Fractional order Sobolev spaces Thesis Matematikus MSc
Készítette:
Témavezet®:
Gerencsér Máté Izsák Ferenc adjunktus
Alkalmazott Analízis és Számításmatematikai Tanszék
Eötvös Loránd Tudományegyetem Természettudományi Kar Budapest, 2012
CONTENTS
1
Contents
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2
. . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . .
3
. . . . . . . . . . . . . . . . . . . .
5
3.1.
Real interpolation . . . . . . . . . . . . . . . . . . . . . . . . . . . . .
5
3.2.
Besov spaces . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . .
8
3.3.
Triebel-Lizorkin spaces . . . . . . . . . . . . . . . . . . . . . . . . . .
10
1. Introduction
2. Preliminaries
3. Classical scales of function spaces
. . . . . . . . . . . . . . . . . . . . . . .
13
. . . . . . . . . . . . . . . . . . . . . . . . . . . . . .
14
. . . . . . . . . . . . . . . . . . . . . . . . . . . . . .
17
4. The fractionalization of
Hcurl
4.2.
s The scale Hcurl .s The scale Hcurl
4.3.
Fractionalization of the
operator . . . . . . . . . . . . . . . . . .
19
4.4.
Non-positive indices . . . . . . . . . . . . . . . . . . . . . . . . . . . .
22
4.1.
curl
2
1. INTRODUCTION
1. Introduction The term fractional order Sobolev space might sound like a precise mathematical concept but in fact it is not. There are several methods to ll in the gaps between the traditional Sobolev spaces of integer order and in some cases the function spaces obtained are equivalent, while in other cases they are not.
Dierent approaches
focus on generalizing dierent properties of the Sobolev spaces and each has its own advantage. These generalizations can be interesting and useful both theoretically and in the applications as well. The aim of the thesis is to give an overview of these ideas and apply these techniques to the a non-classical Sobolev space
Hcurl .
The thesis is structured as follows. Chapter 2 summarizes the usual notions used in the following.
Chapter 3 describes the dierent scales of function spaces that
are usually referred to as fractional order Sobolev spaces, based on [1], [2], [5]. Chapter 4 examines the space of
L2
functions whose
fractionalization problems regarding this space.
curl
is also in
L2 ,
and some
The classical results of the topic
follows [4], the rest of the chapter is partially based on [3], partially my own work. I would like to thank my supervisor, Izsák Ferenc, for his help throughout the making of this thesis.
3
2. Preliminaries We will use the following notions throughout the thesis.
Ω ⊂ Rn . A bounded domain is called Lipschitz, if boundary ∂Ω there exists a neighborhood U of x such that
A domain is an open subset for every point
U ∩ ∂Ω
x
of its
is a graph of a Lipschitz-continous function.
For a normed space
Cg(u) (cf (u) ≤ g(u))
X
by default
||·||X
denotes its norm. The relation
denotes that there exists a xed
inequality holds for all
u
C > 0 (c > 0)
f (u) ≤
for which the
from a given space that is always clear from the context.
This constant can change from line to line but is always independent from
u.
The
f (u) ∼ g(u) denotes that cg(u) ≤ f (u) ≤ Cg(u). Two norms ||·|| and ||·||0 0 on a normed space U are said to be equivalent if ||u|| ∼ ||u|| . The space D(Ω) consists of the compactly supoorted innitely many times dierentiable functions with the topology dened by the convergence: φn → φ if and only if there is a compact set K ⊂ Ω with supp(φn ), supp(φ) ⊂ K and for all multiindex α ∂ α φn → ∂ α φ uniformly. Its dual, D0 is the space of the continuous linear functionals, or, the distributions, with the weak topology. For every locally integrable f correR Pn sponds a distribution with the eect φ → j=1 fj φj . For a normed function space V in which D is imbedded, we dene its dual to be the subset of distributions which extends uniquely to V . n α β The Schwartz space of functions u on R with sup |∂ u(x)x | < ∞ for all α, β 0 multiindices is denoted by S . The elements of S , the dual of S are called tempered 0 distributions. The Fourier transformation operator, which can be dened on S , is denoted by F , and the notation u ˆ = F(u) is also used. On S , we dene F(φ)(ξ) = R (2π)−n/2 exp(i < x, ξ >)dx and we extend it to S 0 by Fu(φ) = u(Fφ). n p Given a domain Ω ⊂ R we use the notation L (Ω) for the space of functions u R p with ||u||Lp (Ω) = |u|p < ∞ (1 ≤ p < ∞). When it does not cause confusion, we Ω use the abbreviation ||·||Lp (Ω) = ||·||p . The standard Sobolev space of the functions p k,p with their α-th partial derivatives in L (Ω) for all |α| ≤ k is denoted with W (Ω), P α accompanied with the norm ||u||W k,p (Ω) = |α|≤k ||∂ u||p (k ∈ N, 1 ≤ p < ∞). Here 0 we use the derivatives in the distributional sense, i.e. for u ∈ D , φ ∈ D , we dene ∂ alpha u(φ) = (−1)|α| u(∂ α (φ)). We distinguish the special case H k (Ω) = W k,2 (Ω). We p p n also use the abbreviation L = L (R ), and similarly with the Sobolev spaces. We relation
4
2. PRELIMINARIES
also use this convention for the spaces introduced later.
X and Y their direct sum is denoted by X ⊕ Y and 2 consists of the formal sums x + y where x ∈ X, y ∈ Y , and ||x + y||X⊕Y = (||x||X + ||y||2Y )1/2 . Note that changing 2 to any 1 ≤ p < ∞ we obtain equivalent Banach spaces. If X and Y are Hilbert spaces, the norm can also be characterized by the identities ||x + 0||X⊕Y = ||x||X , ||0 + y||X⊕Y = ||y||Y , and the orthogonality of the components. Given a closed subspace U in a Hilbert space PU denotes the projection operator to U . Given two Banach spaces
5
3. Classical scales of function spaces This section aims to cover most of the possible denitions of fractional order Sobolev spaces that can be found in the literature and describe their relations to each other.
