Digital Differential Protection

Digital Differential Protection G. Ziegler Differential Protection Symposium Belo Horizonte, 7 to 9 Nov. 2005 No.: 1 Differential Protection: Dis...
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Digital Differential Protection G. Ziegler

Differential Protection Symposium

Belo Horizonte, 7 to 9 Nov. 2005

No.: 1

Differential Protection: Discussion Subjects Ø

Mode of operation

Ø

Measuring technique

Ø

Current transformers

Ø

Communications

Ø

Generator and motor differential protection

Ø

Transformer differential protection

Ø

Line differential protection

Ø

Busbar differential protection

Differential Protection Symposium

Belo Horizonte, 7 to 9 Nov. 2005

No.: 2

Digital Differential Protection Principles and Application Gerhard Ziegler

Differential Protection Symposium

Belo Horizonte November 2005

G. Ziegler, 10/2005

page 1

Contents Pages Mode of operation

3 - 27

Measuring technique

28 - 45

Current transformers

46 - 86

Communications

87 - 115

Generator and motor differential protection

116 - 122

Transformer differential protection

123 - 178

Line differential protection

179 - 216

Busbar differential protection

217 - 247

7UT6 product features

248 - 264

Differential Protection Symposium

Belo Horizonte November 2005

G. Ziegler, 10/2005

page 2

Digital Differential Protection Mode of operation Gerhard Ziegler

Differential Protection Symposium

Belo Horizonte November 2005

G. Ziegler, 10/2005

page 3

Comparison protection - Principles Absolute selectivity by using communications IA

IB B

A

Exchange of YES / NO signals (fault forward / reverse)

protection range reverse

forward

Relay

forward

communication

reverse

• Current comparison | ∆I |

Relay

Sampled values Phasors Binary decisions

t

•Directional comparison

IA

IB

•comparison of momentary values or phasors B

• | ∆I | = | IA - IB | > limiting value

A Differential Protection Symposium

Belo Horizonte November 2005

G. Ziegler, 10/2005

page 4

Protection Criterion “current difference“ (differential protection) n Kirchhoff‘s law: II1 + I2 + I3 + ... InI= Idiff = 0;

Current difference indicates fault

n Security by through-current dependent restraint

|I1|+|I2|+ ... |In| = IRes

protection object

n Characteristic:

Idiff Trip Ires n Absolute zone selectivity (limits: CT locations)

No “back-up“ for external faults n Differential protection: for generators, motors, transformers, lines and busbars

Differential Protection Symposium

Belo Horizonte November 2005

G. Ziegler, 10/2005

page 5

Current differential protection: Basic principle

I1 i1

I2 Protection object

i2 ∆I>

∆I=I1 + I2 =0

external fault or load

Differential Protection Symposium

I1

I2

Protection object

i1

i2 i1

∆I>

∆I=I1 + I2

i2

internal fault

Belo Horizonte November 2005

G. Ziegler, 10/2005

page 6

Differential protection: Connection circuit Traditional technique

Digital technique

L1

L1

L2 L3

L2 L3

∆I

∆I

∆I

Galvanically connected circuits must only be earthed once!

Different CT ratios need to be adapted by auxiliary CTs!

Differential Protection Symposium

∆I

CT circuits of digital relays are segregated and must each be earthed !

Digital relays have integrated numerical ratio adaptation !

Belo Horizonte November 2005

G. Ziegler, 10/2005

page 7

Generator and transformer differential protection

L1 L2 L3

L1 L2 L3

∆I

∆I

∆I

Differential Protection Symposium

Yd5

Matching transformer

Belo Horizonte November 2005

∆I

∆I

∆I

G. Ziegler, 10/2005

page 8

Transformer differential protection

Yd5 L1 L2 L3

Matching transformer

Differential Protection Symposium

∆I

∆I

∆I

Belo Horizonte November 2005

G. Ziegler, 10/2005

page 9

Current transformer: Principle, transformation ratio, polarity

i1

i2

i1 w1

u1 i2

1 Φ

u2

i1 ⋅ w1 = i2 ⋅ w2

Function principle i1

u2

u1 u 2 = w1 w2

2

w2

u1

Polarity marks

P1

P2

i2 i1

u1

i2

u2 S1 Equivalent electrical circuit

Differential Protection Symposium

S2

Designation of CT terminals according to IEC 60044-1

Belo Horizonte November 2005

G. Ziegler, 10/2005

page 10

Busbar differential protection Digital protection 7SS52

Analog protection 7SS10/11/13 7SS600 with digital measuring relay (∆I)

∆I Central Unit 2

4

3

Optic fibres

0

∆I

BU

BU

BU

BU

0

G

M Grid infeed

BU: bay unit

G

Load

Differential Protection Symposium

M Grid infeed

Belo Horizonte November 2005

Load

G. Ziegler, 10/2005

page 11

Line differential protection

50/60 Hz current comparison through wire connection I1

Phasor with digital communication via OF, microwave or pilot wires I1

I2 I2

∆I

DI

∆I

∆I

∆I

I1

I2

dedicated O.F. up to about 35 km Other services

PCM MUX

PCM MUX

Other services

O.F. or Microwave

Differential Protection Symposium

Belo Horizonte November 2005

G. Ziegler, 10/2005

page 12

Two wire (pilot wire) line differential protection Voltage comparison principle I2

I1

Grid

G ∆I

RS

U1

∆U

∆I

U2

RS

3

3

∆I

Differential Protection Symposium

∆I

Belo Horizonte November 2005

G. Ziegler, 10/2005

page 13

False differential currents during load or external faults

I∆ / In te

ri st ic

4

ac

∆IGF = total false current

re

la

y

ch

ar

3 2

∆IWF = CT false current ∆IAF = Inaccurate adaptation (CT ratios, tap changer)

1

∆IWF = Transformer magnetising current

1

10

Differential Protection Symposium

15

ID / In

Belo Horizonte November 2005

G. Ziegler, 10/2005

page 14

Percentage differential relay

A = I1− I2 operate stabilise

B S = I1+ I2

I1 Basicpick-up value (B) I2 I1+ I2

Differential Protection Symposium

Belo Horizonte November 2005

G. Ziegler, 10/2005

page 15

Differential protection: analog measuring circuit Rectifier bridge comparator with moving coil relay

I2

I1 protection object

i1

Fault characteristic (single side infeed)

i2

ΔI =

W2

W1 W3

k1 ⋅ I Re s

k1 ⋅ I Re s

I1 − I 2

Relay characteristic

W1

k 2 ⋅ I Op

= k1 ⋅ (I 1 − I 2 ) k1 =

I1 + I 2 > k ⋅ I1 − I 2

W4

w1 w2

Differential Protection Symposium

k=

k2 ⋅ I Op

Σ I = I1 + I 2

= k2 ⋅ (I1 + I 2 ) k2 =

w3 w4

k1 k2

with digital relays: ΣI = I1 + I 2

Belo Horizonte November 2005

G. Ziegler, 10/2005

page 16

Multi-end differential protection: Analog measuring principle

1

n

2

Iop = I1 + I 2 + .... + I n = Σ I

Differential Protection Symposium

k ⋅ I Re s

I Op

I Res = I1 + I 2 + .... + I n = Σ I

Belo Horizonte November 2005

G. Ziegler, 10/2005

page 17

Optimised relay characteristic

G R 2000A

Ideal fault characteristic

∆Ι

IOp = I1 − I 2

internal fault

300A

F

Load RL

IOp = 2000 A

relay characteristic

IS = 2600 A

I F1

I F2

G

G

CT saturation

∆Ι I Res = I1 + I 2

Healthy protection object

δ I Op = 2 ⋅ I F ⋅ cos

Differential Protection Symposium

I Re s = 2 ⋅ I F

δ 2

Belo Horizonte November 2005

G. Ziegler, 10/2005

page 18

Digital differential protection: Relay characteristic IOp Positive current polarity k2 ∆I

k1

Id > IR0

I Op = ΣI = I1 + I 2

Settings:

I Res = Σ I = I1 + I 2

• slope k1

IRes

• Pick-up value Id >

• slope k2 with footing point IR0

Differential Protection Symposium

Belo Horizonte November 2005

G. Ziegler, 10/2005

page 19

∆I / ΣI und I1 / I2 diagram ΔI = I1 + I 2

I1 Internal faults IS0 1+ k + ⋅B 2 2⋅k

k [% / 100 ] slope

B

IS0

IS0 1− k ⋅B + 2 2⋅k

Σ I = I1 + I 2

(

1

I1 + I 2 > k I1 + I 2 − I S 0

2

I1 + I 2 > B

Differential Protection Symposium

)

IS0 2

Belo Horizonte November 2005

G. Ziegler, 10/2005

page 20

I2

Polar diagram of differential protection I1 + I 2 > k ⋅ I1 − I 2

β-Plane (remote/local current)

I 1+ 2 1+β I1 > k or >k I2 1- β 1− I1

I  Im  2  I1 

I β= 2 I1

I2 Protection object ∆Ι

I with β = 2 I1 −

I1

1+ k 1− k

+1

-1 (k=0,5)



1− k 1+ k

I  Re 2   I1 

Restraint area

Differential Protection Symposium

Belo Horizonte November 2005

G. Ziegler, 10/2005

page 21

Polar diagram of digital differential protection: Basic pick-up value B > 0

90

I 2 jϕ e I1

120

I1 + I 2 > k ⋅ ( I1 + I 2 ) + B or  I2 > k ⋅ 1 + 1+  I1 

I2 I1

 B +  I 1 

60

ϕ

150

30

180

0 5

210

10

330

300

240 270 B/I1= 0,3

a1(Φ): k=0,3 a2(Φ): k=0,6 a3(Φ): k=0,8

Differential Protection Symposium

Belo Horizonte November 2005

G. Ziegler, 10/2005

page 22

Mixing transformer of composed current differential protection

IL1

IL2

IL3 IL1

Composed current during symmetrical 3-ph fault or load

IM

2

IL3

7SD503: IM = 100 mA 7SS600: IM = 100 mA 7SD502: IM = 20 mA

1

IE 3 Mixing transformer

IM =

IL3

1 ⋅ 3 ⋅ I Ph −3 w

2 ·IL1

IL3

IL1

I M = 2 ⋅ I L1 + 1 ⋅ I L3 + 3 ⋅ I E IL3

IL2

Differential Protection Symposium

= 5 ⋅ I L1 + 3 ⋅ I L2 + 4 ⋅ I L3 ⇒ composed current (vector sum) Belo Horizonte November 2005

