Interferometric Synthetic Aperture Radar

EE/Ae 157 b Interferometric Synthetic Aperture Radar EE/Ge 157 b, Week 3 3-1 PRINCIPLES OF IMAGING RADAR CHARACTERISTICS OF RADAR WAVES • The p...
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EE/Ae 157 b

Interferometric Synthetic Aperture Radar

EE/Ge 157 b, Week 3

3-1

PRINCIPLES OF IMAGING RADAR CHARACTERISTICS OF RADAR WAVES



The propagation of radar waves are governed by Maxwell’s equations. From these equations, one can derive the so-called free-space wave equation: 2

 E •

2 c 2r

E0

The solution to this free-space wave equation is of the form:

E  Ae i kr t   •

There are three parameters in this wave solution that we commonly exploit in radar remote sensing: – Amplitude and polarization provides information about scattering properties and structure – Frequency diversity allows us to learn more about the size of scatterers – Phase information is used in interferometry to reconstruct three-dimensional topography, as well as small changes to topography

EE/Ge 157 b, Week 3

3-2

PRINCIPLES OF IMAGING RADAR TYPES OF IMAGING RADARS

Structural Information Polarimeter

Polarimetric Interferometer

Spectral Information Spectrometers EE/Ge 157 b, Week 3

Elevation Information Interferometer

Spatial Information Imaging Radar 3-3

RADAR INTERFEROMETRY HOW DOES IT WORK?

A2 B RADAR

A1

Antenna 1 Antenna 2

Return could be from anywhere on this circle

Return comes from intersection

SINGLE ANTENNA SAR EE/Ge 157 b, Week 3

INTERFEROMETRIC SAR 3-4

RADAR INTERFEROMETRY TRIGONOMETRY



The radar phase difference for a common transmitter is 1 

4



  



 ;2 

2



2



2   

A1

B 

  + 

For the spaceborne case, B   From the law of cosines, we find that   (    ) 2   2  B 2  2  B cos       2      B sin(   ) 2     B sin(   )





A2

z

0

 

h 

Z(y)

The phase difference is directly proportional to the electrical length of the interferometer baseline

EE/Ge 157 b, Week 3

y

SIMULTANEOUS BASELINE

3-5

RADAR INTERFEROMETRY Phase Difference in the Absence of Topography (B=60m, alpha=45,wavelength=5.66 cm, altitude = 234 km)

Radar Look Direction

EE/Ge 157 b, Week 3

360 Degrees

Radar Movement

3-6

RADAR INTERFEROMETRY Phase Difference is a function of the ELECTRICAL Length of the Baseline (B=60m, alpha=45, altitude = 234 km)

Wavelength = 5.66 cm

EE/Ge 157 b, Week 3

Wavelength = 24 cm

3-7

RADAR INTERFEROMETRY Example: Mt. Shasta, California

EE/Ge 157 b, Week 3

3-8

RADAR INTERFEROMETRY Mt Shasta Phase Difference (B=60m, alpha=45,wavelength=5.66 cm, altitude = 234 km)

Radar Look Direction

EE/Ge 157 b, Week 3

Radar Movement

3-9

RADAR INTERFEROMETRY TRIGONOMETRY (continued)



Now let  0 represent the look angle to a point on a “flat earth” as shown in the figure. Then

A2

z

sin      sin  0     

A1

B 

 sin  0     cos 0   



In terms of the interferometric phase, it means we can write

   •

2



B sin  0    



B cos 0   

The first term represents the phase difference measured for the “flat earth,” i.e. in the absence of any topography. If we remove the so-called “flat earth phase,” we are left with

 flat   •

2

2



 + 

0

 

h 

Z(y)

B cos 0   

y

This is the so-called “flattened interferogram”

EE/Ge 157 b, Week 3

3 - 10

RADAR INTERFEROMETRY Mt Shasta Flattened Interferogram (B=60m, alpha=45,wavelength=5.66 cm, altitude = 234 km)

EE/Ge 157 b, Week 3

3 - 11

RADAR INTERFEROMETRY SENSITIVITY TO TOPOGRAPHY



The elevation of the image point is found from z y     sin  0



• •

A1

The so-called ambiguity height is the elevation change required to change the flattened phase difference by one cycle  sin 0 ha  B cos  0   

A small ambiguity height means good sensitivity to topography If the elevation is the scene varies by more than the ambiguity height, the phase will be “wrapped”, since we only measure phase modulo 360 degrees.