To avoid confusion, we will omit the term fractional order Sobolev
space and use other common names for these spaces instead. We will formulate the dierent but equivalent denitions in forms of theorems. For the detailed proofs we refer to [1], [2], [5].
3.1. Real interpolation
X0 X0 ∩ X1 = 6 {0}
Given two Banach spaces space
X
with a
and
X1 ,
both continously imbedded in a Banach
- such a pair is called an interpolation couple -,
interpolation methods provide ways to construct intermediate spaces between them. In many cases, including the ones we will deal with,
X1 .
X0
is continuously imbedded in
The two main dierent methods are the real and complex interpolation but we
will now only go into details with the real method. The intersection
X 0 ∩ X1
and the algebraic sum
X0 + X 1
are themselves Banach
spaces with the norms
||u||X0 ∩X1 = max{||u||X0 , ||u||X1 }, ||u||X0 +X1 = inf{||x0 ||X0 + ||x1 ||X1 |u = x0 + x1 , x0 ∈ X0 , x1 ∈ X1 }. The intersection is continuously imbedded in
Xj
and
Xj
is continuously imbedded
j = 0, 1. In general, we say that a Banach space U is intermediate between X0 and X1 if X0 ∩ X1 is continuously imbedded in U and U is continuously imbedded in X0 + X1 . When X0 ⊂ X1 , this equals the intuitive requirement that and intermediate space has to be larger than X0 and smaller than X1 . For any given x ∈ X0 + X1 ⊂ X , t ≥ 0, 1 ≤ p < ∞ dene in the algebraic sum for
Kp (t, x) = inf{||x0 ||pX0 + ||tx1 ||pX1 |x = x0 + x1 , x0 ∈ X0 , x1 ∈ X1 }1/p . The usual approach takes
p = 1,
but it will be clear that all choice of
p
result in
6
3. CLASSICAL SCALES OF FUNCTION SPACES
equivalent Banach spaces. Since in the case of Hilbert spaces the choice turn out to be the suitable one, we introduce the abbreviation
1 ≤ q < ∞ and 0 < θ < 1. x ∈ X0 + X1 for which
The interpolation space
||x||q(X0 ,X1 )θ,q
(X0 , X1 )θ,q
∞
Z
[t−θ K(t, x)]q
= 0
K = K2 .
p=2
will
Now take
consists of the vectors
dt < ∞. t
Let (X0 , X1 ) be an interpolation couple, 0 < θ < 1, and 1 ≤ q < ∞. Then (X0 , X1 )θ,q is a Banach space and its norm satises Theorem 3.1
||u||(X ,X ) √ 1 √ ||u||X0 +X1 ≤ R ∞ −θ 0 1 θ,q q dt ≤ 2 ||u||X0 ∩X1 , [t min{1, t}] t 2 0
therefore (X0 , X1 )θ,q is an intermediate space between X0 and X1 . The extremal cases for
q = ∞ and/or θ = 0, 1 can also be dened, the correspond-
ing theorems are often trivial, but to avoid technical diculties we will not deal with these cases. Chopping the dening integral to integrals between
2j
and
2j+1
one can show the
following discretization theorem.
Theorem 3.2
Let (X0 , X1 ) be an interpolation couple, 0 < θ < 1, and 1 ≤ q < ∞.
Then for all x ∈ X0 + X1
||x||q(X0 ,X1 )θ,q
∼
∞ X
2−jqθ (K(2j , x))q .
j=−∞
Let (X0 , X1 ) be an interpolation couple, 0 < θ < 1, and 1 ≤ q < ∞. Then X0 ∩ X1 is dense in (X0 , X1 )θ,q . Theorem 3.3
Let us introduce a functional similar to
K,
this time on
X0 ∩ X1 :
J(t, u) = max{||u||X0 , ||tu||X1 }. This functional can be used to dene interpolation in another way resulting in equivalent spaces, but more importantly, it can be used to formulate the Reiteration
3.1. Real interpolation
7
X
Theorem. First, we dene an intermediate space
to be in the class
H(θ, X0 , X1 ),
if
K(t, u) ≤ Ctθ ||u||X ||u||X ≤ Ct−θ J(t, u) Lemma 3.4
for all for all
u ∈ X,
and
u ∈ X0 ∩ X1 .
Let (X0 , X1 ) be an interpolation couple, 0 < θ < 1, and 1 ≤ q < ∞.
Then (X0 , X1 )θ,q ∈ H(θ, X0 , X1 ).
Let (X0 , X1 ) be an interpolation couple, 0 < λ < 1, 1 ≤ q < ∞, 0 ≤ θ0 < θ1 ≤ 1, and Y0 , Y1 intermediate spaces between X0 and X1 such that Yj ∈ H(θj , X0 , X1 ), j = 0, 1. Let θ = (1 − λ)θ0 + λθ1 .Then Theorem 3.5 (Reiteration Theorem)
(Y0 , Y1 )λ,q = (X0 , X1 )θ,q . The immediate consequence - and the reason for the name of the theorem - is that with the previous notations
((X0 , X1 )θ0 ,q0 , (X0 , X1 )θ1 ,q1 )λ,q = (X0 , X1 )θ,q where
1 ≤ q0 , q1 < ∞
are arbitrary.
It is also an important property of the interpolation that its eect on the dual spaces can be expressed easily.