G. Ziegler, 10/2005

page 23

Mixing transformer: Pickup sensitivity of standard connection (IM= 2IL1+IL3+3IE )

Fault type

Per unit composed current related to 3-phase symmetrical current

Composed current

L1-E

IML1-E = 5 IL1

IL2 = IL3 = 0

IML1-E / IM = 5 / √ 3 = 2.9

L2-E

IML2-E = 3 IL2

IL1 = IL3 = 0

IML2-E / IM = 3 / √3 = 1.73

L3-E

IML3-E = 4 IL3

IL1 = IL2 = 0

IML3-E / IM = 4 / √3 = 2.3

L1-L2

IML12 = 5 I L1 + 3 I L2

IL3 = 0

IML12 / IM = 2 / √3 = 1.15

L2-L3

IML23 = 3 I L2 + 4 I L3

IL1 = 0

IML23 / IM = 1 / √3 = 0.58

L1-L3

IML13 = 5 I L1 + 4 I L3

IL2 = 0

IML13 / IM = 1 / √3 = 0.58

L1-L2-L3

IML123 = 5 IL1 + 3IL2 + 4IL3

|IL1| = |I L2| = |I L3|

IML123 / IM = √3 / √3 = 1

Differential Protection Symposium

Belo Horizonte November 2005

Highest sensitivity

G. Ziegler, 10/2005

page 24

Composed current differential protection Behaviour during cross country fault (isolated/compensated network) ∆I

A

B L1 L2 L3

IF

L1 internal und L3 external: IM-A= 5⋅IF - 4⋅IF = 1⋅IF und IM-B= + 4⋅IF ∆I = |IM-A + IM-B| = 5IF und ΣI = |IM-A| + |IM-B| = 5⋅IF ∆I/ΣI = 5/5 = 1.0

Tripping

L2 internal, L3 external IM-A= - 1⋅IF und IM-B= + 4⋅IF ∆I = |IM-A + IM-B| = 3 ⋅IF und ΣI = |IM-A| + |IM-B| = 5⋅IF ∆I/ΣI = 3/5 = 0.6

Tripping if k-setting < 0.6

Differential Protection Symposium

Belo Horizonte November 2005

G. Ziegler, 10/2005

page 25

Composed current differential protection Through current stabilisation with unsymmetrical earthing conditions

2

1

3

3

2

IM2=2·IL1 + 1·IL3+ 3 ·IE =2·IF + 1 ·IF+ 3·3IF = +12 ·IF

IM1=2·IL1 + 1·IL3 + 3 ·IE =2 ·(–IF) + 1 ·(–IF) + 3·0= –3·IF IOp=| IM1 + IM2 | = 9 ·IF IRes=|IM1| +|IM2| = 15 ·IF

1

k=9/15 = 0.6

IOp

Fault L2-E

k=0.5

Faults in other phases: Fault L1-E: IOp = (3+12) ·IF = 15 ·IF, IRes= (3+12) ·IF = 15 ·IF,

k=1

Fault L3-E: IOp = (0+12) ·IF = 12 ·IF, IRes= (0+12) ·IF = 12 ·IF,

k=1

Differential Protection Symposium

IRes Belo Horizonte November 2005

G. Ziegler, 10/2005

page 26

High impedance differential protection: Principle Behaviour during external fault with CT saturation

with ideal current transformers

ISC

RCT

RCT

ISC

ISC

ISC

UR

ECT −1 = (RL + RCT ) ⋅ iSC

ECT −1 = 2 ⋅ (RL + RCT ) ⋅ iSC

UR = 0 ECT −2 = (RL + RCT ) ⋅ iSC

Differential Protection Symposium

U R = (RL + RCT ) ⋅ iSC

Belo Horizonte November 2005

G. Ziegler, 10/2005

page 27

High impedance differential protection: Calculation example (busbar protection)

Given:

n = 8 feeders rCT = 600/1 A UKN = 500 V RCT = 4 Ohm ImR = 30 mA (at relay pick-up value)

Pick-up sensitivity:

(

600 ⋅ (0.02 + 0.05 + 8 ⋅ 0.03) 1

I F − min = 186 A ⋅ (31% )

Differential Protection Symposium

RR = 10 kOhm Ivar = 50 mA (at relay pick-up value)

Stability:

I F −min = rCT ⋅ I R − pick −up + IVar + n ⋅ I mR

I F − min =

RL= 3 Ohm (max.) IR-pick-up.= 20 mA (fixed value)

)

I F −through − max < rCT ⋅

I F −throuh − max


9 10

0

1

6

trip

7 8

restrain

9

0 10

18O = 1 ms (50 Hz) = 0.67 ms (60 Hz)

ΣI

IA

IB

∆I

∆I

Operating quantity :

∆I = I A + I B

Restraining quantity : ΣI = I A + I B Differential Protection Symposium

Belo Horizonte November 2005

G. Ziegler, 10/2005

page 35

Discrete Fourier-Transformation (Principle) sin 2π ⋅i n 0 1 2 . .

i( k −n+i )

.

Correlate: Multiply samples and add for one cycle n

Correlate IS(k)

i k-n

I (k) = I S(k) + j ⋅ I C(k) k

Correlate IC(k)

I (k )

j

IC(k)

cos 2π ⋅i n

Differential Protection Symposium

Belo Horizonte November 2005

ϕ IS(k)

G. Ziegler, 10/2005

page 36

Discrete Fourier-Transformation (calculation formulae) i 0

i1 i2 i 3 iN ∆t

N

  I = 2  ∑ sin(ω ⋅n⋅ Δt )⋅in S N  n=1 

N

i  i N-1 I = 2  O + N + ∑ cos(ω ⋅n ⋅ Δt)⋅in C N  2 2 n=1 

N-1

0 1 2 3 .... n

0 1 2 3 ...

Differential Protection Symposium

Belo Horizonte November 2005

G. Ziegler, 10/2005

page 37

Orthogonal components of a current phasor dependent on the position of the data window Data window

Φ = ωt IS =

Φ 1 ⋅ ∫ I (ω ⋅ t ) ⋅ sin ωt ⋅ dt 2π Φ −360

IC =

Φ 1 ⋅ ∫ I (ω ⋅ t ) ⋅ cos ωt ⋅ dt 2π Φ −360

I Φ = I S + j ⋅ IC I0 = 1+ j ⋅ 0 I

O

O

O

I30 3 1 = + j⋅ I 2 2 O

I 60 1 3 = + j⋅ I 2 2 O

jIC

I IS

ωt t=0

I90 = 0 + j ⋅1 I O

Differential Protection Symposium

Belo Horizonte November 2005

G. Ziegler, 10/2005

page 38

Transfer function of a one cycle Fourier-filter Hrel 1,0 0,75 0,5 0,25 0 0

1

Differential Protection Symposium

2

3

4

5

6

f/fn

Belo Horizonte November 2005

G. Ziegler, 10/2005

page 39

Digital protection Fast current phasor estimation N

k-N

i(t)

k

Data window i(t) = A ⋅ sin( ωt ) +

Task: Method:

Delta =

 t  −   B ⋅  cos( ωt) - e τ  + C ⋅ cos( ωt)      

Estimation of the coefficients A, B, C on basis of measured currents and voltages Gauß‘s Minimization of error squares: Delta = quality value k = sampling number k N = length of data window 2 ∑ i(n ⋅ ∆T) - f (n) MIN n = variable n=k-N ∆T = sampling interval sampled values

(

)

Differential Protection Symposium

Belo Horizonte November 2005

G. Ziegler, 10/2005

page 40

Differential protection with phasors (principle) A

∆I

B

IAC , IAS IBC , IBS

∆I

∆I

trip

∆I>

restraint

j·IAS

ΣI Operating quantity :

∆I = I A + I B

Restrainin g quantity : Σ I = I A + I B

IBC IAC j·IBS

Differential Protection Symposium

Belo Horizonte November 2005

G. Ziegler, 10/2005

page 41

Digital line differential protection Synchronisation of phasors (ping-pong time alignment) A

tA1 tA2

∆I

∆I

curre n phas t o rs

α ...

tPT1

tAR

tA5

tA1

tPT2 tV tB3 tA1

tBR

tB2

α=

tB3 nt curre . . . rs ph aso

Differential Protection Symposium

t B3 - t A3 ⋅ 360 ° TP

tB4

Signal transmission time: t PT1 = t PT2 = Sampling instant:

IB( tB3 )

tB1 tD

tA3 tA4

IB( tA3 )

B

1 (t A1 - t AR - t D ) 2

t B3 = t A3 - t PT2

Belo Horizonte November 2005

G. Ziegler, 10/2005

page 42

Split path data transmission Impact of unsymmetrical propagation time I1

I2

∆I

∆I

180o ∆T[ms ]⋅ α 10ms ∆I = I ⋅ sin = I ⋅ sin 2 2

α I2 I1

Example: Transmit channel time 3 ms Receive channel time 4.2 ms → time difference ∆ = 1.2 ms

180o 1.2ms ⋅ 10ms = I ⋅ 0.19 ∆I = I ⋅ sin 2

∆I α/2

∆I = 19%!

