BJT Configurations Voltage Gain
Current Gain
Power Gain
X
X
X
X
X
Common Emitter Common Collector Common Base
X
Common emitter: hgh input impedance, for general amplification of voltage, current and power from low power, high impedance sources.
• LTspice • Bipolar Junction Transistor
Common collector: aka "emitter follower" for high input impedance and current gain without voltage gain, as in an amplifier output stage. Common base: low input impedance for low impedance sources, for high frequency response. Grounding the base short circuits the Miller capacitance from collector to base and makes possible much higher frequency response.
Acnowledgements: Neamen, Donald: Microelectronics Circuit Analysis and Design, 3rd Edition
6.101 Spring 2014
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Lecture 3
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6.101 Spring 2014
Lecture 3
General Configuration
2
Transistor Configurations TRANSISTOR AMPLIFIER CONFIGURATIONS
Common Emitter
+15V
RL
+15V
R2
RL
R2
+
R2
+15V
+ +
Vin
Common Base
Common Collector
6.101 Spring 2014
R1 RE
VOUT
-
[a] Common Emitter Amplifier
Lecture 3
3
6.101 Spring 2014
-
+ Vin
+
+
R1
RE
-
VOUT -
-
[b] Common Collector [Emitter Follower] Amplifier
Lecture 3
+
+
+ Vin
+
VOUT
+
+
+
R1
RE
-
[c] Common Base Amplifier
4
Load Line – Operating Point
Variation of Collector Current with β Two Resistor Biasing
+20 V
R2
910
ICQ
+
2N3904
vout R1
91
• • •
Find Vout open circuit voltage: 20V Find ICQ max = 20/(910 +91) = ~20ma Draw load line.
IC
BFC -
IC
• • • •
6.101 Spring 2014
F VB 0.7V RB F RE
Variation of Collector Current with Beta 6
Two Resistor One Resistor
F 10.4 0.7V 22k F 2200
For RE = 0, just choose Q at ½ VCC for maximum swing. For RE > 0, set Q at ½ [VCC – VRE]. For ICQ = 10 mA, VRL = 9.1V, VRE = 0.91V, VCE = 10V. For ICQ = 10.5mA, VRL = 9.6V, VRE = 0.96V, VCE = 9.5V
Lecture 3
5
6.101 Spring 2014
ib
3.7 mA
2.9 mA
50
4.0 mA
4.0 mA
100
4.2 mA
5.0 mA
200
4.3 mA
5.4 mA
300
IC=0.6 mA
IC=2.5 mA
Lecture 3
6
IC
F
3.7 mA
50
4.0 mA
100
4.2 mA
200
4.3 mA
300
The base is connected to the emitter through with R3 and C2 . Since the AC gain between the base and the emitter is almost 1, the voltage at both ends of the resistor R3 is almost the same [the capacitor is a short circuit at signal frequencies]. In real life, the voltage gain is say 0.995 from base to emitter. The AC current through R3 is therefore (1−0.994) ÷ 4.7kΩ = 1.1 µA.
IC=0.6 mA
33K
IC
Bootstrapping*
Base Current – Resistor Divider
68K
F
IC
Result: stiff biasing with high input resistance at signal frequency.
Make ib small compared to the current through R2
*Horowitz and Hill Figure 2.65
See handout: Transistor bias stability 6.101 Spring 2014
Lecture 3
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6.101 Spring 2014
Lecture 3
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Common Emitter with Emitter Degeneration
Commom Emitter – Hybrid π TRANSISTOR AMPLIFIER CONFIGURATIONS WITH HYBRID- EQUIVALENT CIRCUITS COMMON EMITTER AMPLIFER
0 g m r
+15V
RL
RB C
2N3904
+
gm
IC
vout + vin _
VTH 26mv
R’s=RB // RS
+
IB
Rs
I CQ VTH
_
vout o ib RL o RL ; vin ib R 's r o 1RE R 's r o 1RE
v
Av
g m v
if R 's r o 1RE ;
then Av RL / RE
R’s=RB // RS b
c + r
Rs + vin
ib
RB
RL
vout oib RL o RL vin ib R's r R's r
if R'S r ; then Av
e _
_
6.101 Spring 2014
vout
Av
Lecture 3
o RL
o
• • •
g m RL
gm
9
6.101 Spring 2014
Input resistance (β+1)RE Voltage gain reduced by (1+gm RE) Voltage gain less dependent on β (linearity)
Lecture 3
10
AC Coupled vs DC Coupled Amplifiers
Gain vs Frequency
• AC Coupling – Advantage: easy cascading with DC blocking capacitor, bias stability and stage independent – Disadvantage: lot’s of R’s and C’s, no DC gain, need large C for low freqency
• DC coupling – Same gain at DC – Fewer R’s C’s
6.101 Spring 2014
Lecture 3