Let (X0 , X1 ) be an interpolation couple, 0 < θ < 1, and 1 < q < ∞ and assume that X0 ∩ X1 is dense in both X0 and X1 . Dene q 0 by 1/q + 1/q 0 = 1. Then (X1∗ , X0∗ ) is also an interpolation couple and
Theorem 3.6 (Duality Theorem)
(X1∗ , X0∗ )θ,q = (X0 , X1 )∗1−θ,q0 . It is worth to note another simple identity in which this kind of change of parameters appear:
(X0 , X1 )θ,q = (X1 , X0 )1−θ,q . When interpolating between two Hilbert spaces, it is natural to expect that the result is a Hilbert space as well. By checking the paralelogram identity the following theorem provides a sucient condition.
8
3. CLASSICAL SCALES OF FUNCTION SPACES
Let (X0 , X1 ) be an interpolation couple consisting of two Hilbert spaces and 0 < θ < 1. Then (X0 , X1 )θ,2 is also a Hilbert space.
Theorem 3.7
3.2. Besov spaces The scale of Besov spaces is obtained by using the real interpolation method to create intermediate spaces between Sobolev spaces. We have to note that in general the classical Sobolev spaces are not closed under interpolation, i.e. does not equal to
Lemma 3.8
Then
W k,p (Ω) usually
(Lp (Ω), W m,p (Ω))k/m,q .
Let Ω be a Lipschitz domain. Let 0 < k < m be integers and 1 ≤ p < ∞. W k,p (Ω) ∈ H(k/m, Lp (Ω), W m,p (Ω)).
Let 0 < s < ∞, 1 ≤ p ≤ ∞, and 1 ≤ q < ∞. Let m be the smallest integer larger than s. Then the Besov space B s,p,q (Ω) is dened by Definition 3.9
B s,p,q (Ω) = (Lp (Ω), W m,p (Ω))s/m,q . The Reiteration Theorem and the previous Lemma show us that in fact
B s,p,q (Ω) = (W k,p (Ω), W m,p (Ω))θ,q for any
k 0 such that s − 1/p > 0. Then the trace operator is continuous from B s,p,q (Rn ) to B s−1/p,p,q (Rn−1 ).
Theorem 3.11
Repeating taking traces gives imbedding theorems to spaces on large
k.
Rk
for suciently
These theorems extend to traces on suciently smooth surfaces of suciently
high dimension as well.
In case there exists a suitable extension operator from
these theorems also extend to functions in
B
s,p,q
Ω,
(Ω).
It is sometimes useful to examine what more well-known spaces includes the Besov space in question. This motivates the imbedding theorems similar to the following one.
Let 1 < p < ∞, 1 ≤ q < ∞, s > 0, such that sp > n. Then B s,p,q is imbedded in the space of continuous and bounded functions.
Theorem 3.12
The norms of the Besov spaces on
have a more intristic equivalent expressed
h ∈ Rn and a function u ∈ L(R3 ) dene uh to be the mapping x to u(x − h). Let ∆h u = u − uh , ωp (u, h) = ||∆h u||p , (m) m and for positive integers m let ωp (u, h) = ||(∆h ) u||p .
with the
L
p
Rn
-modulus of continuity. First, for a point
Let 1 < p < ∞, 1 ≤ q < ∞, m > s > 0 with m being an integer and u ∈ L (R ). Then u ∈ B s,p,q (Rn ) if and only if
Theorem 3.13 p
n
Z
Rn
|h|−s ωp(m) (u, h)
q dh < ∞. |h|n
Moreover, the q-th root of the expression above is equivalent to ||·||Bs,p,q . For non-integers
s = bsc + {s},
bsc ∈ N and {s} ∈ (0, 1), bsc-th order derivatives:
where
intristic norm can be dened using the
a closely related
Let 1 < p < ∞, 1 ≤ q < ∞, s > 0, and u ∈ W bsc,p (Rn ). Then u ∈ B s,p,q (Rn ) if and only if Theorem 3.14
X Z |α|=bsc
Rn
Z
α
α
p
|∂ u(x) − ∂ u(x − h)| Rn
q/p
|h|−{s}q
dh < ∞. |h|n
10
3. CLASSICAL SCALES OF FUNCTION SPACES
There is another equivalent intristic norm that will show some kind of relation between the Besov spaces and the Triebel-Lizorkin spaces dened in the next subsec-
Φ be an even function on the real line with the properties Φ(t) = 1 for |t| ≤ 1, Φ(t) = 0 for |t| ≥ 2, and |Φ(t)| ≤ 1 for all t. For each integer i i+1 let φi (t) = Φ(t/2 ) − Φ(t/2i ) and for any ξ ∈ Rn let ψi (ξ) = φi (|ξ|). Finally, dene −1 the operator Ti u = F (ξ → ψi (ξ)ˆ u(ξ)). One can regard the functions Ti u as dyadic parts of u with nearly disjoint frequencies. tion. To this end, rst let
Theorem 3.15
The norm ||u||Bs,p,q (Rn ) is equivalent to "
∞ Z X
(1 + 2sj )p |Tj u(x)|p dx
q/p #1/q .
Rn
j=−∞
3.3. Triebel-Lizorkin spaces
Let 0 < s < ∞, 1 ≤ p < ∞, and 1 ≤ q < ∞. Then the TriebelLizorkin space F (Ω) is dened by Definition 3.16
s,p,q
F s,p,q (Rn ) = {u : ||u||F s,p,q (Rn )
Clearly
F s,p,p = B s,p,p ,
Z =
Rn
∞ X
!p/q (1 + 2sj )q |Tj u(x)|q
1/q dx
< ∞}.
j=−∞
and therefore the Slobodeckij spaces are included in this
scale as well. Another important special case is obtained by generalizing the wellknown fact that for any
|ξ|2 )k/2 uˆ(ξ) is changing k to
k
integer
u ∈ W k,p
if and only if the function
the Fourier transform of a function from any
s≥0
Lp .