To keep the false differential current below about 2 to 5%, the propagation time difference should not exceed about 0.1 to 0.25 ms! Otherwise: → more insensitive relay setting → or GPS synchronisation Differential Protection Symposium

Belo Horizonte November 2005

G. Ziegler, 10/2005

page 43

Synchronisation of Differential relays via GPS Line end 1

Line end 2

GPS-Antenna RS232

GPS-Antenna GPS

RS232

UH

DC GPS-Empfänger supply DCF-SIM A B LWL LWL IRIG-B 24V

GPS

GPS-Empfänger Hopf DC supply DCF-SIM A B LWL LWL IRIG-B 24V

IRIG-B Telegram Sec. impulse (highly accurate)

LWL K1

LWL

BE2

K2

IRIG-B Telegram Sec. impulse (highly accurate)

LWL

K2

K1

7XV5654 Sync-Trans. K1 X1 K2 K2

LWL

BE2

K2

K2

7XV5654 Sync-Trans. K1 X1 K2 K2

+ - 24V + 1 3 8 4

+ - 24V + 1 3 8 4

Y-cable 7XV5105

1 3 8 4

RUN

7SD52

SIEMENS

ERR OR

L1 402,1A L2 402,1A L3 402,1A E 00.0A

to max.

Differential Protection Symposium

SIEMENS

ERR OR

L1 402,1A L2 402,1A L3 402,1A E 00.0A

7SD52

6

V4

SIPROTEC RUN

Max450.1A Max450.1A Max450.1A

Anr. L1 Anr. L2 Anr. L3 Anr. Erde Automat

1 3 8 4

V4

SIPROTEC

RUN

Max450.1A Max450.1A Max450.1A

Anr. L1 Anr. L2 Anr. L3 Anr. Erde Automat

1

1 3 8 4

V4

SIPROTEC

L1 402,1A L2 402,1A L3 402,1A E 00.0A

Y-cable 7XV5105

1 3 8 4

V4 SIEMENS

UH

SIEMENS

ERR OR

SIPROTEC

RUN

Max450.1A Max450.1A Max450.1A

L1 402,1A L2 402,1A L3 402,1A E 00.0A

Anr. L1 Anr. L2 Anr. L3 Anr. Erde Automat

ERR OR Max450.1A Max450.1A Max450.1A

Anr. L1 Anr. L2 Anr. L3 Anr. Erde Automat

1

t0 max.

Belo Horizonte November 2005

6

G. Ziegler, 10/2005

page 44

Devices for GPS time synchronisation n GPS receiver with 2 optical outputs (7XV5664-0AA00). Output for IRIB-B telegram and output for second/ minute pulse n Galvanic separation between the receiver and the tranceiver 7XV5654 n Optic/electric signal conversion in the tranceiver n Distribution of the electrical signals via Y-bus cable to port A of the relays (telegram) n Electronic contact for the minute pulse in case of synchronisation through binary input with battery voltage

Differential Protection Symposium

Outdoor antenna FG4490G10 for GPS

GPS receiver 7XV5664 Tranceiver 7XV5654 Belo Horizonte November 2005

G. Ziegler, 10/2005

page 45

Additional components for SICAM SAS GPS-System

• • • •

Differential Protection Symposium

24 satellites move in a height of 20 000km on 6 different paths Transmission frequency 1,57542GHz For a continuous time reception min. 4 satellites is necessary High accuracy : 1 usec

Belo Horizonte November 2005

G. Ziegler, 10/2005

page 46

Operating characteristic of digital differential relays

I∆ =|I1+ I2|

I1

I2

b%

∆I

I∆>

a%

I∑ b

Differential Protection Symposium

I∑ = |I1|+ |I2|

Belo Horizonte November 2005

G. Ziegler, 10/2005

page 47

Differential protection CT saturation with internal and external faults ∆I Protection object

I2

I1 Internal fault

External fault

I1 I2 Σ I= |I1| + |I2| ∆I=|I1 +I2| t=0

t=10

Differential Protection Symposium

t=20 ms

t=0

t=10

t=20 ms

Belo Horizonte November 2005

G. Ziegler, 10/2005

page 48

Saturation detector:

Locus of ∆I/ΣI for external faults without and with CT saturation

i Op( n ) = i1( n ) + i 2( n ) 6' 7'

saturation

3'

re s

i 2( n )

in tra

n

8'

External fault

5' 4' with CT

i1( n )

e rat e op

i1( n ) + i 2( n )

9'

0 10

External fault (ideal CTs)

1

2

3

4 5

9

8

7

6

i Re s ( n ) = i1(n ) + i 2( n )

Differential Protection Symposium

i1(n ) + i 2( n )

n=0

n=10

Belo Horizonte November 2005

n=20

G. Ziegler, 10/2005

page 49

Differential current caused by transient CT saturation (ext. fault) with operating and restraint current of busbar protection 7SS5 I1 100

50

I2

0

50

IRes.= |I1| + |I2|

IOp=|I1 +I2|

Differential current appears only every second half wave!

Differential Protection Symposium

Belo Horizonte November 2005

G. Ziegler, 10/2005

page 50

Tripping logic of digital busbar protection 7SS600/7SS5 with saturation detector (simplified) di Re s > k s [A / ms] dt

i Op > iset i Op > k ⋅ i Re s

A N D

A N D

A N D

3 ms A N D

Transient blocking

Differential Protection Symposium

1-out-of-1

2 150 ms

Saturation detected

3 ms

Trip

n=2

Adaptive restraint

A N D

O R

Trip

2-out-of-2 Trip

Belo Horizonte November 2005

G. Ziegler, 10/2005

page 51

Transformer differential protection 7UT6: Saturation detection and automatic increase stabilisation

Internal faults

Trip

Restrain

Area of add-on restraint

Differential Protection Symposium

Belo Horizonte November 2005

G. Ziegler, 10/2005

page 52

Transient CT saturation causes false differential currents

IF

IF

+I1

+I2

87

I1

IF

I2

+∆I

∆I

Wave shape similar to transformer inrush current ?

Differential Protection Symposium

Belo Horizonte November 2005

G. Ziegler, 10/2005

page 53

Adaptive restraint against CT errors (7SD52/61) Detection of CT saturation (wave shape analysis)

CT Error approximation (no-saturation)

Error %

Load range

Fault range

fL

fF 10%

ALF‘/ALFN • IN-CT

Differential Protection Symposium

ALF’ •IN-CT

Belo Horizonte November 2005

G. Ziegler, 10/2005

page 54

Adaptive 87 restraint (7SD52/61) considers current CT- errors IDiff

I1

Trip Area

Trip level With saturation Block-Area

IDiff> 0 0 Current summation:

Trip level Without saturation

I2

External Fault

I2

I1

Max. error (ε) without saturation

IDiff = │I1+ I2│

Max. error (ε) with saturation.

IRest

Max. error summation: IRestraint = ΣIError = IDiff> + εCT1 ·I1 + fSat· εCT2 ·I2

Differential Protection Symposium

Belo Horizonte November 2005

G. Ziegler, 10/2005

page 55

External fault Increase of stabilisation after detection of saturation Begin of saturation ∆Ι

(K1:iE = -K1:iL1)

Increase of restraint

I∆

IRestraint

ΣΙ Differential Protection Symposium

Belo Horizonte November 2005

G. Ziegler, 10/2005

page 56

Fast charge comparison supplement speeds up phasor based line differential protection (7SD52/61) Q2

Q1

iL1/kA 20 10 0 -10

-0,02

-0,01

-0,00

0,01

0,02

0,03

0,04

0,05

0,06

0,07

0,08

-0,02

-0,01

-0,00

0,01

0,02

0,03

0,04

0,05

0,06

0,07

0,08

-0,02

-0,01

-0,00

0,01

0,02

0,03

0,04

0,05

0,06

0,07

0,08

t/s

-0,02

-0,01

-0,00

0,01

0,02

0,03

0,04

0,05

0,06

0,07

0,08

t/s

t/s

-20 -30 -40

iL2/kA 20 10 0 -10

Q3

t/s

-20 -30 -40

iL3/kA 20 10 0 -10 -20 -30

Diff G-AUS

Q 1/4 cycle

1 cycle data windows for phasor comparison •Synchronized with fault inception ¼ cycle data windows of fast charge comparison

Differential Protection Symposium

•Released by Idiff >>

Belo Horizonte November 2005

G. Ziegler, 10/2005

page 57

Generator, Motor and Transformer protection: Adaptive algorithms to upgrade relay stability and dependability with CT saturation (7UT6) Measured value processing i1L i2L

Side 1 Side 2

Sampled momentary values iRes = | i1 | + | i2 | iOp = i1 + i2

Mean values IRes = Mean(iRes) Fundamental wave IOp = RMS(iDiff)60Hz

87 algorithm Operating characteristic IOp

IDiff>

IRes.

Motor start DC component

&

Trip IOp>

Saturation detector

For security:

Harmonic Analysis: -2nd Harmon. Blocking -Cross Blocking

Adaptive restraint

IOp IDiff> >

For dependability: Fast tripping using sampled momentary values ensures fast operation with very high currents before extreme CT saturation occurs!

