I. The Bipolar Junction Transistor A. Physical Structure:
, , ,
• oxide-isolated, low-voltage, high-frequency design • typical of the bipolar transistor found in a BiCMOS process,
metal contact to base
p+
n
n+ buried layer
field oxide
metal contact to collector
p-type base
,, ,,, ,
,,, ,, A
n+ polysilicon contact to n+ emitter region
n+
A'
n+ buried layer
n+ - p - n sandwich (intrinsic npn transistor)
p-type substrate
(a)
,,,,,,,,, ,,,,,,,,, ,,,, , , , , ,,,, ,,,, , , ,,,,,,, ,,,,,,,, , , , (base)
A
p+
p
n + emitter area, AE (intrinsic npn transistor)
(emitter)
edge of n + buried layer
field oxide
A'
n+
(collector)
(b)
EECS 6.012 Spring 1998 Lecture 16
B. Circuit Symbol and Terminal Characteristics • Two devices that have complementary characterisitics npn transistor and the pnp transistor • The direction of the diode arrow indicates device type
pnp
npn
C B IB
+ VBE
− E
E +
IC + VCE − −IE
(a)
Normal operation: VCE positive IC positive VBE = 0.7 IB positive -IE positive
VEB −
B −IB
C
IE + VEC − −IC
(b)
Normal operation: VEC positive –IC positive VEB = 0.7 –IB positive IE positive
EECS 6.012 Spring 1998 Lecture 16
C. npn BJT Collector Characteristics • Similar test circuit as for n-channel MOSFET ... except IB is controlled instead of VBE IC = IC(IB, VCE)
+ V − CE IB
(a) IC (µA) 300
IB = 2.5 µA IB = 2 µA
250 200
IB = 1.5 µA
(saturation)
150
IB = 1 µA
(forward active)
100 IB = 500 nA 50 −3
−2
IB = 0 (cutoff)
−1 1
IB = 1 µA IB = 2 µA
2
3
4
5
6
VCE (V)
−4 (reverse active)
−8
(b)
EECS 6.012 Spring 1998 Lecture 16
D. Regions of Operation • Constant-current region is called forward active ... corresponds to MOSFET saturation region (!!!) IC = βF IB • Bipolar saturation region (modeled as a constant voltage) corresponds to MOSFET triode region V CE ≈ V CE ( sat ) = 0.1V
• Cutoff ... corresponds to MOSFET cutoff region • Reverse active ... terminal voltages for npn sandwich are flipped so that VCE is negative and VBC = 0.7 V. Only occasionally useful.
• Boundary between saturation and forward-active regions: V CE > V CE ( sat )
and
IB > 0
EECS 6.012 Spring 1998 Lecture 16
II. Bipolar Transistor Physics A. Forward Active Region of Operation
n+ polysilicon base-emitter depletion region
p-type base
n+ emitter 0
n-type collector
x base-collector depletion region
n+ buried layer outline of “core” n+pn sandwich
B. Game Plan • Understand thermal equilibrium potential and carrier concentrations. • Apply the Law of the Junction with VBE ≈ 0.7 V and VBC < 0 (typical forward-active bias point) to find the minority carrier concentrations at the depletion region edges. • Assume that the emitter and the base regions are “short” (no recombination) and find the diffusion currents.