ξ → (1 +
The spaces we get by
in this property are often referred to as the Bessel potential
spaces.
Let 0 < s < ∞ and 1 ≤ p < ∞. Then u ∈ F s,p,2 if and only if the function ξ → (1 + |ξ|2 )s/2 uˆ(ξ) is the Fourier transform of a function from Lp . Theorem 3.17
(1+|ξ|2 )s/2 can be bounded from above and below by constant times 1+|ξ|s , −1 the previous condition can be rephrased that require u and ξ → F |ξ|s uˆ(ξ) to be p in L . The latter expression is also known as the fractional Laplacian of u, and so Since
the Bessel potential spaces can be obtained by generalizing the denition of Sobolev
3.3. Triebel-Lizorkin spaces
11
spaces by the derivatives of the function.
The fractional Laplacian is one of the
possible generalizations of the dierentiation operator (see [7], Chapter 2), it simply fractionalizes the positive operator that
F
m,p,2
=W
m,p
for integers
−∆.
It also follows from the previous Theorem
m.
It also turns out that the Bessel potential spaces can be obtained from the classical Sobolev spaces the same way as the Besov spaces if we use the complex interpolation method instead of the real interpolation.
Let (X0 , X1 ) be an interpolation couple. Let A denote the collection of bounded analytic functions f from the strip {θ + iτ |0 < θ < 1} to X0 + X1 that extend continously to the boundary with the property f (j + τ ) ∈ Xj and ||f (j + iτ )||Xj → 0 as |τ | → ∞, for j = 0, 1. For 0 < θ < 1 the complex interpolation space between X0 and X1 is Definition 3.18
[X0 , X1 ]θ = {u ∈ X0 + X1 |∃f ∈ A : f (θ) = u}
with the norm ||u||[X0 ,X1 ]θ = inf{max{sup ||f (iτ )||X0 , sup ||f (1 + iτ )||X1 }|f (θ) = u}. τ
τ
Although we omit the detailed description of this method, it is worth to note that it has similar properties to the real method. For example the analogues of the Reiteration Theorem and the Duality Theorem hold.
We also have the following
identities that show the connection between the two methods
(X0 , X1 )θ,1 ⊂ [X0 , X1 ]θ ⊂ (X0 , X1 )θ,∞ , ([X0 , X1 ]θ0 , [X0 , X1 ]θ1 )λ,q = (X0 , X1 )(1−λ)θ0 +λθ1 ,q , [(X0 , X1 )θ0 ,q0 , (X0 , X1 )θ1 ,q1 ]λ = (X0 , X1 )(1−λ)θ0 +λθ1 ,q , where
q
is dened by
1/q = (1 − λ)/q0 + λ/q1 .
Let 0 < s < ∞, 0 < θ < 1, m ≤ k integers with (1 − θ)m + θk = s, and 1 ≤ p < ∞. Then Theorem 3.19
F s,p,2 = [W m,p , W k,p ]θ .
12
3. CLASSICAL SCALES OF FUNCTION SPACES
Similar imbedding theorems holds for the Triebel-Lizorkin spaces as for the Besov spaces. For example, analogously to the one mentioned in the previous subsection, the following theorem holds.
Let 1 < p < ∞, 1 ≤ q < ∞, s > 0, such that sp > n. Then F s,p,q is imbedded in the space of continuous and bounded functions.
Theorem 3.20
Finally, we summarize the relations between the spaces introduced:
In the special case case
m
F s,p,q ⊂ B s,p,q
if
q ≤ p,
B s,p,q ⊂ F s,p,q
if
p ≤ q,
B s,p,q0 ⊂ B s,p,q1
if
q0 ≤ q 1 ,
F s,p,q0 ⊂ F s,p,q1
if
q0 ≤ q1 .
p = q = 2, B s,2,2 = F s,2,2
with the special cases
F m,2,2 = H m
in
is integer, and furthermore we have
B s,2,2 = (B s0 ,2,2 , B s1 ,2,2 )θ,2 = [B s0 ,2,2 , B s1 ,2,2 ]θ for
0 < s0 < s < s1 < ∞ Remark.
with
(1 − θ)s0 + θs1 = s.
Some of the denitions and the theorems were stated only in the case
n
Ω = R . These properties can be extended to more general domains via the use of an extension operator. In [6] it is shown that there exists an extension operator E such s,p,q that it simultaneously and boundedly extends functions in B (Ω) to B s,p,q (Rn ) s,p,q and F (Ω) to F s,p,q (Rn ) if the domain Ω is nice enough, for example, if it is a s,p,q Lipschitz domain. Here F (Ω) is dened as restrictions of functions on F s,p,q (Rn ). s,p,q The spaces B (Ω) were already dened, but from the existence of this extension operator it follows that they can also be dened through restriction.
13
Hcurl
4. The fractionalization of
In this section we deal with the possibilities of the fractionalization of the nonstandard Sobolev space
Hcurl = {u ∈ (L2 )3 |curl(u) ∈ (L2 )3 }.
important role in the theory of Maxwell equations.
This space plays an
Even the extension to integer
orders is not evident, we present two approaches. First recall some properties of the
curl(u) =
curl
operator. It is dened by
∂u3 ∂u2 ∂u1 ∂u3 ∂u2 ∂u1 − , − , − ∂2 ∂3 ∂3 ∂1 ∂1 ∂2
where derivatives are understood in the distributional sense. Its Fourier counterpart is the vectorial product with the longitudinal direction:
F(curl(u))(ξ) = i(ξ × uˆ(ξ)). The same formula holds if we replace
j ∈ N.