EE/Ge 157 b, Week 3

A2

z B 

 + 

0

 

h 

Z(y)

y

3 - 12

RADAR INTERFEROMETRY Ambiguity Height Baseline = 60 m, Baseline Angle = 45 Degrees, Altitude = 234 km

Ambiguity Height in Meters

3000 L-Band

2500

C-Band

2000

1500

1000

500

0 20

30

40

50

60

70

Look Angle in Degrees EE/Ge 157 b, Week 3

3 - 13

RADAR INTERFEROMETRY PHASE UNWRAPPING

Phase z

8



Phase



2 0

EE/Ge 157 b, Week 3

4 2 0

y

ACTUAL ELEVATION PROFILE

6

y

WRAPPED PHASE

y

UNWRAPPED PHASE

3 - 14

RADAR INTERFEROMETRY Ambiguity Height & Phase Wrapping Relief exceeds ambiguity height, resulting in wrapped phases

Wavelength = 5.66 cm

EE/Ge 157 b, Week 3

Relief does not exceed ambiguity height; Phase is not wrapped

Wavelength = 24 cm

3 - 15

RADAR INTERFEROMETRY HOW IS IT IMPLEMENTED?

B

SIMULTANEOUS BASELINE Two radars acquire data at the same time EE/Ge 157 b, Week 3

B

REPEAT TRACK Two radars acquire data from different vantage points at different times 3 - 16

RADAR INTERFEROMETRY COMPARISON OF TECHNIQUES

IMPLEMENTATION

ADVANTAGES

DISADVANTAGES

Simultaneous Baseline

• Known baseline

• Difficult to get adequate baseline in space

• No temporal decorrelation

• High data rate from two radars

• Typically better performance

• Typically higher cost

• Lower data rate from one radar

• Temporal decorrelation

• Lower cost

• Baseline not well known and may be changing

Repeat T rack

• Depending on orbit, any baseline can be realized

EE/Ge 157 b, Week 3

3 - 17

INTERFEROMETRIC SAR PROCESSING GEOMETRY

Ra nge S phe re

D opple r C one Ba se line Ve ctor Aircra ft Position

Ve locity Ve ctor

Pha se C one

S ca tte re r is a t inte rse ction of Ra nge S phe re , D opple r C one a nd Pha se C one

EE/Ge 157 b, Week 3

3 - 18

EE/Ge 157 b, Week 3

3 - 19

PRINCIPLES OF IMAGING RADAR SAR IMAGE PROJECTION Radar Image Plane

A three-dimensional image is projected onto a two-dimensional plane, causing characteristic image distortions: • b’ appears closer than a’ in radar image LAYOVER

b’ a’

c’

d’

• d’ and e’ are closer together in radar image FORESHORTENING

e’ f’

g’

b c

EE/Ge 157 b, Week 3

d

i’

h

e a

h’

• h to i not illuminated by the radar RADAR SHADOW

f

g

i

3 - 20

RADAR INTERFEROMETRY EXAMPLE: TOPSAR DATA

EE/Ge 157 b, Week 3

3 - 21

RADAR INTERFEROMETRY IS IT POSSIBLE TO USE THE SPACE SHUTTLE TO MAP THE EARTH? (1994)



• • •

With the weight of a typical radar payload, the shuttle can be launched into an orbit with 57 degrees inclination, and altitude

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