Differential Protection Symposium

iOp

≥1

Trip IOp>>

IDiff>>>

Belo Horizonte November 2005

G. Ziegler, 10/2005

page 58

Current Transformers for Differential Relaying Requirements and Dimensioning Gerhard Ziegler

Differential Protection Symposium

Belo Horizonte November 2005

G. Ziegler, 10/2005

page 46

Equivalent current transformer circuit I2′ = I1 ⋅ I1

jX1 R1

N1 N2

Im

P1 N1

P2

jX2

N2 U2

Ideal transformer

R2

I2 S1

Zm

Zb

S2

X1 = Primary leakage reactance R1 = Primary winding resistance X2 = Secondary leakage reactance Z0 = Magnetising impedance R2 = Secondary winding resistance Zb = Secondary load Note:

Normally the leakage fluxes X 1 and X2 can be neglected

Differential Protection Symposium

Belo Horizonte November 2005

G. Ziegler, 10/2005

page 47

Current transformer: Phase displacement (δ) and current ratio error (ε) w1 . I1 w 2

w1:w2 j·X2

R2 U2

I2

I1

ZB

ε

I2 δ

I‘1=

w1 ·I w2 1

Im

I2

Em

I1 Em

R2

U2

RB

Xm

Differential Protection Symposium

Im

Im

Belo Horizonte November 2005

G. Ziegler, 10/2005

page 48

Dimensioning of CTs for differential protection Pi = I sec .2 × R CT

CT classes to IEC 60044-1: 5P or 10P Specification:

300/1 A

5P10, 30 VA RCT ≤ 5 Ohm Rated burden (nominal power) PN

Ratio In -Prim / In -Sek. 5% accuracy at I= n x In Actual accuracy limit factor in operation is higher as the CT is normally under-burdened : Operating ALF: ALF‘

Accuracy limit factor ALF Dimension criterium:

P + PN ALF ' = ALF × i Pi + PB

I ALF ' ≥ SC − max × KTF In

KTF (over-dimensioning factor) considers the single sided CT over-magnetising due to the d.c. component in short circuit current I SC. KTF values required in practice depend on relay type and design. Recommendations are provided by manufacturers (see Application Guide) Differential Protection Symposium

Belo Horizonte November 2005

G. Ziegler, 10/2005

page 49

Current transformer, Standard for steady-state performance

IEC 60044-1 specifies the following classes:

Accuracy class

Current error at nominal current (In)

5P

±1%

10P

± 5%

Differential Protection Symposium

Angle error δ at rated current In

Total error at n x In (rated accuracy limit)

± 60 minutes

5% 10 %

Belo Horizonte November 2005

G. Ziegler, 10/2005

page 50

Current transformers, Standard for transient performance IEC 60044-6 specifies four classes:

Class

Error at rated current Ratio error

TPX (closed iron core)

TPY with anti-remanence air-gap

TPZ linear core

TPS closed iron core

Maximum error at rated accuracy limit

Remanence

Angle error

± 0,5 %

± 30 min

εˆ ≤ 10 %

± 1,0 %

± 30 min

εˆ ≤ 10 %

± 1,0 %

± 180 ± 18 min

εˆ ≤ 10% (a.c. current only)

Special version for high impedance protection (Knee point voltage, internal secondary resistance)

Differential Protection Symposium

Belo Horizonte November 2005

no limit < 10 %

negligible

No limit

G. Ziegler, 10/2005

page 51

Definition of the CT knee-point voltage (BS and IEC)

British Standard BS3938: Class X

U2 10 %

or IEC 60044-1 Amendment 2000/07: Class PX

UKN 50 %

Specify: Knee point voltage Secondary resistance RCT Im

I U KN ≥ K TF ⋅ (R CT + R B − connected ) ⋅ SC − max . I n − CT Differential Protection Symposium

Belo Horizonte November 2005

G. Ziegler, 10/2005

page 52

CT specification according to ANSI C57.13

w1 I‘1= w ·I1 2

I2

Im

Em

ANSI C57.13 specifies:

RCT RB

U2

• Secondary terminal voltage U2 at 20 times rated current (20x5=100 A) and rated burden • Error > ALF‘ > (I>>set / In) Belo Horizonte November 2005

G. Ziegler, 10/2005

page 68

Coordination of CTs and digital relays Summary ü Digital relays use intelligent algorithms and are therefore highly tolerant against CT saturation. ü In particular differential relays allow short time to saturation of ¼ cycle and below. ü Determination of transient dimensioning factors for short time to saturation must consider the real flux course after fault inception. ü With time to saturation < 10 ms, the critical point on wave of fault inception is not close to voltage zero-crossing (fully offset current), but varies and is closer to voltage maximum (a.c. current). ü CT dimensioning is normally based on relay specific Ktd factors provided by manufacturers ü In practice, fully offset s.c. current has been assumed while remanence has been widely neglected for CT dimensioning. ü A new dimensioning factor is discussed in CIGRE WG B5.02, composed of more probable transient and remanence factors. Differential Protection Symposium

Belo Horizonte November 2005

G. Ziegler, 10/2005

page 69

CT dimensioning for differential protection (1) 1. Calculation of fault currents 110/20 kV F1 40 MVA 110 kV, 3 GVA uT=12%

F2

OH-line: l = 8 km, zL‘= 0,4 Ω/km

F3

Net 300/1A

7SD61

7UT61

Impedances related to 20 kV:

Impedances related to 110 kV:

Transf. :

∆ IL

∆ IL

∆ IT

Net :

200/1A

200/1A

1200/1A

F4

U N 2  kV 2    110 2 ZN = = = 4.03 Ω S SC ' ' [MVA ] 3000

Net :

U N 2  kV 2    uT [% ] 110 2 12 % ZT = ⋅ = ⋅ = 36.3 Ω PN -T [MVA ] 100 40 100

Transf. :

U N 2  kV 2    20 2 ZN = = = 0.13 Ω SSC ' ' [MVA ] 3000 U N 2  kV 2    uT [% ] 20 2 12 % ZT= ⋅ = ⋅ = 1.2 Ω PN - T [MVA ] 100 40 100

Line : Z L = l[km ] ⋅ z L ' [Ω/km ] = 8 ⋅ 0,4 = 3,2 Ω

Differential Protection Symposium

Belo Horizonte November 2005

G. Ziegler, 10/2005

page 70

CT dimensioning for differential protection (2)

F1

I F1 =

1.1 ⋅ U N / 3 1.1 ⋅ 110kV/ 3 = = 17.3 kA ZN 4.03 Ω

F2

I F2 =

1.1 ⋅ U N / 3 1,1 ⋅ 110kV/ 3 = = 1.73 kA Z N + ZT 4.03 Ω + 36.3 Ω

F3 I F3 = F4

I F4 =

1.1 ⋅ U N / 3 1.1 ⋅ 20kV/ 3 = = 9.55 kA Z N + ZT 0.13Ω + 1.2Ω

1.1 ⋅ U N / 3 1,1 ⋅ 20kV/ 3 = = 2.8 kA Z N + Z T + Z L 0.13Ω + 1.2Ω + 3.2Ω

Dimensioning of the 110 kV CTs for the transformer differential protection: Manufacturer recommends for relay 7UT61:

1) Saturation free time ≥ 4ms for internal faults 2) Over-dimensioning factor KTF ≥ 1,2 for through flowing currents (external faults)

The saturation free time of 3 ms corresponds to KTF≥ 0,75 See diagram, page 59 Criterion 1) therefore reads:

I 17300 ALF' ≥ K TF ⋅ F1 = 0,75 ⋅ = 43 IN 300

For criterion 2) we get: I 1730 ALF' ≥ K TF ⋅ F2 = 1,2 ⋅ =7 IN 300

The 110 kV CTs must be dimensioned according to criterion 1).

Differential Protection Symposium

Belo Horizonte November 2005

G. Ziegler, 10/2005

page 71

CT dimensioning for differential protection (3) We try to use a CT type: 300/1, 10 VA, 5P?, internal burden 2 VA.

ALF ≥

Pi + Poperation 2 + 2.5 ⋅ ALF ' = ⋅ 43 = 16.1 (Connected burden estimated to about 2.5 VA) Pi + Prated 2 + 10

Chosen, with a security margin : 300 /1 A, 5P20, 10 VA, R2≤ 2 Ohm (Pi ≤ 2VA) Specification of the CTs at the 20 kV side of the transformer: It is good relaying practice to choose the same dimensioning as for the CTs on the 110 kV side: 1200/1, 10 VA, 5P20, R2≤ 2 Ohm (Pi ≤ 2VA) Dimensioning of the 20 kV CTs for line protection: For relay 7SD61, it is required: The saturation free time of 3 ms corresponds to KTF≥ 0.5 See diagram, page 59 Criterion 1‘) therefore reads: I 9550 ALF' ≥ K TF ⋅ F3 = 0.5 ⋅ = 24 IN 200

1‘) Saturation free time ≥ 3ms for internal faults 2‘) Over-dimensioning factor KTF ≥ 1.2 for through flowing currents (external faults)

For criterion 2‘) we get:

I 2800 ALF' ≥ KTF ⋅ F4 = 1.2 ⋅ = 16 .8 IN 200

The 20 kV line CTs must be dimensioned according to criterion 1‘).

Differential Protection Symposium

Belo Horizonte November 2005

G. Ziegler, 10/2005

page 72

CT dimensioning for differential protection (4)

For the 20 kV line we have considered the CT type: 200/5 A, 5 VA, 5P?, internal burden ca. 1 VA

Pi + Poperation 1+1 ⋅ ALF ' = ⋅ 24 = 8 ALF ≥ Pi + Prated 1+ 5

(Connected burden about 1 VA)

Specification of line CTs: We choose the next higher standard accuracy limit factor ALF=10 : Herewith, we can specify: CT Type TPX, 200/5 A, 5 VA, 5P10, R2≤ 0.04 Ohm ( Pi≤ 1 VA)

Differential Protection Symposium

Belo Horizonte November 2005

G. Ziegler, 10/2005

page 73

Interposing CTs, Basic versions

w1

i1

separate winding connection

i2

i1

w2

wa

i2

wb

i1 -i2

Relay

i2 =

w1 ⋅ i1 w2

auto-transformer connection Relay

i2 =

wb ⋅ i1 wa + wb

No galvanic separation!

Differential Protection Symposium

Belo Horizonte November 2005

G. Ziegler, 10/2005

page 74

Interposing CTs, Example

1A W1= 21 turns

600/1 A

1A

600/1 A

Differential Protection Symposium

1,5 A W2= 14 turns

1A

Wa=16 turns

0,5 A

Wb=32 turns

RB

1,5 A

RB

Belo Horizonte November 2005

G. Ziegler, 10/2005

page 75

Interposing CTs in Y-∆-connection

Yd5

-I1c

I1a

I2a-c

I1b

I2b-a I2c-b

I1c

w1

I2a

I1a

-I1b

I2c

I1b I1c

w1 = w2

w2 I1 =

Differential Protection Symposium

150O

I2b I2b

I2c

-I1a I2a

o 1 w ⋅ I 2 ⋅ 2 ⋅ e j ⋅( n⋅30 ) w1 3

Belo Horizonte November 2005

G. Ziegler, 10/2005

page 76

False operation during external fault of transformer differential protection without zero-sequence current filter

L1 L2 L3

∆I

Differential Protection Symposium

∆ I

∆I

∆I>0 without delta winding!