Here the operator
j
ξ×
curl
by
(curl)j , ξ×
by
ξ×j ,
and
i
by
ij
for any
is dened by
ξ ×j f (ξ) = ξ × · · · ξ× f (ξ) | {z } j
and similarly for
(curl)j .
The space
Hcurl
can be decomposed
Hcurl = Ker(curl) ⊕ Ker(curl)⊥ where the second component is compactly imbedded in
(L2 )3 .
This is known as the
Helmhlotz decomposition. The Fourier transform of a function in the kernel of the
curl from
points in the longitudinal direction almost everywhere. Conversely, if a function
(L2 )3
has a Fourier transform that points in the longitudinal direction, its
is zero. Therefore it is easy to see that if
u ∈ Ker(curl)⊥ ,
curl
then its Fourier transform
has to point perpendicular to the longitudinal direction. It is known that the sequence called the De Rahm-diagram
grad
curl
div
(H 1 )3 −→ Hcurl −→ Hdiv −→ (L2 )3
(1)
14
4. THE FRACTIONALIZATION OF
HCU RL
has the property that the image of each operator is included in the kernel of the next one, where
Hdiv = {u ∈ (L2 )3 |div(u) = Similarly, if our initial space is
∂u1 ∂u2 ∂u3 + + ∈ L2 }. ∂1 ∂2 ∂3
(L2 (Ω))3 ,
we can dene
Ω is bounded and has Σ1 , Σ2 , . . . ΣL such that
domain. Assume that connected surfaces
• Σl
Hcurl (Ω), Hdiv (Ω)
the property that there exist
for any
L
open
is an open part of a smooth surface,
• ∂Σl ⊂ ∂Ω, • Σl ∩ Σm = ∅ •
if
For any point
l 6= m,
x ∈ ∂Ω
there is an integer
rx ∈ {1, 2}
ρx > 0 center x
and a
0 < ρ < ρx the intersection of Ω with the ball with has rx connected components, each one being a Lipschitz
all
such that for and radius
ρ
domain.
Under these conditions the diagram (1) also has the property that the image of each operator is a closed subspace of nite codimension in the kernel of the next operator [4].
4.1. The scale
s Hcurl
If we consider the
curl
operator as a kind of dierentiation, it is natural to intro-
duce the following spaces
n Hcurl = {u ∈ (L2 )3 |curlj (u) ∈ (L2 )3 n Hcurl
for
j = 1, 2, . . . n}.
P 2 ||u||2H n = nj=0 ||curlj (u)||2 . curl s > 0 by dening
is a Hilbert space with the norm
this denition for any non-integer
dse
s Hcurl = ((L2 )3 , Hcurl )s/dse,2
where
dse
is the smallest integer larger than
We can extend
(2)
s.
Before moving on to examine these spaces further, we establish some simple properties of the real interpolation.
4.1. The scale
s Hcurl
15
Let X, Y, V, W be Banach spaces, 1 ≤ q < ∞, and 0 < θ < 1.
Proposition 4.1
Then
(X ⊕ V, Y ⊕ W )θ,q = (X, Y )θ,q ⊕ (V, W )θ,q
with equivalent norms. In case q = 2, the same holds for Hilbert spaces. Proof.
The equality of the sums simply follows from considering
1 √ (t ||x||X + ||y||Y + t ||v||V + ||w||W ) ≤ t ||x + v||X⊕V + ||y + w||Y ⊕W ≤ 2 ≤ t ||x||X + ||y||Y + t ||v||V + ||w||W . After taking inmums, multiplying by
dt respect to the measure on t In case
q =2
perpendicular to
[0, ∞),
tθ ,
taking
q -th
powers, and integrating with
we get the inequalities required.
it remains to show that for any
z + u ∈ (X ⊕ V, Y ⊕ W )θ,q , z
is
u.
4 < z, u >= ||z + u||2(X⊕V,Y ⊕W )θ,q − ||z − u||2(X⊕V,Y ⊕W )θ,q = Z =
∞
t−2θ (K(t, z + u))2 − (K(t, z − u))2
0 Note that the inmum dening
K
dt . t
can be decomposed:
K(t, z + u) = inf{||t(x + v)||2X⊕V + ||y + w||2Y ⊕W |z + u = (x + v) + (y + w)}1/2 = = inf{||tx||2X + ||y||2Y |z = x + y}1/2 + inf{||tv||2V + ||w||2W |u = v + w}. K(t, z − u)
has exactly same form, except that in the second inmum
−1. This does not aect the u)) − (K(t, z − u)) = 0 and < z, u >= 0. multiplied by
v
w are K(t, z +
and
value of the inmum, therefore
Let U, V, W be subspaces of a Hilbert space X , and suppose that W is closed, 1 ≤ q < ∞, and 0 < θ < 1. Then
Proposition 4.2
(U, V )θ,q ∩ W = (U ∩ W, V ∩ W )θ,q
with equivalent norms.
16
4. THE FRACTIONALIZATION OF
Proof.
HCU RL
w ∈ W . For every decomposition w = u + v we can take w = (PU ∩W u + PV ∩W v) + (PU ∩W ⊥ u + PV ∩W ⊥ v) instead. The second term is in W ⊥ by defnition, and ⊥ it is also a dierence of two elements of W , therefore it is in W ∩ W and thus it is Set
zero. The norm of the components can only decrease with this modication, therefore
KU ∩W,V ∩W (t, w) ≤ KU,V (t, w), while the other inequality is trivial. The of the two K functionals then implies the equivalence of the norms.
equivalence
Let U, V be Banach spaces with U compactly imbedded in V , 1 ≤ q < ∞, and 0 < θ < 1. Then (U, V )θ,q is also compactly imbedded in V . Proposition 4.3
Proof.
