Chapter Fourteen: ACIDS AND BASES
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Contents
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14-1 The Nature of Acids and Bases
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Arrheniuis postulates that acids produce hydrogen ios in aqueous solution, while bases produce hydroxide ions. Danish chemist Johannes Bronsted and the English chemist Thomas Lowry In terms of the Bronsted-Lowry model, an acids is a proton (H+) donor, and a base is a proton acceptor. Arrhenius: Acids produce H+ in solution, bases produce OHion. Brønsted-Lowry:Acids are H+ donors, bases are proton acceptors. HCl + H2O Cl+ H3O+ HCl + H2O Cl+ H3O+ acid base
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Models of Acids and Bases
Arrhenius: Acids produce H+ in solution, bases produce OH-ion.
Brønsted-Lowry: Acids are H+ donors, bases are proton acceptors. HCl + H2O → Cl-+ H3O+ acid base
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Conjugate acid-base pair
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The equilibrium expression for Ka HA(aq) + H2O
H3O+(aq) + A-(aq)
acid
onjugate cid
base
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conjugate base
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Brønsted-Lowry Reaction
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Ex 14.1 Acid Dissociation (lonization) Reactions
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Write the simple dissociation (ionization) reaction (omitting water) for each of the following acids.
a. Hydrochloric acid (HCl)
b. Acetic acid (HC2H3O2)
c. The ammonium ion (NH4+)
d. The anilinium ion (C6H5NH3+)
e. The hydrated aluminum(III) ion [Al(H2O)6]3+
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The Bronsted- Lowry model is not limited to aqeous solutions
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In this reaction is donated by the hydrogen chloride to the ammonia, as shown these Lewis structure.
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14-2 Acid Strength
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The strength of an acid is defined by the equilibrium position of its dissociation (ionization) reaction. Before dissociation
After dissociation at equilibrium
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Figure 14.5
The relationship of acid strength and conjugate base strength for the ionization reaction.
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A strong acid is virtually 100 %
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dissociated in water.
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Acid Strength
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Figure 14.6
(a) A strong acid HA is completely ionized in water. (b) A weak acid HB exists mostly as undissociated HB molecules in water. Note that the water molecules are not sown in this figure.
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Acid Ionization Equilibrium
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Self-Ionization of Water
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ct a e R
HA(aq) + H2O acid base
H3O+(aq) + A-(aq) conjugate conjugate acid base
What is the equilibrium constant expression for an acid acting in water? 19
Think!
How good is Cl-(aq) as a base?
Is A-(aq) a good base?
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Think!
H2O(aq) + H2O acid base
H3O+(aq) + OH-(aq) conjugate conjugate acid base
At 25 C, Kw = 1.0 x 10-14
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Values of Ka
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Appendix 5.1 contains a table of Ka values. Organic acids: carboxyl group
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Ex 14.2 Relative Base Strength Using Table 14.2, arrange the following species according to their strengths as bases: H2O, F-, Cl-, NO2-, and CN-. Solution
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Water as an Acid and a Base
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Kw
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There are three possible situations:
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Ex 14.3 Calculating [H+] and [OH-]
Calculate [H+] or [OH-] as required for each of the following solutions at 25℃, and state whether the solution is neutral, acid, or basic.
a. 1.0 × 10 -5 M OH-
b. 1.0 × 10-7 M OH-
c. 10.0 M H+ 28
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Ex 14.4 Autoionization of Water
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At 60 ℃, the value of Kw is 1 × 10-13. a. Using Le Chatelier’ s principle, predict whether the reaction is exothermic or endothermic. 2 H 2O(l ) H 3O (aq) OH (aq)
b. Calculate [H+] and [OH-] in a neutral solution at 60 ℃. 30
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14.3 The pH Scale
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The pH Scale
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Ex 14.5 Calculating pH and pOH Calculate pH and pOH for each of the following solutions at 25 ℃ a. 1.0 × 10 -3 M OHb. 1.0 M OH-
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(a)
(b)
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The pH scale and pH values of some common substances
Figure 14.8
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Ex 14.6 Calculating pH The pH of a sample of human blood was measured to be 7.41 at 25℃. Calculate pOH, [H+], and [OH-] for the sample.