Belo Horizonte November 2005

G. Ziegler, 10/2005

page 77

Zero-sequence current filter

I1a

I3a

I2a

I1b

I3b

I2b

I1c

I3c

I2c

I 1a ⋅ w1 + I 2a ⋅ ww2 + I 3a ⋅ w3 = 0 I 1b ⋅ w1 + I 2b ⋅ ww2 + I 3b ⋅ w3 = 0 I 1c ⋅ w1 + I 2c ⋅ ww2 + I 3c ⋅ w3 = 0 I 3a = I 3b = I 3c I 2a + I 2b + I 2c = 0

Differential Protection Symposium

Relay

I w I +I +I I 3a = I 3b = I 3c = 1 ⋅ 1a 1b 1c = E w3 3 3 I +I +I  w  I 2a = 1  I 1a − 1a 1b 1c   w2  3  I 1a + I 1b + I 1c  w1   I 2b = I −  3 w2  1b  I +I +I  w  I 2c = 1  I 1c − 1a 1b 1c   3 w2   Belo Horizonte November 2005

G. Ziegler, 10/2005

page 78

Biasing of transformer differential protection during external earth fault with zero-sequence current filter (closed delta winding)

L1 L2 L3

With delta winding: ∆I=0 !

Differential Protection Symposium

∆I

∆ I

∆I

Belo Horizonte November 2005

G. Ziegler, 10/2005

page 79

Current matching with interposing CTs (1) Calculation example 110 kV ±16% L1

75 / 1 A

Yd5

6.3 kV

53.9A

915A

1200 / 5 A

L2 L3 0.719A

3.81A

∆I

3,81 = 2,20 3

Differential Protection Symposium

∆I

∆I

In-Relay = 5A

Belo Horizonte November 2005

G. Ziegler, 10/2005

page 80

Current matching with interposing CTs (2) Calculation example Current transformation ratio: We take through flowing rated current as reference: : 110kV-side: Mean current value of upper and lower tap changer position:

I1 =

10,000kVA = 45.2A 3 ⋅ (110kV + 16%

6 kV-side:

I2 =

10,000kVA = 62.5A 3 ⋅ (110kV − 16%

I1' =

I1− mean =

45.2 + 62.5 = 53.9A 2

10.000kVA = 915A 3 ⋅ 6.3kV

The corresponding secondary currents are:

i1 = 53 . 9 ⋅

1 = 0 . 719 A 75

and

i 2 = 915 ⋅

5 = 3.813 1200

. The current in the star connected winding of the interposing transformer is The current in the delta connected winding is:

i.1

i2 / 3 .

The ratio of the interposing CT must be :

w1 i 2 / 3 3.813 / 3 2.202 = = = = 3.06 w2 i1 0.719 0.719

Differential Protection Symposium

Belo Horizonte November 2005

G. Ziegler, 10/2005

page 81

Link selectable interposing CT 4AM5170-7AA

P1

S1

i2

A B C DE

1 0,013

2

F G H I

7

0,025 0,08

S2

P2

i1

K L

M N O P Q

16

1

2

7

16

Windings

0,75

0,013

0,025

0,08

0,75

R in Ohm

2

4

14

32

2

4

14

32

U-max. in V

5

5

5

1

5

5

5

1

Rated current in A

w1 i2 / 3 3,813 / 3 2, 202 = = = = 3.06 w2 i1 0,719 0,719

chosen :

w1 16 + 16 + 2 34 = = = 3,09 w 2 7 + 2 + 1 + 1 11 Connection and links as shown.

Differential Protection Symposium

Belo Horizonte November 2005

G. Ziegler, 10/2005

page 82

Designation of transformer or CT vector groups (1) Clock-wise notation according to IEC 60076-1

11

12 0

1

0

2

10 9

3 8

4 7 6

4 8

0

6

0

6

4

1 0

4

1 0

8

2

8

2

5 9 1 (13)

5

Differential Protection Symposium

Belo Horizonte November 2005

G. Ziegler, 10/2005

page 83

Designation of transformer or CT vector groups (2) Clock-wise notation according to IEC 60076-1, examples

I

II

III

12

I

II

12

III

I

I

III II

III II

HS

I I

II

III

NS

II

12

III

11 12 I III II

I III II I

II

III

Dyn11

12 II

III I 5

Yny0d5

Differential Protection Symposium

Belo Horizonte November 2005

G. Ziegler, 10/2005

page 84

Frequently used vector groups (IEC 60076-1)

Differential Protection Symposium

Belo Horizonte November 2005

G. Ziegler, 10/2005

page 85

Finding the vector group by using the clock principle

Proceed in the following steps: 1. Starting on the high voltage winding, the phase connection terminals are numbered with 0, 4, 8 (always 4 x 30 O= 120O phase shift). 2. The opposite end of each winding is labelled with a number incremented by +6 relative to the phase connection (6x 30 O =180O). 3. The secondary windings are numbered the same. In this context it is assumed that the polarity of the windings is the same in the diagram. (If in doubt, polarity marks may also be applied.) 4. The phase connection is labelled with the average value of the corresponding terminal designations belonging to the winding terminals connected to this phase terminal, e.g. (6+4)/2= 5 5. The difference between the high and low voltage side terminal numbers of same phases corresponds each with the vector group number, being Yd5 in this case.

Differential Protection Symposium

Belo Horizonte November 2005

G. Ziegler, 10/2005

page 86

Checking the connections of transformer differential protection using the clock-wise notation method

Yd5 L1 L2 L3

6

0

10 4 2

0

6

0

6

5

4

10

4

10

9

5 11

8

2

8

2

1

9

3

1

7

8

6

12

6

12 11

10

4 8

10

4 3

2

8 7

2

Yd5

Differential Protection Symposium

∆I

∆I

∆I

Belo Horizonte November 2005

G. Ziegler, 10/2005

page 87

Current distribution in Y-∆-transformer circuits for different external fault types

3

1

3

G

G

G

3 1

Differential Protection Symposium

Belo Horizonte November 2005

G. Ziegler, 10/2005

page 88

Checking the connections of transformer differential protection using the arrow method (two-phase fault)

Yd5

1

3

L1

3

L2 L3 3 3

= 3

3

∆I

∆I

Differential Protection Symposium

∆I

3

Dy5

Belo Horizonte November 2005

G. Ziegler, 10/2005

page 89

Checking the connections of transformer differential protection using the arrow method (single-phase earth fault)

Yd5

1

L1 L2 L3

∆I

∆I

Differential Protection Symposium

∆I

3

Dy5

3

Belo Horizonte November 2005

G. Ziegler, 10/2005

page 90

Digital Differential Protection Communications Gerhard Ziegler

Differential Protection Symposium

Belo Horizonte November 2005

G. Ziegler, 10/2005 page 87

Comparison protection Absolute selectivity by using communication

IA

A

IB

B

• Directial comparison distance protection Exchange of YES/NO signals (e.g. fault forward / reverse) • Current comparison (phasors) differential protection

Protection Relay

Communication samples, phasors, binary signals

| ∆I |

Protection Relay

IA

IB

| ∆I | = | IA - IB | > Ipick-up

Differential Protection Symposium

Belo Horizonte November 2005

G. Ziegler, 10/2005 page 88

Signal transmission channels for differential relaying Pilot wires - AC (50/60 Hz), voice frequency and digital communication (128 - kbit/s) - for short distances (< about 20 km) - influenced by earth short-circuit currents! Optical fibres - wide-band communication (n · 64 kbit/s) - digital signal transmission (PCM) - up to about 150 km without repeater stations - noise proof Digital microwave channels 2 - 10 GHz - wide-band communication (n · 64 kbit/s) - digital signal transmission (PCM) - up to about 50 km (sight connection) - dependent on weather conditions (fading) Differential Protection Symposium

Belo Horizonte November 2005

G. Ziegler, 10/2005 page 89

Analog pilot wire differential relaying

3

3

87L

87L

• Pilot wires are normally operated insulated form earth • Voltage limiters (glow dischargers) connected to earth , as used with telephone lines, are not allowed!

Differential Protection Symposium

Belo Horizonte November 2005

G. Ziegler, 10/2005 page 90

Relay-to-Relay pilot wires communication New technology on existing (copper-) pilots Traditional:

Composed current measurement Comparison of analogue values

Modern:

E

O

O

E

Phase segregated measurement

Digital data transmission 64 kbps bi-directional 4 value digital code (2B1Q) Amplitude and phase modulation Spectrum mid frequency: 80 kHz

Differential Protection Symposium

Belo Horizonte November 2005

G. Ziegler, 10/2005 page 91

Wire pilot cables Longitudinal voltage induced by earth currents Relay B

Relay A

G IF

Φ E

F1

E/2 F2

Differential Protection Symposium

A) Symmetrical coupling along the pilot cable

E/2

F2

F1

E

Belo Horizonte November 2005

B) Unsymmetrical Coupling along the pilot cable

G. Ziegler, 10/2005 page 92

Disturbance voltage caused by rise in station potential

RG STP STP

E Ω = I SC − G ⋅ R G

PGA RGP Legend: RG STP PGA RGP E

station grounding resistance station potential potential gradient area remote ground potential station potential rise against remote ground (ohmic coupled disturbance voltage )

Differential Protection Symposium

Belo Horizonte November 2005

G. Ziegler, 10/2005 page 93

HV insulated protection pilot cable (example) core diameter

pilot resistance Core Loop

pilot capacitance

mm

Ω/km

Ω/km

nF/km

1,4 0,8

11,9 ---

--73,2

--60

test voltage (r.m.s. value) triple pair pair to core- coretriple to core core shield core pair to triple core kV kV kV kV kV 2,5 8 8 8 2 2 2

Symmetry: better 10–3 (60 db) at 800/1000 Hz better 10–4 (80 db) at 50/60 Hz (Uq 2 Mbit/s

Differential Protection Symposium

Clock Belo Horizonte November 2005

G. Ziegler, 10/2005 page 107

Communication through transmission networks

M U X

A User / Source

Modem Network node circuit / packet switching trunk

Modem

Station user terminal point

M U X

line Transmission path

B loop

Differential Protection Symposium

User / Destination

Belo Horizonte November 2005

G. Ziegler, 10/2005 page 108

Structure of a modern data communication network

622 Gbit/s

ØNetworks are plesiochronous (PDH), synchronous (SDH) or asynchronous (ATM) ØData terminal devices (e.g. relays) are synchronised through the network ØRings guarantee redundance. ØData of different services (e.g. telephone and protection are commonly transmitted (time multiplexed) ØProtection relays must be adapted to the given network conditions (e.g. changing propagation time due to path witching.