Let
{zn }
be a sequence in the unit ball of
n version of interpolation and K1 there are uj and
∈U
and
(U, V )θ,q . Using the discrete vjn ∈ V such that unj + vjn = zn
∞ h X iq 2−jθ (2j unj U + vjn V ) ≤ 2 ||zn ||(U,V )θ,q ≤ 2. j=−∞
We have
n uj ≤ 2j(θ−1)+1 , U
therefore
{unj } ⊂ V
has a Cauchy subsequence for all
j
mk and with the diagonal argument we get a subsequence {zmk } such that {uj } ⊂ V jθ is Cauchy for all j . Fix > 0 and choose j so that 2 < . Then we have vjn V < ml k 2 and therefore if N is chosen so that for mk , ml > N um < , then j − uj V
||zmk − zml ||V < 5. This statement is true in a more general way, but this weaker version easily implies a stronger one. Note that from the Schauder theorem it follows that if compactly imbedded in
V
then
V∗
is compactly imbedded in
U ∗.
In case
U
and
are reexive spaces we can apply the previous proposition to the dual spaces. the Duality Theorem we obtain that
U
is compactly imbedded in
the Reiteration Theorem we can conclude that
(U, V )θ2 ,q for 0 < θ1 < θ2 < 1. n Let H0,curl denote the orthogonal
(U, V )θ1 ,q
(U, V )θ,q
U
is
V
By
and by
is compactly imbedded in
complement of Ker(curl) in
n Hcurl .
the inner product, and therefore the orthogonality, is the same in every
Note that
n Hcurl
if one
of the functions is in Ker(curl). Proposition 4.1 shows that it suces to interpolate between these spaces. It turns out that they are subspaces of the traditional Sobolev spaces.
4.2. The scale
.s Hcurl
17
Proposition 4.4 n (H n )3 ∩ Ker(curl)⊥ = H0,curl
with equivalent norms. Proof.
Let
u∈
⊥ Ker(curl) . For the Fourier transform of such a function
ξ⊥ˆ u(ξ)
holds almost everywhere, therefore
||u||H n
0,curl
n n X X j ξ → ξ ×j uˆ(ξ) = ∼ curl (u) 2 = 2 j=0
j=0
n n X X j ξ → |ξ|j |ˆ = ξ → |ξ × uˆ(ξ)| 2 = u(ξ)| 2 ∼ ξ → (1 + |ξ|2 )n/2 |ˆ u(ξ)| 2 = j=0
j=0
= ξ → (1 + |ξ|2 )n/2 uˆ(ξ) 2 ∼ ||u||(H n )3 .
Using the results from the interpolation of Sobolev spaces we can write the following
Corollary 4.5 s Hcurl = Ker(curl) ⊕ ((B s,2,2 )3 ∩ Ker(curl)⊥ )
(3)
as Hilbert spaces, where by Proposition 4.3 the second component is compactly imbedded in (L2 )3 . This is a slightly generalized form of the Helmholtz decomposition. The consequence of this decomposition is that these spaces "behave well" under interpolation, i.e.
s1 s2 s (Hcurl , Hcurl )θ,2 = Hcurl for any
0 ≤ s1 < s < s 2
4.2. The scale
with
(1 − θ)s1 + θs2 = s.
.s Hcurl
There is another common way to extend the denition of
Hcurl
to integer indices,
found in e.g [4]. In this case we are not interested in the higher order
curls
of the
18
4. THE FRACTIONALIZATION OF
functions, but instead the smoothness of the function and the
curl
HCU RL
of the function is
.n simultaneously prescribed. Dene Hcurl by .n = {u ∈ (H n )3 |curl(u) ∈ (H n )3 }. Hcurl
These are also Hilbert spaces with the norm
||u||2H .n = ||u||2(H n )3 +||curl(u)||2(H n )3 . curl
It is possible to derive a similar decomposition to (3) for these spaces. Obviously, if
u ∈ Ker(curl)
then
Proposition 4.6
(L2 )3 . Then
.n u ∈ Hcurl
if and only if
u ∈ (H n )3 .
Let Ker(curl)⊥ denote the orthogonal complement of Ker(curl) in .n Hcurl ∩ Ker(curl)⊥ = (H n+1 )3 ∩ Ker(curl)⊥
with equivalent norms. Proof.
Similarly to the proof of Proposition 4.4, consider a function
for which therefore
ξ⊥ˆ u(ξ)
u ∈ Ker(curl)⊥
holds. Using again the equivalent Sobolev norm and the
unitarity of the Fourier transform we can write
||u||H .n ∼ ξ → (1 + |ξ|2 )n/2 |ˆ u(ξ)| 2 + ξ → (1 + |ξ|2 )n/2 |ξ × uˆ(ξ)| 2 = curl
= ξ → (1 + |ξ|2 )n/2 |ˆ u(ξ)| 2 + ξ → |ξ|(1 + |ξ|2 )n/2 |ˆ u(ξ)| 2 ∼ ∼ ξ → (1 + |ξ|2 )(n+1)/2 |ˆ u(ξ)| 2 ∼ ||u||(H n+1 )3 .
u ∈ Ker(curl) ∩ (H n )3 and v ∈ Ker(curl)⊥ ∩ (H n )3 , then they are n 3 respect to the (H ) inner product as well. Indeed, taking partial
Observe that if orthogonal with
derivatives from the functions does not change the direction of the Fourier transform of the function, and thus
F(∂ α u)
points perpendicular to the longitudinal direction. Therefore
0
F(∂ α v) < F(∂ α u), F(∂ α v) >=
points in the longitudinal direction, and
pointwise. We thus get the decomposition
.n = ((H n )3 ∩ Ker(curl)) ⊕ ((H n+1 )3 ∩ Ker(curl)⊥ ) Hcurl
4.3. Fractionalization of the
curl
operator
19
as Hilbert spaces and we can again conclude that
.m .n .s (Hcurl , Hcurl )θ,2 = Hcurl
0 ≤ m < s < n integers with (1 − θ)m + θn = s. We can also extend this scale to any non-integer s by using the above interpolation equation as a denition. By the for any
same interpolation properties as we used in (3), we then obtain the decomposition, now for all
s ≥ 0, .s Hcurl = ((B s,2,2 )3 ∩ Ker(curl)) ⊕ ((B s+1,2,2 )3 ∩ Ker(curl)⊥ ).