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6.101 Spring 2014
Lecture 3
12
Expanded Hybrid π
Miller Effect* – Common Emitter
rx
CM C [1 g m ( RC RL )] * Agarwal & Lang Foundations of Analog & Digital Electronics Circuits p 861 6.101 Spring 2014
Lecture 3
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6.101 Spring 2014
log scale
q g m IC kT 0 h fe (datasheet)
AV (dB)
R C
V2
0 -3dB
slope = -6 dB / octave slope = -20 dB / decade
C Cob (datasheet) gm fT (transit frequency datasheet) 2 (C C )
log f
1 1 j XC V j C Av 2 j RC 1 V1 R j X C R 1 j C Av
1 sRC 1
High frequency cutoff f hi
fHI or f-3dB Degrees
0o
1 2RC
gm C 2 fT r rx (low frequency) : datasheet or estimate 50 100
C
PHASE LAG
-45o -90o
(high frequency) : estimate 25 fHI or f-3dB
6.101 Spring 2014
Lecture 2
14
Hybrid‐π Parameters
Low Pass Filter LPF
V1
Lecture 3
log f
15
6.101 Spring 2014
Lecture 3
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2N3904 CE configuration, VCC +15v
β
Use max for worst case cu
6.101 Spring 2014
Lecture 3
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6.101 Spring 2014
hfe and High Frequency Limits
Lecture 3
18
Common Base Configuration
Small signal current gain versus frequency, hfe, of a BJT biased in a common emitter configuration: ib
vbe vbe jC r
h fe
g m vbe g m r ib 1 jr C 1 jr C
For hfe =1 = fT, (transit frequency )
hT
gm where C (c c ) 2C
For 2N3904*, IC =1ma, VCE=10V , cπ=25pF, cμ=2pF
fT
0.04mho 240 MHz 2 27 pF
for a gain of g m RL 100 f h
1 1 320kHz 2 r g m RL c 2 2.5 K(100)2 pF
Miller effect reduces high frequency limit! *Lundberg, Kent: Become One with the Transistor p29 6.101 Spring 2014
Lecture 3
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6.101 Spring 2014
Lecture 3
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Common Collector – Emitter Follower Biasing
Common Collector (Emitter Follower) 0 g m r gm
I CQ VTH
+15V
7.5 mA
VTH 26mv
R2 2N3904
1.0 k
7.5 mA
B
R’s=RB // RS Av
v g m v
o 1 RE o 1ib RE vout ; vin ib R 's r o 1RE R's r o 1RE
if R's r o 1RE ;
• •
6.101 Spring 2014
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Common Collector – Emitter Follower Biasing
7.5 mA R2
IDivider A
8.1 V
2N3904
R1
1.0 k B
7.5 mA 2N3904
Buffer with unity gain High input resistance driving low output resistance (current gain).
Lecture 3
+15V
+15V
then Av 1
•
With R1 = 24kΩ, R2 = 16 kΩ, the current through the voltage divider is 15 ÷ [40 kΩ] = 375 µA.
•
The 75 µA base current is 20% of 375 µA.
•
With R1 = 2 kΩ, will need a divider current that is ~ 4.1 mA. (75 µA is only ~2% of 4.1 mA, which is negligible)
•
The voltage drop across R2 will be [15 V – 8.1 V] = 6.9 V; R2 = 1.7 kΩ
•
But input impedance will be low = ~890Ω
•
Use bootstrapping configuration
IB RB 7.5 V
VB
R1 R1 R2
RB = R1||R2, VB = 15
VB = IBRB + 0.6V + 7.5V VB = [75 µA x 10k] + 0.6V + 7.5V VB = 750 mV + 0.6V + 7.5V VB = 8.9V [15 R1] ÷ [R1 + R2] = 8.9V 15 R1 = 8.9 x [R1 + R2] [15−8.9] R1 = 8.9 R2 R1 = 1.44 R2 [R1 x R2] ÷ [R1 + R2] = 10 kΩ [1.44R2 x R2] ÷ [1.44 R2 + R2] = 10kΩ R2 = 16.9 kΩ (use 16 kΩ) R1 = 1.44 R2 = 24.4 kΩ (use 24 kΩ)
6.101 Spring 2014
Lecture 3
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Low Frequency Hybrid‐ Equation Chart
7.5 mA
High gain applications Moderate input resistance High output resistance
= 24.4 kΩ (use 24 kΩ)
6.101 Spring 2014
Β = 100, iB = 7.5ma/100 =‐ 75µa Using Thevenin equivalent,
A
R1
• •
Lecture 3
23
6.101 Spring 2014
Lecture 3
Unity gain, low output resistance High input resist.
High gain, better high frequency response Low input resistance
24
Lab 2 •
Hands on introduction to – diodes, zener diodes – bjt – operational amplifiers (op‐amps) – power supplies
•
Lab instruments – current tracer – HP 428B Current Probe/Conduction Angle
•
Size resistor wattage accordingly!
•
Be careful with electrolytic capacitors!
6.101 Spring 2014
Lecture 3
25