622 Gbit/s

POTS: Plain Old Telephone Services ISDN: Integrated Services Digital Network STM-n: Synchronous Transport Module level n SMA: Synchronous Module Access ATM: Asynchronous Transmission Mode ISP: Internet Service Provider

Differential Protection Symposium

Belo Horizonte November 2005

G. Ziegler, 10/2005 page 109

Comparison of Switching Methods Circuit Switching

Packet switching

The physically assigned channel is established before and disconnected after communication

Data stream is segmented to packets

POT (Plain old telephony), ISDN Digital networks on basis of PCM with plesiochronous digital hierarchy (PDH) Reliable and fast transmission possible when connection is established. Circuit establishment requires a free channel from A to B Connection occupies channel also when no data is exchanged Deterministic data transmission (fixed data transmission time per channel)

Differential Protection Symposium

Transmission runs connection-oriented or connection-less Synchronous digital hierarchy (SDH), ATM Backbone Cannel not occupied during whole connection time Channels can be used quasi-simultaneously Data transmission by principle time is random. SDH and ATM can provide virtual circuitswitched channels. However, split path signal routing may however result in unsymmetrical signal transmission times.

Belo Horizonte November 2005

G. Ziegler, 10/2005 page 110

SDH network: Split path routing

Node F

Node E

Node D

Standby path

Node A tP2‘ Node B Relay End 1

Differential Protection Symposium

tP1

Node C

tP1‘

tP2 Healthy path

Relay End 2

Belo Horizonte November 2005

G. Ziegler, 10/2005 page 111

Digital Transport Systems: Bundling of channels PCM 7680

PDH Hierarchy

PCM 1920

Plesiochronous (almost synchronous) PCM 480 PCM 120 PCM 30

M U X

M U X

M U X

M U X

M U X

565 Mbit/s

140 Mbit/s

32 Mbit/s

8 Mbit/s

2 Mbit/s

64 kbit/s

SDH Hierarchy Synchronous SMT-1 155 Mbit/s

SMT-4 622 Mbit/s

1

SMT-16 2.5 Gbit/s 1 2

1 2

2 3

3

3 4

Differential Protection Symposium

SMT-64 10 Gbit/s 1

4

4 Belo Horizonte November 2005

G. Ziegler, 10/2005 page 112

PDH (Plesiochronous Digital Hierarchy)

Multiplexing structure: ØBase rate 64 kbit/s (digital equivalent of analogue telephone channel) ØEquipments may generate slightly different bit rates due to independent internal clocks ØBit stuffing is used to bring individual signals up to the same rate prior to multiplexing (Dummy bits are inserted at the sending side and removed at the receiving side) ØIntermediate inserting and extracting of individual channels is not possible, but the full multiplexing range has always to be run through. Hierarchical level 0 1 2 3 4

Europe 64 kbit/s 2‘048 Mbit/s 8‘448 Mbit/s 34‘368 Mbit/s 139‘264 Mbit/s

Differential Protection Symposium

USA 56 kbit/s 1‘544 Mbit/s 6‘312 Mbit/s 44‘736 Mbit/s 139‘264 Mbit/s

Belo Horizonte November 2005

G. Ziegler, 10/2005 page 113

SDH (Synchronous Digital Hierarchy) Multiplexing structure Ø SONET (Synchronous Optical Network) first appeared in USA (1985) Ø ITU-T (formerly CCITT) issued B-ISDN as world wide standard (1988) Ø All multiplexing functions operate synchronously using clocks derived from a common source Ø Designed to carry also future ATM SDH STM level STM-1 STM-4 SZM-16 STM-64

Aggregate Rate 155,520 Mbit/s 622,080 Mbit/s 2‘488,320 Mbit/s 9‘953,280 Mbit/s

Differential Protection Symposium

SONET OC level

STS level

Aggregate Rate

OC-1 OC-3 OC-12 OC-48 OC-192

STS-1 STS-3 STS-12 STS-48 STS-192

51,840 Mbit/s 155,520 Mbit/s 622,080 Mbit/s 2‘488,320 Mbit/s 9‘953,280 Mbit/s

Belo Horizonte November 2005

G. Ziegler, 10/2005 page 114

ATM (Asynchronous Transfer Mode) and Broadband B-ISDN Features of ATM: Ø Synchronisation individually per packet

Voice Audio

Fax

Data

Video

Ø Packets carry each complete address of destination so that each can be separately delivered (Datagrams, here called Cells) Ø Information stream is segmented into cells that are 53 octets long Ø ATM sets up a virtual switched connection and sends data along a switched path from source to destination

ISDN

Ø Requirements on bandwidth, bounded delay and delay variation can be set by the user ØSingle cells can be inserted or removed at the nodes, as required Ø The predominant use is for net backbones

Differential Protection Symposium

Belo Horizonte November 2005

G. Ziegler, 10/2005 page 115

TDM over optical fiber

Hicom

FO MUX >2 Mbit/s L1-L2 21,3 KA 73,6 kW

I O

Optic fibres in the core of earth wires

x 64 kbit/s

V

Differential Protection Symposium

Belo Horizonte November 2005

G. Ziegler, 10/2005 page 116

Bit error rate (of data channels) Bit error rate:

p=

number of faulty bits total number of sent bits

Typical bit error rates of public services: Telephone circuits ca. 10 -5 Digital data networks (Germany) ca. 10 -6 to 10-7 Coaxial cables (LAN) ca. 10 -9 Fiber optic communication ca. 10 -12 Utility conditions (CIGRE SC34 Report 2001): Fiber optic communication ca. 10 -6 Data networks (PDH, SDH, ATM) ca. 10-6 Microwave ca. 10 -3 Requirements acc. to CIGRE report: Protection and control in general: < 10-6 Function guaranteed up to < 10 -3 however downgraded (reduced operating speed) Line differential protection < 10 -6 and < 10-5 during power system faults

Differential Protection Symposium

Belo Horizonte November 2005

G. Ziegler, 10/2005 page 117

Error detection methods: Cyclic redundancy check 01111110 Flag

01111110 Address

Control

I(x)

Data field

Check field

Flag

I(x) + R(x) Receiver

Sender

Division by G(x)

R(x) = CRC

error free data block

CRC 16: G(x) = X16 + X15 + X2 + 1 binary: 1 1000 0000 0000 0101 Reduction of the block failure rate by the factor > 10 -5 against the bit failure rate! (CRC 32: > 10-10)

Differential Protection Symposium

Division by G(x)

R(x) = 0

faulty data block

Belo Horizonte November 2005

G. Ziegler, 10/2005 page 118

Data integrity (line differential protection 7SD52/61)

Received data

Block failure rate P = 10-5

Error detection e.g. CRC = 32

Residual data

Block failure rate R = 10-15

Differential Protection Symposium

Belo Horizonte November 2005

G. Ziegler, 10/2005 page 119

Residual error rate

Residual error rate:

R=

number of not detected faulty telegrams (data blocks) total number of sent telegrams (data blocks)

Practical range of protection and control systems: Time between 2 not detected errors:

T=

R < 10 -10 to 10-15

n v⋅R

n= length of telegram (data block) v= transmission speed in bit/s

Example: Telegrams of n =200 bit are continuously transmitted at 64 kbit/s. R

T

10-7

20 hours

10-10

2.3 years

10-15

230000 years

typical application cyclic transmission (metering)

remote control and protection

Differential Protection Symposium

Belo Horizonte November 2005

G. Ziegler, 10/2005 page 120

Protection of a short line lines Differential relay using direct digital relay-to-relay communication

A

B

D 7SA6

D 7SA6

Communication via direct relay-relay connection Fibre type

optical wave length

maximum attenuation

permissible distance

Multi-mode 62.5/125 µm

820 nm

16 dB

ca. 3.5 km

Monomode 9/ 125 µm

1300 nm

29 dB

ca. 60 km

9/ 125 µm

1500 nm

29 dB

ca. 100 km

Differential Protection Symposium

Belo Horizonte November 2005

G. Ziegler, 10/2005 page 121

Line differential relaying using digital communication A

B

D 7SD52

D 7SD52 D 7SD52

Chain topology or redundant ring topology

typical Adaptive add-on stabilisation Settable time difference to consider given data transmission asymmetry

l Adaptive topology recognition Automatic recognition of connections and remote end devices Automatic re-routing from ring to chain topology if one data connection fails In case of multi-terminal protection, remaining relay system continues operation if one line end is switched off and the relay is logged out for maintenance

Differential Protection Symposium

Belo Horizonte November 2005

G. Ziegler, 10/2005 page 123

Individual time references by synchro-phasors Definition of a synchrosynchro-phasor: phasor: SynchroSynchro-phasors, phasors, are phasors, phasors, which are measured at different network locations by independent devices and referred to a common time basis

Time reference iB

iA

Ort : A

Ort : B IM

IA

relay A

RE

IB relay B

Differential Protection Symposium

Belo Horizonte November 2005

G. Ziegler, 10/2005 page 124

Phasor synchronisation between line ends

A

tA1 tA2

∆I

∆I

curre n phas t o rs

tAR

tA5

B

α ...

tA1

tPT1

tB2

tBR

α=

tB3

tPT2 ...

tV tB3 tA1

nt curre rs ph aso

Signal transmission time: Sampling instant:

Differential Protection Symposium

IB( tB3 )

tB1 tD

tA3 tA4

IB( tA3 )

t B3 - t A3 ⋅ 360 ° TP

tB4

t PT1 = t PT2 =

1 (t A1 - t AR - t D ) 2

t B3 = t AR - tTP2 Belo Horizonte November 2005

G. Ziegler, 10/2005 page 125

Specification of data channel for line differential protection based on Cigre Report: Protection using Telecommunication *)

Data rate

64 kbit/s (min.)