4.3. Fractionalization of the
curl
operator
Similarly to the fractional versions of the Laplacian operator, it is possible to fractionalize the
curl
as well through fractionalizing the appropriate operator acting
on the Fourier transform. A natural expectation for these operators to form a semi-
curln operator dened ⊥ earlier. Let u ∈ Ker(curl) ∩ S and examine how the curl operator changes u ˆ at a ⊥ point ξ . Both u ˆ(ξ) and ξ × uˆ(ξ)/i falls in the subspace ξ . In fact ξ × uˆ(ξ)/i = Aˆ u(ξ), group, and also we wish that for integer indices we get back the
where
A = Aξ = |ξ|Rπ/2 = |ξ|
cos(π/2) − sin(π/2) sin(π/2) cos(π/2)
!
ξ ⊥ . Similarly, ξ ×n uˆ(ξ)/in = An uˆ(ξ). The s-th power s s by A = |ξ| Rsπ/2 for any s ≥ 0 and this leads to the
is a linear operator acting on of
A
can be easily dened
denition
curls (u) = F −1 (ξ → is Asξ uˆ(ξ)). This denition can be extended to any integrable, so is
u ∈
⊥ Ker(curl)
∩ (L2 )3 :
since
uˆ
is locally
ξ → is Asξ uˆ(ξ) and therefore we can take its inverse Fourier transform.
In fact this denition extends to any tempered distribution having locally integrable
curls (curlt (u)) = curls+t (u) and we dened curln so that coincides with the n-th power of the curl operator if n is an integer. 2 3 s If u ∈ Ker(curl) ∩ (L ) then we can simply take curl (u) = 0 for s > 0. Then we s 2 3 s t can extend curl to (L ) linearly. It is clear that the properties curl (curl (u)) = Fourier-transform. It is easy to see that
20
4. THE FRACTIONALIZATION OF
curls+t (u)
and
curln = (curl)n
still hold. This extension therefore satises our ex-
pectations and also, it is closely related to the scale of spaces
Proposition 4.7
HCU RL
s Hcurl .
s if and only if curls (u) ∈ (L2 )3 . Let u ∈ (L2 )3 . Then u ∈ Hcurl
This shows that this fractionalization of the
curl could also be used to give another
s equivalent denition of Hcurl quite analogously to the traditional Sobolev spaces.
Proof.
Clearly it is enough to show the claim for
(3), u0 ∈ (B
composition
s,2,2 3
) = (F
s,2,2 3
)
u0 = PKer(curl)⊥ u.
By the de-
, and we can use the equivalent norm of
Proposition 3.17. Therefore,
||u0 ||(L2 )3 + ||u0 ||H s
curl
∼ ||ξ → uˆ0 (ξ)||2 + ξ → (1 + |ξ|2 )s/2 uˆ0 (ξ) 2 ∼
∼ ||ξ → uˆ0 (ξ)||2 + ||ξ → ||ξ|s uˆ0 (ξ)|||2 = = ||ξ → uˆ0 (ξ)||2 + ξ → |is |ξ|s Rsπ/2 uˆ0 (ξ)| 2 = ||u0 ||2 + ||curls (u0 )||2 . Note that this calculation shows that, in fact, if we introduce the norm
||curls (u)||22 )1/2
on
s Hcurl ,
(||u||22 +
we obtain an equivalent Hilbert space.
The analogue of the diagram (1) can be written as
grad
curls
div
s −→ Hdiv −→ (L2 )3 (H 1 )3 −→ Hcurl
for any
s > 0,
and it preserves the property that the image of each operator is
included in the kernel of the next one. Indeed, the kernel of
2 3
curls
is the same for
u ∈ (L )
whose Fourier transform
points in the longitudinal direction almost everywhere.
On the other hand, the
any
s > 0,
kernel of
namely it consists of the functions
div
consists of the functions
2 3
u ∈ (L )
whose Fourier transform points in
perpendicular to longitudinal direction. By denition, all functions of form has this property. inclusion Im(curl
s
However, using the fractional
) ⊂ Ker(div)
curl
curls u
it is easy to show that the
is not of nite codimension.
Set 0 < T ≤ ∞ and let the family of linear operators {C s }s∈(0,T ) acting on the spaces {Vs }s∈(0,T ) such that C s C t is dened and equals to C s+t for all choice of s, t > 0 with s + t < T . Suppose furthermore that Ker(C s ) = Ker(C t ) for Proposition 4.8
4.3. Fractionalization of the
curl
operator
21
all s, t > 0. Then Im(C t ) ⊂ Im(C s ) for all 0 < s < t < T and the inclusions are either strict for every choice of s and t, or are trivial for every choice. C t u = C s (C t−s u). For the second part, it s s is enough to check the actions of C on Vs /Ker(C ), thus we can assume that the t s operators are injectives. Suppose that the inclusion Im(C ) ⊂ Im(C ) is srtict for a xed 0 < s < t. For any r > q > t x m such that (t − s)/m ≤ r − q . At least for s+j(t−s)/m one j ∈ {1, 2, . . . , m} one of the inclusions Im(C ) ⊂ Im(C s+(j−1)(t−s)/m ) is s+(j−1)(t−s)/m strict, that is, there is a v such that v = C u, but there is no such w that v = C s+j(t−s)/m w. Consequently there is no such w that v = C s+(j−1)(t−s)/m+(r−q) w 0 q−(s+(j−1)(t−s)/m) either. Thus v = C v equals to C q u, but doesnt equal to C r w for any w, and thus Im(C r ) ⊂ Im(C q ). We can conclude that there exists an s0 such that the inclusion of images is trivial if both indices are smaller than s0 , and strict if both s 2s s s indices are larger than s0 . On the other hand, if Im(C ) = Im(C ) = Im(C C ) for s s ms a xed s, then C maps Im(C ) onto itself, therefore Im(C ) = Im(C ns ) for any n, m integers. Hence s0 can be only 0 or T , which proves the statement. Proof.
