth to the balloon
P1 = ρw·g·h1
P2 = ρw·g·h2
Cubic grain immersed in water (side length “L”)
Fluid pressure at the top = P = ρgh
L Fluid pressure at the bottom = P = ρg(h +L)
ρ = water density g = acceleration of gravity h = depth below the water surface
Cubic grain immersed in water (side length “L”)
Fluid pressure at the top = P = ρgh
ΔP = ρgL = change in pressure L Fluid pressure at the bottom = P = ρg(h +L)
ρ = water density g = acceleration of gravity h = depth below the water surface
Cubic grain immersed in water (side length “L”)
Fluid pressure at the top = P = ρgh L ΔP = ρgL = change in pressure
Fluid pressure at the bottom = P = ρg(h +L) Area = L2 Force = pressure x area
ρ = water density g = acceleration of gravity h = depth below the water surface
Cubic grain immersed in water (side length “L”)
Fluid pressure at the top = P = ρgh L ΔP = ρgL = change in pressure
Fluid pressure at the bottom = P = ρg(h +L) Area = L2 Force = ΔP x L2
ρ = water density g = acceleration of gravity h = depth below the water surface
Cubic grain immersed in water (side length “L”)
Fluid pressure at the top = P = ρgh L ΔP = ρgL = change in pressure
Fluid pressure at the bottom = P = ρg(h +L) Area = L2 Force = ρgL3 = ρgV = buaoyancy force = FB
Cubic grain immersed in water
FB = ρgV = the magnitude of buoyancy force is equal to the weight of the volume of fluid the grain displaces (Archimedes’ Principle)
Cubic grain immersed in water
The grain weight is reduced by FB
FB
Wnew = Wdry – buoyancy force
buoyancy force
buoyancy force = the weight of the volume of water the grain displaces
The total weight pushing on the shear plane is reduced
the weight of each grain is reduced by the buoyancy force
friction force
weight
FN
friction force = normal force x coefficient of friction or friction force = FN x μ
friction force
FS =
resisting forces driving forces
W x cosθ x μ + c
friction + cohesion
=
= Fp
water decreases friction and cohesion and increases Fp all of which reduce FS
.
W
Friction = Ff
FN
θ
Fp
cohesion = c
θ
The slope fails if FS is less than “1”
W x sinθ
FS =
resisting forces driving forces
friction + cohesion
= Fp
FS =
resisting forces driving forces
friction + cohesion
= Fp
FS =
resisting forces driving forces
friction + cohesion
= Fp
FS =
resisting forces driving forces
friction + cohesion
= Fp
FS =
resisting forces driving forces
friction + cohesion
= Fp
FS =
resisting forces driving forces
friction + cohesion
= Fp
USGS Experimental Debris –Flow Flume
Seattle Area, Washington Cumulative Precipitation Threshold
Seattle Area, Washington Precipitation Intensity-Duration Threshold
The Pe Ell landslide occurred on December 3rd, 2007, blocking State Highway 6 and destroying three structures http://www.dnr.wa.gov/ResearchScience/Topics/GeologicHazardsMapping/Pages/landslides_dec07storm.aspx
Dec 11, 2004 - Massive landslide on the Sultan River, CA