Channel delay time:

< 5 ms

Channel delay time unsymmetry:

< 0.2 ms

Bit error rate normal:

< 10 -6

during power system fault Availability:

< 10-5 *) > 99.99 %

*) Report of WG34/35.11, Brochure REF. 192, Cigre Central Office, Paris, 2001, *) It is suggested that for a BER of less than 10-6 the dependability shall not suffer a noticeable deterioration . For a BER of 10-6 to 10-3 the teleprotection may still able to perform its function although a loss in dependability is to be expected.

Differential Protection Symposium

Belo Horizonte November 2005

G. Ziegler, 10/2005 page 126

Digital Protection of Generators and Motors Gerhard Ziegler

Differential Protection Symposium

Belo Horizonte November 2005

G. Ziegler, 10/2005

Seite 116

Generator differential protection

a a c

S

S S A

IA/In 3 2

S S A

1 S A

Connection circuit

Differential Protection Symposium

1

2

3

4

5

6

IS/In

Operating characteristic

Belo Horizonte November 2005

G. Ziegler, 10/2005

Seite 117

Generator HI differential protection

a b c

A

Differential Protection Symposium

A

A

Belo Horizonte November 2005

G. Ziegler, 10/2005

Seite 118

Transverse differential protection

a

b

c

S

S S

S S

A

Differential Protection Symposium

A

S A

Belo Horizonte November 2005

G. Ziegler, 10/2005

Seite 119

HI earth current differential protection

L1 L2 L3

∆IE>

Differential Protection Symposium

Belo Horizonte November 2005

G. Ziegler, 10/2005

Seite 120

Earth current differential protection for generators

L1 L2 L3

U0>

∆IE> Tripping

Differential Protection Symposium

Belo Horizonte November 2005

G. Ziegler, 10/2005

Seite 121

Motor starting current

20

IRush /IN

TRush

15

Tst 10

Ist/IN

5 0 5

0

50

100

150

200

250

300

tst (ms)

Differential Protection Symposium

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Seite 122

Transformer Differential Protection Gerhard Ziegler

Differential Protection Symposium

Belo Horizonte November 2005

G. Ziegler, 10/2005

page 123

Transformer: Function principle and equivalent circuits I1

w1

w2

I2

U1

Xσ1

R1

Φ

U2 Φ σ1

Φ σ2

U1

I1

I ⋅ w + I ⋅ w = I µ ⋅ w1 1 1 2 2

I µ

K OB 4 ⋅ K OB − 1

10

20

t

20

1

or

k>

1 4 ⋅ K TF − K 2 TF

KOB= CT over-burdening factor KTF= 1/KOB = CT over-dimensioning factor

Differential Protection Symposium

Belo Horizonte November 2005

G. Ziegler, 10/2005

page 240

Digital busbar protection 7SS5, Measuring technique External fault, fault current with DC offset I1

I2

2 2

I1

IOp= |I1+I2| 0

20

40

1

60

0

20

0

20

40

60

40

60

40

60

2

I2 0

20

40

60

k·IRes =k·(|I1|+|I2|)

1

2

t

2

IRes=|I1|+|I2|

1

∆I=IOp - IRes

1

0

20

1 0

20

40

Differential Protection Symposium

60

2

Belo Horizonte November 2005

G. Ziegler, 10/2005

page 241

Digital busbar protection 7SS5, Measuring technique Internal fault, fault current with DC offset I1

I2 3 2 1

2

IOp= |I1+I2|

I1

0

20

40

60

40

60

1 0

I2

20

40

2

t

2

k·IRes =k·(|I1|+|I2|) 0

20

t

2 3

60

40

1 0

60

20

1 t

2 2 2

∆I=IOp - IRes

IRes=|I1|+|I2| 0

20

40

60

0.75 0.5 0

40

60

1.75 3

Differential Protection Symposium

20

Tripping!

Belo Horizonte November 2005

G. Ziegler, 10/2005

page 242

CT dimensioning for busbar protection 7SS5, Example (1)

25 ⋅ 106 I N −T = = 1440A 10 ⋅103 ⋅ 3

110kV SSC‘‘= 4 GVA 110/10 kV 25 MVA uT= 14% TT= 60 ms

G

1500/1

2MW

600/1 300/1

150/1

5MW

10 kV 10 MVA Xd‘‘= 15% TG= 100 ms

300/1

300/1

ISt= 6·IN Xd‘‘= 17% TM= 35 ms

M

M

5MW

5MW

Differential Protection Symposium

I N −G =

10 ⋅10 6 = 577A 3 10 ⋅ 10 ⋅ 3

5 ⋅10 6 ΣI N − M -HV = 2 ⋅ = 577A 3 10 ⋅ 10 ⋅ 3

IF−T =

1.1 ⋅ 1440 = 11.3 kA 0.14

IF−G =

1.1 ⋅ 577 = 4.2 kA 0.15

ΣI F − M =

Belo Horizonte November 2005

1.1 ⋅ 577 = 3.7 kA 0.17

G. Ziegler, 10/2005

page 243

CT dimensioning for busbar protection 7SS5 and 7SS6, Example (2) As worst case, the CT 150/1 A in bay 1 is considered. Total fault current with a fault at the transformer HV terminals:

ΣI F = I F − T + I F − G + ΣI F − M = 11,3 + 4,2 + 3,7 = 19,2 kA Equivalent time constant:

I ⋅ T + I F − G ⋅ TG + ΣI F − M ⋅ TM 11.3 ⋅ 60 + 4.2 ⋅ 100 + 3.7 ⋅ 35 TEquiv. = F − T T = = 64 ms I F − T + I F − G + ΣI F − M 11.3 + 4.2 + 3.7 We consider a CT type 5P?, 30 VA, internal burden Pi= 15% (4.5 VA): Connected burden Pa= 1 VA CT over-dimensioning factor for 3ms saturation free time: KTF ca. 0.45 Corresponding to an overburdening factor of kOB= 1/KTF = 2.2 Checking of the k-setting (Stability with symmetrical fault currents):

ALF ' =

ΣI F I N − CT

⋅ K TF =

19 .200 ⋅ 0 . 45 = 58 150

k>

k OB 4 ⋅ kOB − 1

ALF =

=

2,2 = 0 .5 (chosen: k=0.6) 4 ⋅ (2 .2 − 1)

Pa + Pi 1 + 4.5 ⋅ ALF ' = ⋅ 58 = 9.3 PN + Pi 30 + 4.5

We finally choose: CT 5P10, 150/1, 30 VA, R2≤ 4.5 Ohm

Differential Protection Symposium

Belo Horizonte November 2005

G. Ziegler, 10/2005

page 244

Transient performance of iron closed CT cores (type TPX) Over-dimensioning factor KTF for short time to saturation

1.5

1.5

KTF

1.4

TM

1.3

KTF

1.4 1.2

1.2

5 ms

1.1

1.1

1

1

0.9

0.9

0.8

4 ms

0.7 0.5

0.5

3 ms

0.3

0.2

0.2

0.1

0.1 10 20 30 40 50 60 70 80 90 100

3 ms

0.4

0.3

0

4 ms

0.7 0.6

0.4

5 ms

0.8

0.6

0

TM

1.3

0

0

1

2

3

4

6

7

8

9

10

TN

TN

Differential Protection Symposium

5

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G. Ziegler, 10/2005

page 245

High impedance busbar protection

RCT

RCT

RCT

RCT

RCT: Resistance of CT secondary winding

RL

RL

RL

RL

RL: Connection cable resistance RRV: Relay series resistance RRS: Relay shunt resistance

RRS

Varistor IV

IS

RRV ∆I

Differential Protection Symposium

IR

Belo Horizonte November 2005

G. Ziegler, 10/2005

page 246

HI busbar protection, calculation example RL= 3 Ohm (max.) IR=20 mA (fixed value) RRV = 10 kOhm RRS = 250 Ohm Iv = 50 mA (at relay pick-up voltage)

Given: :n = 8 feeders rCT = 600/1 A UKN = 500 V RCT = 4 Ohm ImR = 30 mA (at relay pick-up voltage)

Primary pick-up current: I F − min = rCT ⋅ (I R + IS + I V + n ⋅ I mR I F − min =

Stability with external faults:

)

I F − through − max < rCT ⋅

600 ⋅ (0.02 + 0.89 + 0.05 + 8 ⋅ 0.03 ) 1

I F − min = 666A ⋅ (111%I N − CT )

Differential Protection Symposium

I F − through − max
, t

50N/51N

Ground overcurrent (IE, t)

50G/51G

Hand reset trip

86

Unbalanced current I2>, t

46

Trip circuit supervision

74TC

Thermal overload IEC 60255-8

49

Therm. OL IEC 60354 (hot spot)

49

Differential Protection Symposium

ANSI No.