EECS 6.012 Spring 1998 Lecture 16
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C. Thermal Equilibrium • Typically emitter is doped two orders of magnitude (at least) more heavily than the base; the collector is an order of magnitude more lightly doped than the base. • Minority carrier concentrations: pnE(x) (log)
n+ polysilicon contact
npB(x) (log)
emitter
pnC(x) (log)
base
collector
npBo = 103 cm−3
pnCo = 104 cm−3
pnEo = 10 cm−3
−WEo − xBEo
− xBEo 0
WBo
WBo + xBCo
x
(c)
• Electrostatic potential: n+ emitter: φo = 550 mV
−WEo − xBEo
−xBEo
φo(x) (mV) 500
n collector: φo = 360 mV
250
0
WBo
WBo + xBCo
x
−250 p base: −500 φo = −420 mV
EECS 6.012 Spring 1998 Lecture 16
D. Carrier Concentrations under Forward Active Bias • Boundary conditions at the edges of the depletion region are: Emitter-Base: exp[VBE / Vth] >> 0......Base-Collector: exp[VBC / Vth] = 0 • Ohmic contacts return carrier concentration to equilibrium φ(x)(V) 2.5 2 1.5 VCE = 2 V 1
thermal equilibrium
0.5
,, −WE − xBE
−xBE
W VBE = 0.7 V B
x
(a) pnC(x)
npB(x) npB(0)
emitter
collector
base
pnE(−xBE) pnCo npBo
npB(WB)
pnEo
−WE − xBE
WB + xBC
−0.5
pnE(x)
n+ polysilicon contact
0
−xBE 0
WB
pnC(WB+ xBC)
WB + xBC
x
(b)
EECS 6.012 Spring 1998 Lecture 16
,,
E. The Flux Picture - Forward Active Bias
• Rather than current densities, we use the concept of flux [# per cm2 per second] • The width of the electron flux “stream” is greater than the hole flux stream. n+ polysilicon
n+ emitter
,,,,,,,,,,,, ,,,,,,,,,,,, ,,,,,,,,,,,, ,,,,,,,,,,,, ,,,,,,,,,,,, ,,,,,,,,,,,, , , , , , ,
hole diffusion flux
majority electrons
majority hole flux from base contact
electron diffusion
p-type base
n-type collector
n+ buried layer
majority electron flux to coll. contact (minimum resistance path is through the n+ buried layer)
(b)
• The electrons are supplied by the emitter contact and diffuse across the base • Electric field in the collector depletion region sweeps electrons into the collector • n+ buried layer provides a low resistance path to the collector contact • The holes are supplied by the base contact and diffuse across the emitter • The reverse injected holes are recombined at the polysilicon ohmic contact
EECS 6.012 Spring 1998 Lecture 16
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III. Forward-Active Terminal Currents pnE(x)pnE(x)
emitter polysilicon (emitter) polysilicon contact contact
− xBE - W−W E -ExBE
pnCpnC (x)(x)
npBn(x) pB(x)
collector (collector)
base (base)
- xBE −xBE 0 0
WB WB
x WBW+Bx+ BC BC
x
x
A. Collector current: • Electron diffusion current density X emitter area
V BC e n pBo
⁄V
th
V
BE
⁄V
th
–e n pB(W B) – n pB(0) diff = qD ----------------------------------------------- = qD -----------------------------------------------------------------------------------J nB n n W W B B
qD n n pBo A E BE diff I C = – J nB A E = ------------------------------- e WB V
⁄V
th
EECS 6.012 Spring 1998 Lecture 16
B. Base current • Reverse-injected hole diffusion current density X emitter area
qD p p nEo V BE ⁄ V th diff J = – ------------------------- ( e –1) pE W E
qD p p nEo A E BE diff I B = – J pE A E = ------------------------------- e WE V
⁄V
th
– 1
C. Emitter current • Sum of IB and IC according to KCL (negative ... reference is positive-in)
qD p p nEo A E qD n n pBo A E V BE ⁄ V th diff diff I = J +J A = – ---------------------------------- + --------------------------------- e E nB pE E W W E B
EECS 6.012 Spring 1998 Lecture 16
IV. Forward-Active Current Gains A. Alpha-F - αF • The ratio of collector current to the magnitude of the emitter current qD n n pBo A E ------------------------------- WB IC -------- = ----------------------------------------------------------------------------------- = α F IE qD p p nEo A E qD n n pBo A E ------------------------------- + ------------------------------- WE WB
α
1 = ---------------------------------------------F D p N aB W B 1 + ----------------------------- D n N dE W E
• αF --> 1 ... typically, αF = 0.99.
B. Beta Forward Current Gains - βF • The ratio of collector current to base current IC 1 – αF I B = – I E – I C = ------- – I C = I C ---------------- αF αF αF I C = ---------------- I B = β F I B . 1 – αF • A typical value is βF = 100
EECS 6.012 Spring 1998 Lecture 16