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14-4 Calculating the pH of Strong Acid Solutions
Ex 14.7 pH of Strong Acids M HCl. a. Calculate the pH of 0.10 M HNO3. b. Calculate the pH of 1.0 × 10 Solution: (a) (b)
-10
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14-5 Calculating the pH of Weak Acid Solutions
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Ex 14.17 Calculating Ka from Percent Dissociation p643
Lactic acid is a waste product that accumulates in muscle tissue during exertion, leading to pain and a feeling of fatigue. In a 0.100 M aqueous solution, lactic acid is 3.7% dissociated . Calculate the value of Ka for this acid. Solution:
14.6 Bases
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Ex 14.12 The pH of Strong Bases
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Calculate the pH of a 5.0 x 102- M NaOH. Solution:
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The lone pair is located on a nitrogen atom
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Kb
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Ex 14.13 The pH of Weak Bases I
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Calculates the pH for a 15.0 M NH3(Kb = 1.8 x 10-5). Solution:
14.7 Polyprotic Acids
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Polyprotic acids
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Ex14.15 The pH of a Polyprotic Acid
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Calculate the pH of a 5.0 M H3PO4 solution and the equilibrium concentrations of the species H3PO4, H2PO4-, HPO42-, and PO43-. Solution: a.
e. b.
c.
f. d.
Acid-Base Properties of Salts
Cation neutral neutral
conjugate acid of weak base conjugate acid of weak base
Anion neutral conjugate base of weak acid neutral
conjugate base of weak acid
Acidic or Basic neutral basic
Example NaCl NaF
acidic
NH4Cl
depends on Ka & K b values
Al2(SO4)3 50
14-8 Acid-Base Properties of Salts Salts That Produce Neutral Solutions KCl, NaCl, NaNO3, and KNO3 are neutral.
Salts That produce Basic Solutions The pH of the solution will be determined by the conjugate anions of weak acids, such as CN-, acetate ion C2H3O2-.
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Ex 14.18 Salts as Weak Bases Calculating the pH of a 0.30 M NaF solution. The Ka value for HF is 7.2 x 10-4. Solution:
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Base Strength in Aqueous Solutions Relative base strength: OH- > CN- > H2O Salts That Produce Acidic Solutions Table 14.5 Qualitative Prediction of pH of Salt Solutions of Salts for Which Both Cation and Anion Have Acidic or basic properties
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Various Types of Salts
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14-9 The Effect of Structure on Acid-Base Properties Table 14.7 Bond Strengths and Acid Strengths for Hydrogen Halides
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The structure effect
Two factors for acidity in binary compounds:
Bond Polarity (high is good)
Bond Strength (low is good)
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The Effect of Structure on Acid-Base Properties The effect of number of attracted oxygens on the O-H bond in a series of chlorine oxyacids.
Figure 14.11
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14-10 Acid-Base Properties of Oxides
Oxides
Acidic Oxides (Acid Anhydrides): • O X
bond is strong and covalent.
SO2, NO2, CrO3 Basic Oxides (Basic Anhydrides): • O X
bond is ionic.
K2O, CaO 59
14-11 The Lewis Acid-Base Model
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Three Models for Acids and Bases
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Lewis model
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Lewis acid-Lewis base reaction Hydration of a metal ion. 3+
Al3+ + 6 O
H
H Al H
O H
Figure 14.12 Reaction of BF3 with NH3
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Al3+
ion accepts one electron pair from each of six water molecules to form Al(H2O)63+.
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14-12 Strategy for Solving Acid-Base p666 Problems: A Summary