Binary inputs for tripping commands

Belo Horizonte November 2005

G. Ziegler, 5/2005

page 251

7UT6: Application

(1) ∆

∆I ∆I Shunt Reactor

G

Three winding transformer

Two winding transformer

∆I

Generator / Motor

Differential Protection Symposium

∆I

∆I

Transformer bank (1-1/2-LS)

∆I

∆I

Busbars

Belo Horizonte November 2005

G. Ziegler, 5/2005

page 252

7UT6: Application Generation Unit protection (overall differential)

Y ∆

(2)

HI restricted earth fault protection

7UT6xx 7UT635

G 3~

Differential Protection Symposium

Belo Horizonte November 2005

G. Ziegler, 5/2005

page 253

7UT6: selectable: I0-correction or restricted earth fault protection YN

yn0

d5

R S T

49 (1)

49 (2)

50 51

∆ITE

∆IT 7UT613

Differential Protection Symposium

Belo Horizonte November 2005

G. Ziegler, 5/2005

page 254

7UT6: operating characteristic

Idiff >>

7 Locus of internal faults

6

I Op In

45° 5

S

operate

e2 p lo restrain

4

*)

3 2

Idiff >

1

e1 p o l S

0 0

2

supplementary restraint

4

6

8

10

12

14

16

IRes

*) Slope of add on characteristic:

In

7UT6 à as slope 1 (7UT5 à ½ of slope 1)

Differential Protection Symposium

Belo Horizonte November 2005

G. Ziegler, 5/2005

page 255

7UT6: Effect of supplementary restraint in case of CT saturation

Restrain 45°

Trip

Area of add-on restraint

Differential Protection Symposium

Belo Horizonte November 2005

G. Ziegler, 5/2005

page 256

Differential protection functions IDiff> and IDiff>> Sampled momentary values

Measuring value processing i1L

iRes = |i1|+ |i2|

Side 1

i2L

iOp = i1 + i2

Side 2

Average value IStab = iRest Fundamental wave: IDiff = Eff(iDiff)50Hz

Operating characteristic, Saturation detector IDiff IDiff>

IStab

&

Trip IDiff>

≥1

Trip IDiff>>

Motor start, DCcomonent Harmonic Analysis: -2nd Harmon. Blocking -Cross Blocking

iRes IRes

IDiff

IDiff IDiff>>

I / InO

I / InO

iDiff

ms

iDiff 2·IDiff>> ms

Fast tripping using sampled momentary values ensures dependable operation in case of extreme CT saturation!

Differential Protection Symposium

Belo Horizonte November 2005

G. Ziegler, 5/2005

page 257

7SA6: Temperature monitoring

RS485 Interface

7XV5662-(x)AD10

7XV5662-(x)AD10

Two thermo-devices can be connected to the serial service interface (RS485) Monitoring of up to 12 measuring points (6 per thermo-device) - each with two pick-up levels Display of the measured temperatures - directly at the thermo-device (which can also be used stand alone) - at the relay One input is reserved for hot spot monitoring (measurement of oil temperature) Thermistors: Pt100, Ni100 or Ni120

Differential Protection Symposium

Belo Horizonte November 2005

G. Ziegler, 5/2005

page 258

7UT6: Temperature monitoring with hot spot calculation (1) Example: Natural cooling Θ h = Θ O + H gr ⋅ k Y

Θh= hot spot temperature Θh= oil temperature Hgr=hot-spot-to-oil temperature gradient k= load factor I/In Y= winding exponent

Aging rate: Oil Temp.

HV LV

Aging at Θh V= = 2(Θ h −98)/6 Aging at 98°C

98O is reference for the aging of Cellulose insulation

Mean value of aging during a fixed time interval: T

2 1 L= ⋅ ∫ V ⋅ dt T2 − T1 T1

Differential Protection Symposium

Belo Horizonte November 2005

G. Ziegler, 5/2005

page 259

7UT6: Temperature monitoring with hot spot calculation (1) Example: Natural cooling

Θ h = Θ o + H gr ⋅ k Y ≈ 73 + 23 ⋅1.151.6 = 102°C

(L)

V = 2(Θ h −98)/6 = 2(102−98)/6 ≈ 1.6 108°C

k, V, L

98°C 102°C 73°C

Θh Hot spot temp. Θo oil temp. (from thermodevice)

[°C]

Θh Θo

1.6

k (I/In)

V (relative aging) L (mean value of V)

1.15

t

Differential Protection Symposium

Belo Horizonte November 2005

G. Ziegler, 5/2005

page 260

7UT6: Commissioning und service tool

(1)

WEB-Technology Access to WEB Browser Help system in the INTRANET / INTERNET http://www.siprotec.com

Relay homepage address of : http://141.141.255.160 IP-address can be set with program DIGSI 4 at the front or service interface of the relay

1. Serial connection Directy or with modem to standard DIAL-UP network 2. HTM L page view at IP-address of the relay http://141.141.255.160

Differential Protection Symposium

WEB server in relay firmware Server sends HTML pages and JAVA code to WEB Browser via DIAL-UP connection

Belo Horizonte November 2005

G. Ziegler, 5/2005

page 261

7UT6: Commissioning and service tool

(2)

Current phasors of all terminals can be displayed

Transformer YNd11d11, 110/11/11kV, 38.1MVA, IL2S2à wrong polarity

Differential Protection Symposium

Belo Horizonte November 2005

G. Ziegler, 5/2005

page 262

7UT6: Commissioning and service tool (3) Operating/restraint position can be displayed

Transformer YNd11d11, 110/11/11kV, 38.1MVA, IL2S2à wrong Polarität

Differential Protection Symposium

Belo Horizonte November 2005

G. Ziegler, 5/2005

page 263

Power Transmission and Distribution

Differential Protection (7UT)

Determination of the Transformer Vector Group

Transformer with Vector Group Yy0

7UT612

80 MVA Yy0 2500A/1A

20 kV

110 kV 500A/1A

PTD PA13 N. M Tests 7UT 05/03 No. 2

Method of Vector Group Determination (ExampleYy0) IL1,S2

Side 2:

Side 1:

2L1 1L1

IL1,S1

2L2

1L2 2L3 1L3

IL1,S2 = IL1

UL1,S1

UL1,S2

IL1,S1

UL3,S2

UL2,S2

UL3,S1

UL2,S1

0° Vector group is

Yy0 PTD PA13 N. M Tests 7UT 05/03 No. 3

Transformer Protection

7UT612

80 MVA Yd11 2500A/1A

20 kV

110 kV 500A/1A

PTD PA13 N. M Tests 7UT 05/03 No. 4

Method of Vector Group Determination (ExampleYd11) IL1,S2

Side 2:

Side 1:

2L1

IL1,S1

2L2

1L1 1L2

2L3 1L3

IL1,S2 = IL1 - IL2

IL1,S1

UL1,S1

UL1,S2

UL2,S2 UL3,S1

UL2,S1

UL3,S2

Vector group is Y d 11

330° (n * 30°)

PTD PA13 N. M Tests 7UT 05/03 No. 5

Definitions in SIPROTEC 4 Relays

Vector definition to a node is positive The shown vectors or phase angles are transformed in this positive definition The phase angle is displayed mathematics positive. The reference phase is always phase L1 on side 1 How to see the vector group Yd11? Original

Siprotec 4 (Browser)

Phase angles Side 1: 0° (reference phase) Side 2: 210° Please subtract 180°, than you get 30° (360° - 30° = 330°) PTD PA13 N. M Tests 7UT 05/03 No. 6

Web Tool (Browser) Vector group YNd11

PTD PA13 N. M Tests 7UT 05/03 No. 7

Vector Group Determination via Fault Record IL1;Side 2 lags 150° or leads 210°

Star point is towards the protected object

IL1;Side 1

Way 1: IL1 Side: 150° + 180° = 330°

Way 2: IL1 Side: 210° - 180° = 30° leads 30° or lags 330°

Phase shift is according the vector group definition 330° → 11 * 30° PTD PA13 N. M Tests 7UT 05/03 No. 8

Digital Transformer Differential Protection

I0-correction + vector group adaptation

Differential Protection Symposium

Belo Horizonte November 2005

G. Ziegler, 10/2005

page 1

Transformer differential protection with I0-correction External fault L3

L1 L2 L2

L3

L1

Yd5

3

3

3

L1 L2 L3

1 3

1:3

Vector group adaptation

3

1

I0-correction

Differential Protection Symposium

1

2

3

2







3

Belo Horizonte November 2005

G. Ziegler, 10/2005

page 2

Transformer differential protection with I0-correction Internal fault L3

L1 L2 L2

L3

L1

Yd5

3

3

3

L1 L2 L3

1 3

1:3

1

I0-correction

Differential Protection Symposium

Vector group adaptation

1

1

3

2







3

Belo Horizonte November 2005

G. Ziegler, 10/2005

page 3

Power Transmission and Distribution

Differential Protection (7UT)

Determination of the Transformer Vector Group

Transformer with Vector Group Yy0

7UT612

80 MVA Yy0 2500A/1A

20 kV

110 kV 500A/1A

PTD PA13 N. M Tests 7UT 05/03 No. 2

Method of Vector Group Determination (ExampleYy0) IL1,S2

Side 2:

Side 1:

2L1 1L1

IL1,S1

2L2

1L2 2L3 1L3

IL1,S2 = IL1

UL1,S1

UL1,S2

IL1,S1

UL3,S2

UL2,S2

UL3,S1

UL2,S1

0° Vector group is

Yy0 PTD PA13 N. M Tests 7UT 05/03 No. 3

Transformer Protection

7UT612

80 MVA Yd11 2500A/1A

20 kV

110 kV 500A/1A

PTD PA13 N. M Tests 7UT 05/03 No. 4

Method of Vector Group Determination (ExampleYd11) IL1,S2

Side 2:

Side 1:

2L1

IL1,S1

2L2

1L1 1L2

2L3 1L3

IL1,S2 = IL1 - IL2

IL1,S1

UL1,S1

UL1,S2

UL2,S2 UL3,S1

UL2,S1

UL3,S2

Vector group is Y d 11

330° (n * 30°)

PTD PA13 N. M Tests 7UT 05/03 No. 5

Definitions in SIPROTEC 4 Relays

Vector definition to a node is positive The shown vectors or phase angles are transformed in this positive definition The phase angle is displayed mathematics positive. The reference phase is always phase L1 on side 1 How to see the vector group Yd11? Original

Siprotec 4 (Browser)

Phase angles Side 1: 0° (reference phase) Side 2: 210° Please subtract 180°, than you get 30° (360° - 30° = 330°) PTD PA13 N. M Tests 7UT 05/03 No. 6

Web Tool (Browser) Vector group YNd11

PTD PA13 N. M Tests 7UT 05/03 No. 7

Vector Group Determination via Fault Record IL1;Side 2 lags 150° or leads 210°

Star point is towards the protected object

IL1;Side 1

Way 1: IL1 Side: 150° + 180° = 330°

Way 2: IL1 Side: 210° - 180° = 30° leads 30° or lags 330°

Phase shift is according the vector group definition 330° → 11 * 30° PTD PA13 N. M Tests 7UT 05/03 No. 8

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