The rst part is trivial from
It now suces to nd an
u ∈ Im(curl)\ Im(curl2 ), and then the Proposition yields
that all the intermediate inclusions in
Im(curl
s
n
) ⊂ Im(curls/2 ) ⊂ · · · ⊂ Im(curls/2 ) ⊂ · · · ⊂ Ker(div)
are strict, therefore the codimension of Im(curl
s
) in Ker(div) is innite. Consider −1 the function v = F (ξ → χ|ξ| + < curl∗s (u), v2 > for all
(4)
s 2 n 3 u ∈ Hcurl where the latter inner products are understood in the (L (R )) sense,
24
4. THE FRACTIONALIZATION OF
and
vj = v|Qj
for
j = 1, 2.
HCU RL
Tf for the regular distribution for R P3 Tf (φ) = j=1 fj φj . Consider the
Let us use the notation
any given locally integrable function
f.
That is,
distribution
T = Tv1 + curls (Tv2 ). We now show that
Tv1 (φ) =< φ, v1 >,
T
s Hcurl
is extended to
by
L.
(5)
Taking
φ ∈ S,
we clearly have
and
s
s
curl (Tv2 )(φ) = F(curl (Tv2 )(F
−1
3 X (Rsπ/2 vˆ2 )j (ξ)φˆj (−ξ) = i |ξ|
Z
s
(φ)) =
s
j=1
Z =
s
s
T
i |ξ| vˆ2 (ξ)
T ˆ Rsπ/2 φ(−ξ)
Z =
s
s
i |ξ|
3 X
T ˆ j (−ξ) = (ˆ v2 )j (ξ)(Rsπ/2 φ)
j=1
= F(v2 )(F −1 (curl∗s (φ)) =< curl∗s (φ), v2 > . Comparing this with (4), we get
T (φ) = L(φ),
so
L
indeed extends
T.
T is of the form (5), we need to show that it has a unique s 2 3 s extension to Hcurl . Since S is dense in (L ) , which is dense in Hcurl , for any xed ∞ s we can nd a sequence {φn }n=1 ⊂ S converging to it. We can write u ∈ Hcurl On the other hand, if
|T (φk ) − T (φl )| ≤ | < φk − φl , v1 > | + | < curl∗s (φk − φl ), v2 > | ≤ ≤ ||φk − φl ||2 ||v1 ||2 + ||curls (φk − φl )||2 ||v2 ||2 ≤ ||φk − φl ||H s
curl
||v||L2 (V ) .
{T (φn )} is a Cauchy sequence in C and so converges to a limit that we can denote by L(u) since it is clear that we obtain the same limit to any other sequence {ψn } ⊂ S converging to u. The functional L is linear and also bounded, since Thus
|L(u)| = lim |T (φn )| ≤ lim ||φn ||H s n→∞
n→∞
We can now extend the scale
s Hcurl
curl
||v||L2 (V ) = ||u||H s
curl
||v||L2 (V ) .
to negative indices in a natural way, while also
ensuring the expectations for duality. Let
A
denote the subspace of
S0
with distri-
butions whose Fourier transform is locally integrable and its longitudinal component is in
(L2 )3 .
For any
s∈R
set
As = A ∩ {u ∈ S 0 |curls (u) ∈ (L2 )3 }.
4.4. Non-positive indices
Proposition 4.10
25
The scale s Hcurl
(L2 )3 ∩ A s = (L2 )3 + A
s
if s ≥ 0 if s ≤ 0
−s s )0 = Hcurl coincides with the initial denition (2) for s ≥ 0 and has the property (Hcurl .
Proof.
The rst claim is simply a rephrasing of Proposition 4.7. The only dierence
is the intersection with for
s ≥ 0.
A
s ⊂ (L2 )3 ⊂ A Hcurl the case s ≤ 0 follows
which does not change our space since
The second part is Proposition 4.9 for
from the reexivity of Hilbert spaces.
s ≥ 0,
while
26
REFERENCES
References [1] R. A. Adams, J. J. F. Fournier,
Sobolev Spaces, Second Edition,
Academic Press,
Amsterdam (2003) [2] J. Bergh, J. Löfström,
Interpolation Spaces, an Introduction,
Springer-Verlag,
Berlin-New York (1976) [3] N. Engheta, Fractional curl operator in electromagnetics,
Lett., 17: [4] P. Monk,
Microw. Opt. Technol.
86-91 (1998)
Finite Element Methods for Maxwell's Equations,
Clarendon Press,
Oxford (2003)
Sobolev Spaces of Fractional Order, Nemytskij Operators, and Nonlinear Partial Dierential Equations, de Gruyter, Berlin (1996)
[5] T. Runst, W. Sickel,
[6] V. S. Rychkov On restrictions and extensions of the Besov and Triebel-Lizorkin spaces with respect to Lipschitz domains,
J. London Math. Soc. (2) 60, 237-257
(1999) [7] Q. Yang Novel analytic and numerical methods for solving fractional dynamical systems, PhD Thesis, Queensland University of Technology (2010)